TEST BANK QUESTIONS WITH
CORRECT DETAILED ANSWERS
(y^2 + yx)dx - (x^2)dy = 0 - Answer-homogeneous
1/2x^2 + x/y = c
(x+y)dx + (x)dy = 0 - Answer-homogeneous
c = 1/2x^2 + 1/2ln(2(y/x)+1)
(y^2 + yx)dx + (x^2)dy = 0 - Answer-homogeneous
c = ln(x) + 1/2ln(y/x) - ln((y/x)+2)
dy/dx = (y-x)/(y+x) - Answer-homogeneous
-1/2ln((y/x)^2 +1) - tan^-1(y/x) = ln(x) + c
dy/dx = (x + 3y)/(3x + y) - Answer-homogeneous
Ln((y/x) + 1) - 2ln((y/x) - 1) = Ln(x) + c
(x)dy/dx + y = 1/y^2 - Answer-Bernoulli's
(y^3)= (1/3x^-2/3 + c)/(x^1/3)
dy/dx - y = e^x(y^2) - Answer-Bernoulli's
e^x(1/y) = -1/2(e^2x) + c
dy/dx = y(xy^3 - 1) - Answer-(e^-3x)(y^-3) = xe^-3x - 1/3e^-3x + c
(x)dy/dx - (1+x)y = xy^2 - Answer-Bernoulli's
1/y = (-e^x(x+1) + c)/(xe^x)
(x^2)dy/dx - 2xy = 3y^4 y(1) = 1/2 - Answer-Bernoulli's
1/y^3 = ((-9/5)x^5 + 19/5)/(x^6)