1. A ball is thrown vertically upwards with an initial velocity of 12 m/s. How high does the ball
go before it starts coming down?
A. 6 m
B. 8 m
C. 10 m
D. 12 m
Answer: B) 8 m
Rationale: At maximum height, the velocity becomes 0. Using v2=u2−2ghv^2 = u^2 -
2ghv2=u2−2gh,
0=122−2×9.8×h0 = 12^2 - 2 \times 9.8 \times h0=122−2×9.8×h,
h=1222×9.8=8h = \frac{12^2}{2 \times 9.8} = 8h=2×9.8122=8 m.
2. A particle moves in a circle with radius 5 m. If the particle has a speed of 10 m/s, what is its
centripetal acceleration?
A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²
Answer: C) 10 m/s²
Rationale: Centripetal acceleration is given by ac=v2ra_c = \frac{v^2}{r}ac=rv2,
ac=1025=20a_c = \frac{10^2}{5} = 20ac=5102=20 m/s².
3. A particle of mass 4 kg is moving with a velocity of 3 m/s. What is its momentum?
A. 10 kg·m/s
B. 12 kg·m/s
C. 14 kg·m/s
,D. 16 kg·m/s
Answer: B) 12 kg·m/s
Rationale: p=mv=4×3=12p = mv = 4 \times 3 = 12p=mv=4×3=12 kg·m/s.
4. A car is moving at a constant speed of 20 m/s. What is the car’s kinetic energy?
A. 80,000 J
B. 100,000 J
C. 120,000 J
D. 160,000 J
Answer: B) 100,000 J
Rationale: KE=12mv2KE = \frac{1}{2} mv^2KE=21mv2,
KE=12×1000×202=100,000KE = \frac{1}{2} \times 1000 \times 20^2 =
100,000KE=21×1000×202=100,000 J.
5. A block is at rest on a rough horizontal surface. If the coefficient of static friction is 0.4, what
is the force required to just move the block?
A. 4 N
B. 8 N
C. 10 N
D. 12 N
Answer: B) 8 N
Rationale: The force required to overcome friction is F=μs×N=0.4×10=8F = \mu_s \times N =
0.4 \times 10 = 8F=μs×N=0.4×10=8 N.
6. A force of 20 N is applied to a 4 kg object. What is the acceleration?
A. 2 m/s²
B. 4 m/s²
C. 5 m/s²
, D. 8 m/s²
Answer: B) 5 m/s²
Rationale: Using F=maF = maF=ma,
a=Fm=204=5a = \frac{F}{m} = \frac{20}{4} = 5a=mF=420=5 m/s².
7. A particle is moving with a uniform velocity of 2 m/s for 10 seconds. What distance does the
particle cover?
A. 5 m
B. 15 m
C. 20 m
D. 25 m
Answer: C) 20 m
Rationale: Distance = velocity × time,
2×10=202 \times 10 = 202×10=20 m.
8. A body is projected horizontally with a speed of 8 m/s from a height of 20 m. How long will it
take to reach the ground?
A. 2 s
B. 3 s
C. 4 s
D. 5 s
Answer: C) 4 s
Rationale: Using s=12gt2s = \frac{1}{2} g t^2s=21gt2,
20=12×9.8×t220 = \frac{1}{2} \times 9.8 \times t^220=21×9.8×t2,
t2=409.8≈4.08t^2 = \frac{40}{9.8} \approx 4.08t2=9.840≈4.08, so t=4.08≈4t = \sqrt{4.08}
\approx 4t=4.08≈4 s.
go before it starts coming down?
A. 6 m
B. 8 m
C. 10 m
D. 12 m
Answer: B) 8 m
Rationale: At maximum height, the velocity becomes 0. Using v2=u2−2ghv^2 = u^2 -
2ghv2=u2−2gh,
0=122−2×9.8×h0 = 12^2 - 2 \times 9.8 \times h0=122−2×9.8×h,
h=1222×9.8=8h = \frac{12^2}{2 \times 9.8} = 8h=2×9.8122=8 m.
2. A particle moves in a circle with radius 5 m. If the particle has a speed of 10 m/s, what is its
centripetal acceleration?
A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²
Answer: C) 10 m/s²
Rationale: Centripetal acceleration is given by ac=v2ra_c = \frac{v^2}{r}ac=rv2,
ac=1025=20a_c = \frac{10^2}{5} = 20ac=5102=20 m/s².
3. A particle of mass 4 kg is moving with a velocity of 3 m/s. What is its momentum?
A. 10 kg·m/s
B. 12 kg·m/s
C. 14 kg·m/s
,D. 16 kg·m/s
Answer: B) 12 kg·m/s
Rationale: p=mv=4×3=12p = mv = 4 \times 3 = 12p=mv=4×3=12 kg·m/s.
4. A car is moving at a constant speed of 20 m/s. What is the car’s kinetic energy?
A. 80,000 J
B. 100,000 J
C. 120,000 J
D. 160,000 J
Answer: B) 100,000 J
Rationale: KE=12mv2KE = \frac{1}{2} mv^2KE=21mv2,
KE=12×1000×202=100,000KE = \frac{1}{2} \times 1000 \times 20^2 =
100,000KE=21×1000×202=100,000 J.
5. A block is at rest on a rough horizontal surface. If the coefficient of static friction is 0.4, what
is the force required to just move the block?
A. 4 N
B. 8 N
C. 10 N
D. 12 N
Answer: B) 8 N
Rationale: The force required to overcome friction is F=μs×N=0.4×10=8F = \mu_s \times N =
0.4 \times 10 = 8F=μs×N=0.4×10=8 N.
6. A force of 20 N is applied to a 4 kg object. What is the acceleration?
A. 2 m/s²
B. 4 m/s²
C. 5 m/s²
, D. 8 m/s²
Answer: B) 5 m/s²
Rationale: Using F=maF = maF=ma,
a=Fm=204=5a = \frac{F}{m} = \frac{20}{4} = 5a=mF=420=5 m/s².
7. A particle is moving with a uniform velocity of 2 m/s for 10 seconds. What distance does the
particle cover?
A. 5 m
B. 15 m
C. 20 m
D. 25 m
Answer: C) 20 m
Rationale: Distance = velocity × time,
2×10=202 \times 10 = 202×10=20 m.
8. A body is projected horizontally with a speed of 8 m/s from a height of 20 m. How long will it
take to reach the ground?
A. 2 s
B. 3 s
C. 4 s
D. 5 s
Answer: C) 4 s
Rationale: Using s=12gt2s = \frac{1}{2} g t^2s=21gt2,
20=12×9.8×t220 = \frac{1}{2} \times 9.8 \times t^220=21×9.8×t2,
t2=409.8≈4.08t^2 = \frac{40}{9.8} \approx 4.08t2=9.840≈4.08, so t=4.08≈4t = \sqrt{4.08}
\approx 4t=4.08≈4 s.
