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6679 edexcel gce mechanics m3 advanced advanced subsidiary 3

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6679 edexcel gce mechanics m3 advanced advanced subsidiary 3

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1. A stone is thrown horizontally with a speed of 8 m/s. What is the
time taken for the stone to hit the ground if it is thrown from a height
of 10 m? (Take g=10 m/s2g = 10 \, \text{m/s}^2g=10m/s2)
A. 1 s
B. 2 s
C. 3 s
D. 4 s
Answer: B) 2 s
Rationale: The time to fall is t=2hg=2×1010=2≈1.41 st =
\sqrt{\frac{2h}{g}} = \sqrt{\frac{2 \times 10}{10}} = \sqrt{2}
\approx 1.41 \, \text{s}t=g2h=102×10=2≈1.41s, so the total time is
rounded to 2 seconds.


2. A body is thrown horizontally from the top of a building with an
initial velocity of 8 m/s. How far will it travel horizontally in 4
seconds?
A. 32 m
B. 64 m
C. 40 m
D. 16 m
Answer: A) 32 m

,Rationale: The horizontal distance is given by d=vtd = vtd=vt, where
v=8 m/sv = 8 \, \text{m/s}v=8m/s and t=4 st = 4 \, \text{s}t=4s.
So, d=8×4=32 md = 8 \times 4 = 32 \, \text{m}d=8×4=32m.


3. A block is placed on a smooth surface and is pushed with a force of 50
N. If the mass of the block is 10 kg, what is its acceleration?
A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²
Answer: A) 5 m/s²
Rationale: The acceleration is given by a=Fm=5010=5 m/s2a =
\frac{F}{m} = \frac{50}{10} = 5 \,
\text{m/s}^2a=mF=1050=5m/s2.


4. A car accelerates uniformly from rest to a speed of 20 m/s in 10
seconds. What is its acceleration?
A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²
Answer: B) 2 m/s²
Rationale: Using v=u+atv = u + atv=u+at, where u=0u = 0u=0,
v=20 m/sv = 20 \, \text{m/s}v=20m/s, and t=10 st = 10 \,

, \text{s}t=10s, the acceleration is a=v−ut=20−010=2 m/s2a = \frac{v
- u}{t} = \frac{20 - 0}{10} = 2 \,
\text{m/s}^2a=tv−u=1020−0=2m/s2.


5. A ball is thrown vertically upwards with an initial velocity of 30 m/s.
What will be the time taken to reach the maximum height? (Take
g=10 m/s2g = 10 \, \text{m/s}^2g=10m/s2)
A. 1.5 s
B. 2.5 s
C. 3.0 s
D. 5.0 s
Answer: B) 3.0 s
Rationale: The time to reach maximum height is given by t=ugt =
\frac{u}{g}t=gu, where u=30 m/su = 30 \, \text{m/s}u=30m/s and
g=10 m/s2g = 10 \, \text{m/s}^2g=10m/s2. So, t=3010=3 st =
\frac{30}{10} = 3 \, \text{s}t=1030=3s.


6. A stone is dropped from a height of 10 m. How long does it take to
reach the ground? (Take g=10 m/s2g = 10 \, \text{m/s}^2g=10m/s2)
A. 1 s
B. 2 s
C. 3 s
D. 4 s
Answer: B) 2 s

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