100% Correct Answers
1. John bought a camera on sale that normally (c) $128
costs $160. If the price was reduced 20% dur-
ing the sale, what was the sale price of the This question asks you
camera? to determine the sale
price of a camera that
(a) $120 normally sells at $160
(b) $124 and is discounted 20%.
(c) $128 To solve, determine what
(d) $140 20% of $160 equals.
Rewrite 20% as a deci-
mal.
20% = 0.20. So 20% of
$160 = 0.20 x $160 =
$32.
The sale price of the cam-
era would be $160 - $32
= $128, choice (c)
2. A subway car passes 3 stations every 10 min- (b) 18
utes. At this rate, how many stations will it pass
in one hour? First, set up the rate as
a proportion, where (x) is
(a) 15 the number of stations.
(b) 18
(c) 20 3 stations/10 minutes =
(d) 30 (x) stations/1 hour
Then, convert the units.
3 stations/10 minutes =
(x) stations/60 minutes
Cross multiply and solve
for (x).
180 = 10(x)
18 = (x)
,ASVAB - Arithmetic Reasoning/Mathematics Knowledge Test with
100% Correct Answers
3. On a certain map, 3/4 inch represents one mile. (b) 2 1/3
What distance, in miles, is presented by 1 3/4
inches? In this question, the ratio
is implied: for every 3/4
(a) 1 1/2 inch of map there is 1 real
(b) 2 1/3 mile, so the ratio of inch-
(c) 2 1/2 es to the miles they rep-
(d) 5 1/4 resent is always 3/4 to 1.
Therefore, you can set up
the proportion:
number of inches/ num-
ber of miles = 3/ = 3/4
Now 1 3/4 inches = 7/4
inches.
Set up a proportion:
7/4 inches
7/4 inches / number of
miles = 3/4
Cross-multiply:
7/4(4) = 3 (number of
miles)
7= 3(number of miles)
7/3 = number of miles or
2 1/3 = number of miles
4. A certain box contains baseballs and golf balls. (d) 45
If the ratio of baseballs to golf balls is 2:3 and
there are 30 baseballs in the box, how many You can express the ratio
golf balls are in the box? of baseballs to golf balls
, as 2/3. Since you know
(a) 18 the number of baseballs,
(b) 20 you can set up a propor-
(c) 36 tion: 2/3 = 30/ (x) where
(d) 45 (x) is the number of golf
balls. To solve, cross-mul-
tiply to get 2(x) = 90, or x
= 45.
5. Four people shared a taxi to the airport. The (d) $11.25
fare was $36.00, and they gave the driver a tip
equal to 25% of the fare. If they equally shared The total cost of the taxi
the cost of the fare and tip, how much did each ride equals $36 + (25%
person pay? of $36), or $36 + (.25 x
$36) = $36 + $9 = $45. If
(a) $9.75 four people split the cost
(b) $10.25 equally, then each per-
(c) $10.75 son paid $45/4, or $11.25
(d) $11.25 each.
6. If a car travels 1/100 of a kilometer each sec- (a) 36
ond, how many kilometers does it travel in an
hour? Find the number of sec-
onds in an hour and then
(a) 36 multiply this by the dis-
(b) 60 tance the car is traveling
(c) 72 each second. There are
(d) 100 60 seconds in a minute
and 60 minute in one
hour; therefore, there are
60 x 60, or 3,600, sec-
onds in an hour. In one
second the car travels
1/100 kilometers; in one
hour the car will travel
3,600 x 1/100 or 36 kilo-
meters.
7.
, 20 - (-5) = . (b) 25
(a) -25 Subtracting a negative
(b) 25 number is the same as
(c) 15 addition, so 20 - (-5) is
(d) -15 really 20 + 5 = 25.
8. Ms. Smith drove a total of 700 miles on a busi- (c) $25.00
ness trip. If her car averaged 35 miles per gal-
lon of gasoline and gasoline cost $1.25 per gal- If Ms. Smith's car aver-
lon, what was the cost in dollars of the gasoline age 35 miles per gallon,
for the trip? she can go 35 miles on
1 gallon. To go 700 miles
(a) $20.00 she will need 700/35, or
(b) $ 24.00 20 gallons of gasoline.
(c) $ 25.00 The price of gasoline was
(d) $40.00 $1.25 per gallon, so she
spent 20 x $1.25, or $25,
for her trip.
9. After eating 25% of the jelly beans, Brett had (d) 96
72 left. How many jelly beans did Brett have
originally? Be careful with a ques-
tion like this one. You're
(a) 90 given the percent de-
(b) 94 crease (25%) and the
(c) 95 new number (72), and
(d) 96 you're asked to recon-
struct the original num-
ber. Don't just take 25%
of 72 and add it on. That
25% is based not on the
new number, 72, but on
the original number - the
number you're looking for.
The best way to do a
problem like this is to set
up an equation: