1. A particle of mass 5 kg is moving with a velocity of 2 m/s. What is its momentum?
A. 2 kg·m/s
B. 5 kg·m/s
C. 10 kg·m/s
D. 20 kg·m/s
Answer: C) 10 kg·m/s
Rationale: Momentum = mass × velocity. So, 5×2=105 \times 2 = 105×2=10 kg·m/s.
2. A car accelerates from rest to 30 m/s in 10 seconds. What is its acceleration?
A. 3 m/s²
B. 5 m/s²
C. 10 m/s²
D. 30 m/s²
Answer: A) 3 m/s²
Rationale: Using the formula a=Δvta = \frac{{\Delta v}}{{t}}a=tΔv, where Δv=30\Delta v =
30Δv=30 m/s, and t=10t = 10t=10 s. So, a=3010=3a = \frac{{30}}{{10}} = 3a=1030=3 m/s².
3. A block of mass 2 kg is placed on a horizontal surface. The coefficient of friction between the
block and the surface is 0.4. What is the frictional force acting on the block?
A. 2 N
B. 4 N
C. 6 N
D. 8 N
Answer: B) 4 N
,Rationale: Frictional force Ff=μ×NF_f = \mu \times NFf=μ×N, where μ=0.4\mu = 0.4μ=0.4 and
N=2×9.8=19.6N = 2 \times 9.8 = 19.6N=2×9.8=19.6 N. So, Ff=0.4×19.6=7.84F_f = 0.4 \times
19.6 = 7.84Ff=0.4×19.6=7.84 N.
4. A particle is moving with uniform velocity along a straight line. Which of the following is true
about the acceleration of the particle?
A. The acceleration is constant.
B. The acceleration is zero.
C. The acceleration is negative.
D. The acceleration is positive.
Answer: B) The acceleration is zero.
Rationale: Uniform velocity means no change in speed or direction, implying zero acceleration.
5. A body of mass 6 kg is acted upon by two forces: 10 N and 15 N. If these forces are applied in
the same direction, what is the resultant acceleration of the body?
A. 2.5 m/s²
B. 4.2 m/s²
C. 5 m/s²
D. 10 m/s²
Answer: B) 4.2 m/s²
Rationale: The resultant force is 10+15=2510 + 15 = 2510+15=25 N. Using F=maF = maF=ma,
we have a=Fm=256≈4.17a = \frac{{F}}{{m}} = \frac{{25}}{{6}} \approx
4.17a=mF=625≈4.17 m/s².
6. A particle is moving with a velocity of 4 m/s. After 5 seconds, its velocity increases to 10 m/s.
What is the acceleration of the particle?
A. 1.2 m/s²
B. 2 m/s²
C. 1.5 m/s²
, D. 3 m/s²
Answer: B) 2 m/s²
Rationale: Acceleration a=Δvt=10−45=2a = \frac{{\Delta v}}{{t}} = \frac{{10 - 4}}{{5}} =
2a=tΔv=510−4=2 m/s².
7. A stone is dropped from the top of a building. After 3 seconds, what is its velocity?
A. 9.8 m/s
B. 19.6 m/s
C. 29.4 m/s
D. 39.2 m/s
Answer: B) 29.4 m/s
Rationale: Using v=u+gtv = u + gtv=u+gt, where u=0u = 0u=0 (initial velocity), g=9.8g =
9.8g=9.8 m/s², and t=3t = 3t=3 s, we have v=0+9.8×3=29.4v = 0 + 9.8 \times 3 =
29.4v=0+9.8×3=29.4 m/s.
8. A car of mass 1000 kg is moving with a velocity of 20 m/s. What is its kinetic energy?
A. 100,000 J
B. 200,000 J
C. 400,000 J
D. 800,000 J
Answer: B) 200,000 J
Rationale: Kinetic energy KE=12mv2KE = \frac{1}{2} m v^2KE=21mv2. So,
KE=12×1000×202=200,000KE = \frac{1}{2} \times 1000 \times 20^2 =
200,000KE=21×1000×202=200,000 J.
