Correct Answers
Chapter 0
Topics mentioned in Chapter 0 that these flash cards do not cover: - Answer-- graphing
inequalities
- piecewise functions
- one to one functions
- limits and continuity
- basic rules of differentiation
- basic integration
- method of substitution
/.Chapter 0
For any two sets A and B, (A∩B)∪(A∩B') = - Answer-A
/.Chapter 0
Two sets A and B are disjoint if A∩B = - Answer-∅
/.Chapter 0
n(S) is defined to be - Answer-the number of elements in a set
/.Chapter 0
n(A∩B) + n(A∩B') = - Answer-n(A)
/.Chapter 0
In order to account for double counting, n(A∪B) = - Answer-n(A) + n(B) - n(A∩B)
/.Chapter 0
In order to account for double counting in three sets, n(A∪B∪C) = - Answer-n(A) + n(B)
+ n(C) - n(A∩B) - n(A∩C) - n(B∩C) + n(A∩B∩C)
(how does this work for a number of sets greater than three?)
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The inverse of a function ƒ(x) = y is - Answer-the function solved for x in terms of y,
such that if ƒ(x₀) = y₀, ƒ⁻¹(y₀) = x₀
/.Chapter 0
A quadratic function of the form ax² + bx + c = 0 can be solved with the quadratic
equation: - Answer-[-b ± √(b² - 4ac)] / 2a
/.Chapter 0
y = b^x ↔ log.b(y) = - Answer-x
,/.Chapter 0
The natural logarithm is - Answer-log.e(y) = ln(y)
/.Chapter 0
Important properties of logarithms: - Answer-...
/.Chapter 0
Partial differentiation with respect to x is found by - Answer-differentiating with respect
to x and regarding y as a constant, then substituting in x₀ and y₀
/.Chapter 0
Antiderivatives of frequently used functions: - Answer-(for individual flash cards, see
other deck)
/.Chapter 0
Useful integration rules: - Answer-(for individual flash cards, see other deck)
/.Chapter 0
Integration by parts: - Answer-∫ v × du = v × u - ∫ dv × u
/.Chapter 0
∫ e^(ax) = - Answer-[axe^(ax) - e^(ax)] / a^2
/.Chapter 0
∫ xe^(ax) = - Answer-xe^(ax) / a - e^(ax) / a^2
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Geometric progression : a, ar, ar², ar³, ...
Sum of first n terms: - Answer-a + ar + ar² + ... + arⁿ⁻¹ = a[1 + r + r² + ... + rⁿ⁻¹] = a × (rⁿ-
1)/(r-1) = a × (1- rⁿ)/(1-r)
/.Chapter 0
∫ xⁿe^(-cx) = - Answer-n!/c^(n+1)
/.Chapter 0
Infinite sum of geometric series: - Answer-a/(1-r)
/.Chapter 0
Arithmetic progression: a, a +d, a + 2d, a + 3d, ...,
sum of first n terms - Answer-na + d × n(n-1)/2
/.Chapter 1
Topics mentioned in chapter 1 that these flash cards do not cover: - Answer-Definitions:
- event
- union of events
, - intersection of events
- complement
- continuous probability space
/.Chapter 1
Sample point - Answer-the simple outcome of a random experiment
/.Chapter 1
Probability space - Answer-the collection of all possible sample points related to a
specific experiment
/.Chapter 1
Mutually exclusive outcomes - Answer-cannot occur simultaneously (disjoint)
A∩B = ∅
/.Chapter 1
Exhaustive outcomes - Answer-outcomes that combine to be the entire probability
space, or equivalently, at least one of the outcomes must occur whenever the
experiment is performed
A₁∪A₂∪...∪A.n = S, the entire probability space
/.Chapter 1
Subevent (subset) - Answer-B contains all sample points in event A, then A is subevent
of B, A⊂B. The occurrence of A implies event B.
/.Chapter 1
Partition of A - Answer-C₁, C₂, C₃₃, ..., C.n form a partition of A if A = the union of all Cs
and the Cs are mutually exclusive
/.Chapter 1
DeMorgan's Laws:
(A∪B)' =
(A∩B)' = - Answer-(A∪B)' = A'∪B'
(A∩B)' = A'∩B'
/.Chapter 1
Indicator function for event A, I.A(x) = - Answer-I.A(x) = 1 if x ∈ A
I.A(x) = 0 if x ∉ A
/.Chapter 1
A∩(B₁∪B₂∪...∪B.n) =
A∪(B₁∩B₂∩...∩B.n) = - Answer-(A∩B₁)∪...∪(A∩B.n)
(A∪B₁)∩...∩(A∪B.n)
/.Chapter 1
If B₁...B.n are exhaustive events then for any event A, A = - Answer-(A∩B₁)∪...∪(A∩B.n)