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Exam (elaborations)

Physics Exam- Chapter 2 Section Worksheets With Complete Solutions

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PHYSICS EXAM- CHAPTER 2 SECTION WORKSHEETS WITH COMPLETE SOLUTIONS

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PHYSICS EXAM- CHAPTER 2 SECTION
WORKSHEETS WITH COMPLETE SOLUTIONS
(graphing question)
during which interval is the magnitude of the jogger's acceleration the greatest?
a: AB
b: BC
c: DE
d: EF - ANSWER-d

(graphing question)
during which of the following intervals does the jogger have a constant positive velocity?
a: BC
b: CD
c: DE
d: FG - ANSWER-a

(graphing question)
during which of the followingnintervals is the speed of the jogger decreasing?
a: AB only
b: AB and CD
c: AB, CD, and EF
d: EF only - ANSWER-b

(graphing question)
for the first five time intervals shown, during how many intervals does the dog pace at
the same average speed?
a:0
b: 1
c: 2
d: 3 - ANSWER-d

(graphing question)
rank the four displacements for the first time intervals CD, DE, EF, and FG in
decreasing order. explain your answer. - ANSWER-this displacement of the jogger with
a constant acceleration is equal to the average velocity during a time interval multiplied
by the time interval. because the time intervals are equal, the displacements are in the
same order as decreasing average velocities. by inspection the average velocity
decreases in the order CD, DE, EF, and FG

(graphing question)
the graph below shows the motion of four objects. which of the following lines represent
an object in free fall? assume positive velocity is upward.
a: I only
b: II only

, c: I and III
d: I and IV - ANSWER-c

(graphing question)
the jogger is at rest during which interval?
a: AB
b: BC
c: DE
d: EF - ANSWER-c

(graphing question)
what is the dog's average velocity for total displacement? - ANSWER-di = 3.0
df = 4.0
tf = 10.0
(4-3)/(10-0) = Vavg
Vavg = 1/10 m/s to the south

(graphing questions)
for the first time intervals shown, during how many intervals does the dog have the
same average velocity?
a: 0
b: 1
c: 2
d: 3 - ANSWER-c

A cat walking at 0.25 m/s sees a mouse and accelerates uniformly at 0.40 m/s(squared)
for 3.0 s. What is the cat's displacement during this time? - ANSWER-Vi = .25 m/s
a = .4 m/s (squared)
(delta)t = 3.0 s
(delta)x = Vi(delta)t + (1/2)a((delta)t)(squared)
(delta)x = .25(3) + ((.4*3)/2)
(delta)x = 2.6 m

a climber throws a rope with a velocity of 3.0 m/s downward to another climber 4.0 m
directly below. what ks the rope's velocity when it reached tje lower climber? assume no
air resistance and that a = -g = -9.81 m/s (squared) - ANSWER-Vi = 3.0 m/s
x = 4.0 m
a = -9.81 m/s(squared)
Vf(squared) = 3.0(squared) + 2(-4.0)(-9.81)
Vf = 9.35 m/s

a dog walks from +4 m to +2 m. which of the following statements is true about the
dog's motion?
a: Xi = +2
b: Xf = +2 m
c: displacement = +2

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