1. In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. The value of tan C is:
(a) 12/7
(b) 24/7
(c) 20/7
(d) 7/24
Answer: (b) 24/7
Explanation: AB = 24 cm and BC = 7 cm
tan C = Opposite side/Adjacent side
tan C = 24/7
2. (Sin 30°+cos 60°)-(sin 60° + cos 30°) is equal to:
(a) 0
(b) 1+2√3
(c) 1-√3
(d) 1+√3
Answer: (c) 1-√3
Explanation: sin 30° = ½, sin 60° = √3/2, cos 30° = √3/2 and cos 60° = ½
Putting these values, we get:
(½+½)-(√3/2+√3/2)
= 1 – [(2√3)/2]
= 1 – √3
3. The value of tan 60°/cot 30° is equal to:
(a) 0
, (b) 1
(c) 2
(d) 3
Answer: (b) 1
Explanation: tan 60° = √3 and cot 30° = √3
Hence, tan 60°/cot 30° = √3/√3 = 1
4. 1 – cos2A is equal to:
(a) sin2A
(b) tan2A
(c) 1 – sin2A
(d) sec2A
Answer: (a) sin2A
Explanation: We know, by trigonometry identities,
sin2A + cos2A = 1
1 – cos2A = sin2A
5. sin (90° – A) and cos A are:
(a) Different
(b) Same
(c) Not related
(d) None of the above
(a) 12/7
(b) 24/7
(c) 20/7
(d) 7/24
Answer: (b) 24/7
Explanation: AB = 24 cm and BC = 7 cm
tan C = Opposite side/Adjacent side
tan C = 24/7
2. (Sin 30°+cos 60°)-(sin 60° + cos 30°) is equal to:
(a) 0
(b) 1+2√3
(c) 1-√3
(d) 1+√3
Answer: (c) 1-√3
Explanation: sin 30° = ½, sin 60° = √3/2, cos 30° = √3/2 and cos 60° = ½
Putting these values, we get:
(½+½)-(√3/2+√3/2)
= 1 – [(2√3)/2]
= 1 – √3
3. The value of tan 60°/cot 30° is equal to:
(a) 0
, (b) 1
(c) 2
(d) 3
Answer: (b) 1
Explanation: tan 60° = √3 and cot 30° = √3
Hence, tan 60°/cot 30° = √3/√3 = 1
4. 1 – cos2A is equal to:
(a) sin2A
(b) tan2A
(c) 1 – sin2A
(d) sec2A
Answer: (a) sin2A
Explanation: We know, by trigonometry identities,
sin2A + cos2A = 1
1 – cos2A = sin2A
5. sin (90° – A) and cos A are:
(a) Different
(b) Same
(c) Not related
(d) None of the above