9. A force of 5 N is applied to a 2 kg object. What is the acceleration of the object?
A. 1 m/s²
B. 2.5 m/s²
C. 5 m/s²
A. 2 kg·m/s
B. 5 kg·m/s
C. 10 kg·m/s
D. 20 kg·m/s
Answer: C) 10 kg·m/s
Rationale: Momentum = mass × velocity. So, 5×2=105 \times 2 = 105×2=10 kg·m/s.
2. A car accelerates from rest to 30 m/s in 10 seconds. What is its acceleration?
A. 3 m/s²
B. 5 m/s²
C. 10 m/s²
D. 30 m/s²
Answer: A) 3 m/s²
Rationale: Using the formula a=Δvta = \frac{{\Delta v}}{{t}}a=tΔv, where Δv=30\Delta v =
30Δv=30 m/s, and t=10t = 10t=10 s. So, a=3010=3a = \frac{{30}}{{10}} = 3a=1030=3 m/s².
3. A block of mass 2 kg is placed on a horizontal surface. The coefficient of friction between the
block and the surface is 0.4. What is the frictional force acting on the block?
A. 2 N
B. 4 N
C. 6 N
D. 8 N
Answer: B) 4 N
,Rationale: Frictional force Ff=μ×NF_f = \mu \times NFf=μ×N, where μ=0.4\mu = 0.4μ=0.4 and
N=2×9.8=19.6N = 2 \times 9.8 = 19.6N=2×9.8=19.6 N. So, Ff=0.4×19.6=7.84F_f = 0.4 \times
19.6 = 7.84Ff=0.4×19.6=7.84 N.
4. A particle is moving with uniform velocity along a straight line. Which of the following is true
about the acceleration of the particle?
A. The acceleration is constant.
B. The acceleration is zero.
C. The acceleration is negative.
D. The acceleration is positive.
Answer: B) The acceleration is zero.
Rationale: Uniform velocity means no change in speed or direction, implying zero acceleration.
5. A body of mass 6 kg is acted upon by two forces: 10 N and 15 N. If these forces are applied in
the same direction, what is the resultant acceleration of the body?
A. 2.5 m/s²
B. 4.2 m/s²
C. 5 m/s²
D. 10 m/s²
Answer: B) 4.2 m/s²
Rationale: The resultant force is 10+15=2510 + 15 = 2510+15=25 N. Using F=maF = maF=ma,
we have a=Fm=256≈4.17a = \frac{{F}}{{m}} = \frac{{25}}{{6}} \approx
4.17a=mF=625≈4.17 m/s².
6. A particle is moving with a velocity of 4 m/s. After 5 seconds, its velocity increases to 10 m/s.
What is the acceleration of the particle?
A. 1.2 m/s²
B. 2 m/s²
C. 1.5 m/s²
, D. 3 m/s²
Answer: B) 2 m/s²
Rationale: Acceleration a=Δvt=10−45=2a = \frac{{\Delta v}}{{t}} = \frac{{10 - 4}}{{5}} =
2a=tΔv=510−4=2 m/s².
7. A stone is dropped from the top of a building. After 3 seconds, what is its velocity?
A. 9.8 m/s
B. 19.6 m/s
C. 29.4 m/s
D. 39.2 m/s
Answer: B) 29.4 m/s
Rationale: Using v=u+gtv = u + gtv=u+gt, where u=0u = 0u=0 (initial velocity), g=9.8g =
9.8g=9.8 m/s², and t=3t = 3t=3 s, we have v=0+9.8×3=29.4v = 0 + 9.8 \times 3 =
29.4v=0+9.8×3=29.4 m/s.
8. A car of mass 1000 kg is moving with a velocity of 20 m/s. What is its kinetic energy?
A. 100,000 J
B. 200,000 J
C. 400,000 J
D. 800,000 J
Answer: B) 200,000 J
Rationale: Kinetic energy KE=12mv2KE = \frac{1}{2} m v^2KE=21mv2. So,
KE=12×1000×202=200,000KE = \frac{1}{2} \times 1000 \times 20^2 =
200,000KE=21×1000×202=200,000 J.
9. A force of 5 N is applied to a 2 kg object. What is the acceleration of the object?
A. 1 m/s²
B. 2.5 m/s²
C. 5 m/s²
