TMC (LJU version 7) with 100%
correct answers already graded A+
(VERIFIED & UPDATED)
A respiratory therapist has achieved the following weaning parameters on
a post-operative patient who experienced a total knee replacement. The
SpO2 is 97% on 35% oxygen.
Spont VT 480 mL
VC 1600 mL
VE 7.0 L
MIP -4 cm H2O
The next best action would be to
A. check the pressure manometer for leaks
B. reduce FIO2 to 0.30
C. evaluate the MEF
D. return to full mechanical ventilation - answer The correct answer is : A
Explanation :
Most of the weaning parameters listed are very good and suggest that the
patient is strong enough for weaning. The respiratory therapist should not
believe the NIF result of -4 cm H2O because it is not consistent with the
remainder of the results. A leak is likely present in the manometer set up.
In preparation for a smoking cessation class, the therapist should include
information on which of the following agents?
A. Aminophylline
B. Pronestyl
C. Sub-lingual Lidocaine spray
D. nicotine patch - answer The correct answer is : D
,Explanation :
Of the options offered, only the nicotine patch will be helpful for a patient
who is trying to stop smoking. Other medications listed here relate to the
heart or long-term bronchodilation.
A respiratory therapy supervisor is responsible for making suggestions in
the initial development of a smoking cessation program. Which of the
following would be part of an effective smoking cessation program?
A. Nicotine replacement therapy
B. removing pulmonary irritants from the house
C. daily COHb analysis
D. daily completion of an asthma action plan - answer The correct answer
is : A
Explanation :
To stop smoking, both physiological and emotional barriers must be
addressed. The patient may be helped best through nicotine replacement
therapy and emotional support. Routine monitoring of the patient's
progress is also helpful. Removing irritants from the house will not help
the patient stop smoking.
Heated humidification would be most important for a patient using
A. an endotracheal tube
B. a 6 L/min nasal cannula
C. a Venturi mask set at FIO2 0.5
D. a face tent with an air entrainment device set at 50% - answer The
correct answer is : A
Explanation :
Heated humidification is most helpful to patients who cannot receive
humidification by natural means. This occurs when an artificial airway is in
place and the natural humidification processes of the body are bypassed.
An endotracheal tube is an example of such an airway.
,A 5-year old patient with acute epiglottitis has just received a
tracheotomy and is returned to the emergency department for monitoring.
The patient is now breathing through a tracheostomy tube. Which of the
following is most important at this time?
A. keep the tracheostomy tube cuff inflated
B. mechanical ventilatory support
C. provide heated humidity
D. provide cool aerosol therapy - answer The correct answer is : C
Explanation :
A patient who has a tracheostomy tube in place is unable to naturally
humidify inspired gases because the natural humidification processes of
the body, including the nasal passages and oropharynx, are bypassed. In
this case, providing heated humidity, which can make up the entire
humidity deficit, is paramount.
The preferred method of delivery for humidification for a pediatric patient
during a transport lasting twelve hours is a (an)
A. cascade humidifier
B. bubble humidifier
C. HME
D. heated humidifier - answer The correct answer is : C
Explanation :
A heat moisture exchanger (HME), is inexpensive, convenient, and
practical for a relatively short duration transport. The other options would
be difficult or impossible to manage for a patient transport.
The respiratory therapist is asked to estimate the alveolar minute
ventilation on a spontaneously breathing 68 kg (150 lb) female who is
receiving oxygen therapy by air-entrainment mask at FIO2 0.50. The
following data is available
Exhaled VT 450 mL
, mPAP 15 torr
PaCO2 40 torr
PaO2 70 torr
Respiratory rate 12/min
The therapist should report an alveolar minute ventilation of:
A. 5.4 L/min
B. 4.6 L/min
C. 3.6 L/min
D. 12.0 L/min - answer The correct answer is : C
Explanation :
To determine alveolar ventilation, dead space should be subtracted from
each tidal volume. The amount of dead space per tidal volume is
equivalent to 1 mL/lb of ideal body weight. In this case, the patient weighs
200 lbs and therefore has 150 mL of dead space for every inhaled tidal
volume. The amount of gas that goes to the alveoli is, therefore, 300 mL
per breath or 3.6 L per minute. This is calculated by subtracting 150 mL
from 450 mL (the patient's VT) and then multiplying by the respiratory
rate.
How many minutes will a full E cylinder oxygen tank last when running at
5 L/min?
A. 123 minutes
B. 1320 minutes
C. 90 minutes
D. 616 minutes - answer The correct answer is : A
Explanation :
The E cylinder tank factor is 0.28. A full E cylinder is 2200 PSI. 2200x0.28
is equal to 616 L. 616 divided by 5 (the liter flow to the patient) is equal to
approximately 123 min. That is how long the tank will last in minutes. To
get hours, you must further divide by 60 minutes.
correct answers already graded A+
(VERIFIED & UPDATED)
A respiratory therapist has achieved the following weaning parameters on
a post-operative patient who experienced a total knee replacement. The
SpO2 is 97% on 35% oxygen.
