Cea201 Exam Questions With Correct
Answers A+
Simplification of the Boolean expression (A+B+C)(D+E)' + (A+B+C).(D+E) yields which of the
following results?
A+B+C
D+E
A'.B'.C'
D'.E'
None of the others - Answer✔A
What is the definition of "Information"?
It is the newspaper
It is a hard disk, which can store a lot of data.
Data communicated or received that resolves uncertainty about a particular fact or circumstance.
It is the internet - Answer✔C
A /an __________ is an unambiguous mapping between bit strings and the set of possible data.
Communication
store data
decoding
encoding - Answer✔D
How many bits are needed to encode the 10 decimal digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}?
2
4
9
10 - Answer✔B
How many bits are needed to encode the 128 ASCII characters (Control and Printable)?
, ©Jason McConnel 2025 ALL RIGHTS RESERVED.
7
8
9
128 - Answer✔A
We have four symbols, we might choose a unique two-bit string for each: "A" could be "00", B =
"01", C = "10" and D = "11". The encoding for the message "CBAD" would be__________?
00001111
10101010
10010011
10011001 - Answer✔C
The binary number 00010011 is equal to the decimal number ______.
33
3
19
131
13 - Answer✔C
The largest unsigned decimal number that can be represented in binary using eight bits is
______.
64
127
128
255
256 - Answer✔D
The decimal number 21 is equal to the binary number ______.
11110
10001
10101
10110
11101 - Answer✔C
2's complement of '-6' in 4 bits format is ______.
, ©Jason McConnel 2025 ALL RIGHTS RESERVED.
1101
1011
0101
1010
0110 - Answer✔D
Which of the number is not a representative of hexadecimal system?
1234
ABBA
1001
DEFG
2018 - Answer✔D
Addition with signed numbers 8 bits (in 2's complement form): 10001011 + 00010001 =
________.
10101110
10001011
11110110
10011100
Overflow - Answer✔D
Subtraction with signed numbers 5 bits (in 2's complement form): 00011 - 11011 = ______.
10001
01000
10101
00111
Overflow - Answer✔B
The binary number for 0xA0F18 is ______. (binary and hexadecimal numbers using the format
0b____ and 0x____, respectively)
0b 1111 0000 1111 0001 0000
0b 1010 0000 1111 0001 1001
0b 1010 0000 1111 0001 1111
0b 1010 0000 1111 0001 1000