1. A particle of mass 2 kg is subjected to a force of 10 N. If the particle
starts from rest, what is its velocity after 5 seconds?
A. 2 m/s
B. 5 m/s
C. 10 m/s
D. 20 m/s
Answer: B) 5 m/s
Rationale: Using Newton's second law F=maF = maF=ma, the
acceleration is a=Fm=102=5 m/s2a = \frac{F}{m} = \frac{10}{2} =
5 \, \text{m/s}^2a=mF=210=5m/s2. The velocity after 5 seconds is
v=at=5×5=25 m/sv = at = 5 \times 5 = 25 \,
\text{m/s}v=at=5×5=25m/s.
2. A mass of 4 kg is suspended by a light string. What is the tension in
the string? (Take g=10 m/s2g = 10 \, \text{m/s}^2g=10m/s2)
A. 40 N
B. 30 N
C. 20 N
D. 10 N
Answer: A) 40 N
Rationale: The tension in the string is equal to the weight of the mass,
T=mgT = mgT=mg, where m=4 kgm = 4 \, \text{kg}m=4kg and
,g=10 m/s2g = 10 \, \text{m/s}^2g=10m/s2. Thus, T=4×10=40 NT
= 4 \times 10 = 40 \, \text{N}T=4×10=40N.
3. A car accelerates from rest at 2 m/s22 \, \text{m/s}^22m/s2 for 5
seconds. What is its final velocity?
A. 10 m/s
B. 5 m/s
C. 8 m/s
D. 15 m/s
Answer: A) 10 m/s
Rationale: Using the formula v=u+atv = u + atv=u+at, where
u=0 m/su = 0 \, \text{m/s}u=0m/s, a=2 m/s2a = 2 \,
\text{m/s}^2a=2m/s2, and t=5 st = 5 \, \text{s}t=5s, we get
v=0+2×5=10 m/sv = 0 + 2 \times 5 = 10 \,
\text{m/s}v=0+2×5=10m/s.
4. A body moves with a constant velocity of 5 m/s for 10 seconds. How
far does it travel?
A. 30 m
B. 40 m
C. 50 m
D. 60 m
Answer: C) 50 m
, Rationale: The distance traveled is given by d=vtd = vtd=vt, where
v=5 m/sv = 5 \, \text{m/s}v=5m/s and t=10 st = 10 \,
\text{s}t=10s. So, d=5×10=50 md = 5 \times 10 = 50 \,
\text{m}d=5×10=50m.
5. A body is moving in a circular path of radius 2 m with a constant
speed of 4 m/s. What is its centripetal acceleration?
A. 4 m/s²
B. 8 m/s²
C. 16 m/s²
D. 2 m/s²
Answer: B) 8 m/s²
Rationale: The centripetal acceleration is given by a=v2ra =
\frac{v^2}{r}a=rv2, where v=4 m/sv = 4 \, \text{m/s}v=4m/s and
r=2 mr = 2 \, \text{m}r=2m. So, a=422=162=8 m/s2a =
\frac{4^2}{2} = \frac{16}{2} = 8 \,
\text{m/s}^2a=242=216=8m/s2.
6. A pendulum of length 2 m swings with a period of 4 seconds. What
is the acceleration due to gravity at the location?
A. 9.8 m/s²
B. 10.5 m/s²
C. 11.0 m/s²
D. 12.0 m/s²
Answer: A) 9.8 m/s²
starts from rest, what is its velocity after 5 seconds?
A. 2 m/s
B. 5 m/s
C. 10 m/s
D. 20 m/s
Answer: B) 5 m/s
Rationale: Using Newton's second law F=maF = maF=ma, the
acceleration is a=Fm=102=5 m/s2a = \frac{F}{m} = \frac{10}{2} =
5 \, \text{m/s}^2a=mF=210=5m/s2. The velocity after 5 seconds is
v=at=5×5=25 m/sv = at = 5 \times 5 = 25 \,
\text{m/s}v=at=5×5=25m/s.
2. A mass of 4 kg is suspended by a light string. What is the tension in
the string? (Take g=10 m/s2g = 10 \, \text{m/s}^2g=10m/s2)
A. 40 N
B. 30 N
C. 20 N
D. 10 N
Answer: A) 40 N
Rationale: The tension in the string is equal to the weight of the mass,
T=mgT = mgT=mg, where m=4 kgm = 4 \, \text{kg}m=4kg and
,g=10 m/s2g = 10 \, \text{m/s}^2g=10m/s2. Thus, T=4×10=40 NT
= 4 \times 10 = 40 \, \text{N}T=4×10=40N.
3. A car accelerates from rest at 2 m/s22 \, \text{m/s}^22m/s2 for 5
seconds. What is its final velocity?
A. 10 m/s
B. 5 m/s
C. 8 m/s
D. 15 m/s
Answer: A) 10 m/s
Rationale: Using the formula v=u+atv = u + atv=u+at, where
u=0 m/su = 0 \, \text{m/s}u=0m/s, a=2 m/s2a = 2 \,
\text{m/s}^2a=2m/s2, and t=5 st = 5 \, \text{s}t=5s, we get
v=0+2×5=10 m/sv = 0 + 2 \times 5 = 10 \,
\text{m/s}v=0+2×5=10m/s.
4. A body moves with a constant velocity of 5 m/s for 10 seconds. How
far does it travel?
A. 30 m
B. 40 m
C. 50 m
D. 60 m
Answer: C) 50 m
, Rationale: The distance traveled is given by d=vtd = vtd=vt, where
v=5 m/sv = 5 \, \text{m/s}v=5m/s and t=10 st = 10 \,
\text{s}t=10s. So, d=5×10=50 md = 5 \times 10 = 50 \,
\text{m}d=5×10=50m.
5. A body is moving in a circular path of radius 2 m with a constant
speed of 4 m/s. What is its centripetal acceleration?
A. 4 m/s²
B. 8 m/s²
C. 16 m/s²
D. 2 m/s²
Answer: B) 8 m/s²
Rationale: The centripetal acceleration is given by a=v2ra =
\frac{v^2}{r}a=rv2, where v=4 m/sv = 4 \, \text{m/s}v=4m/s and
r=2 mr = 2 \, \text{m}r=2m. So, a=422=162=8 m/s2a =
\frac{4^2}{2} = \frac{16}{2} = 8 \,
\text{m/s}^2a=242=216=8m/s2.
6. A pendulum of length 2 m swings with a period of 4 seconds. What
is the acceleration due to gravity at the location?
A. 9.8 m/s²
B. 10.5 m/s²
C. 11.0 m/s²
D. 12.0 m/s²
Answer: A) 9.8 m/s²
