Summary MAT2612 ASSIGNMENT 1 2025

MAT2612
ASSIGNMENT 1
2025

, QUESTION 1




Solution:


1.1).


0 1 0 0 1 1
A+B = [ ]+[ ]
1 1 0 0 0 1
0+0 1+1 0+1
=[ ]
1+0 1+0 0+1
0 2 1
=[ ]
1 1 1


1.2).


1 0
0 1 1
BC = [ ] [1 0]
0 0 1
0 1
(0)(1) + (1)(1) + (1)(0) (0)(0) + (1)(0) + (1)(1)
=[ ]
(0)(1) + (0)(1) + (1)(0) (0)(0) + (0)(0) + (1)(1)
1 1
=[ ]
0 1

, 1.3).


0 1 0 0 1 1
A⋁B=[ ]⋁[ ]
1 1 0 0 0 1
0⋁0 1⋁1 0⋁1
=[ ]
1⋁0 1⋁0 0⋁1
0 1 1
=[ ]
1 1 1


1.4).


0 1 0 0 1 1
A⋀B=[ ]⋀[ ]
1 1 0 0 0 1
0⋀0 1⋀1 0⋀1
=[ ]
1⋀0 1⋀0 0⋀1
0 1 0
=[ ]
0 0 0


1.5).


B ⊙ C is not defined since matrices B and C are of different sizes.