Spont VT 480 mL
VC 1600 mL
VE 7.0 L
MIP -4 cm H2O
The next best action would be to
A. check the pressure manometer for leaks
B. reduce FIO2 to 0.30
C. evaluate the MEF
D. return to full mechanical ventilation - answer The correct answer is : A
Explanation :
Most of the weaning parameters listed are very good and suggest that the
patient is strong enough for weaning. The respiratory therapist should not
believe the NIF result of -4 cm H2O because it is not consistent with the
remainder of the results. A leak is likely present in the manometer set up.
In preparation for a smoking cessation class, the therapist should include
information on which of the following agents?
A. Aminophylline
B. Pronestyl
C. Sub-lingual Lidocaine spray
D. nicotine patch - answer The correct answer is : D
,Explanation :
Of the options offered, only the nicotine patch will be helpful for a patient
who is trying to stop smoking. Other medications listed here relate to the
heart or long-term bronchodilation.
A respiratory therapy supervisor is responsible for making suggestions in
the initial development of a smoking cessation program. Which of the
following would be part of an effective smoking cessation program?
A. Nicotine replacement therapy
B. removing pulmonary irritants from the house
C. daily COHb analysis
D. daily completion of an asthma action plan - answer The correct answer
is : A
Explanation :
To stop smoking, both physiological and emotional barriers must be
addressed. The patient may be helped best through nicotine replacement
therapy and emotional support. Routine monitoring of the patient's
progress is also helpful. Removing irritants from the house will not help
the patient stop smoking.
Heated humidification would be most important for a patient using
A. an endotracheal tube
B. a 6 L/min nasal cannula
C. a Venturi mask set at FIO2 0.5
D. a face tent with an air entrainment device set at 50% - answer The
correct answer is : A
Explanation :
Heated humidification is most helpful to patients who cannot receive
humidification by natural means. This occurs when an artificial airway is in
place and the natural humidification processes of the body are bypassed.
An endotracheal tube is an example of such an airway.
,A 5-year old patient with acute epiglottitis has just received a
tracheotomy and is returned to the emergency department for monitoring.
The patient is now breathing through a tracheostomy tube. Which of the
following is most important at this time?
A. keep the tracheostomy tube cuff inflated
B. mechanical ventilatory support
C. provide heated humidity
D. provide cool aerosol therapy - answer The correct answer is : C
Explanation :
A patient who has a tracheostomy tube in place is unable to naturally
humidify inspired gases because the natural humidification processes of
the body, including the nasal passages and oropharynx, are bypassed. In
this case, providing heated humidity, which can make up the entire
humidity deficit, is paramount.
The preferred method of delivery for humidification for a pediatric patient
during a transport lasting twelve hours is a (an)
A. cascade humidifier
B. bubble humidifier
C. HME
D. heated humidifier - answer The correct answer is : C
Explanation :
A heat moisture exchanger (HME), is inexpensive, convenient, and
practical for a relatively short duration transport. The other options would
be difficult or impossible to manage for a patient transport.
The respiratory therapist is asked to estimate the alveolar minute
ventilation on a spontaneously breathing 68 kg (150 lb) female who is
receiving oxygen therapy by air-entrainment mask at FIO2 0.50. The
following data is available
Exhaled VT 450 mL
, mPAP 15 torr
PaCO2 40 torr
PaO2 70 torr
Respiratory rate 12/min
The therapist should report an alveolar minute ventilation of:
A. 5.4 L/min
B. 4.6 L/min
C. 3.6 L/min
D. 12.0 L/min - answer The correct answer is : C
Explanation :
To determine alveolar ventilation, dead space should be subtracted from
each tidal volume. The amount of dead space per tidal volume is
equivalent to 1 mL/lb of ideal body weight. In this case, the patient weighs
200 lbs and therefore has 150 mL of dead space for every inhaled tidal
volume. The amount of gas that goes to the alveoli is, therefore, 300 mL
per breath or 3.6 L per minute. This is calculated by subtracting 150 mL
from 450 mL (the patient's VT) and then multiplying by the respiratory
rate.
How many minutes will a full E cylinder oxygen tank last when running at
5 L/min?
A. 123 minutes
B. 1320 minutes
C. 90 minutes
D. 616 minutes - answer The correct answer is : A
Explanation :
The E cylinder tank factor is 0.28. A full E cylinder is 2200 PSI. 2200x0.28
is equal to 616 L. 616 divided by 5 (the liter flow to the patient) is equal to
approximately 123 min. That is how long the tank will last in minutes. To
get hours, you must further divide by 60 minutes.
