IICRC S500 Water Mitigation Questions and Answers
The homeowner - ANSWERis responsible to take the necessary steps to preserve and protect their property from further damage
Four principles of water damage restoration: - ANSWERProvide for health and safety of workers and occupants; Document everything; Mitigate, and Dry
Four principles of drying - ANSWERExtract, Evaporate, dehumidify, control temp
Extraction - ANSWERis removing excess water and is the first step in mitigation
Evaporation - ANSWERis achieved by using energy (heat) to transform water trapped in
porous materials into a vapor, thereby releasing the moisture from the materials.
Dehumidification - ANSWERthe process of removing water vapor from the air.
Rate of Dehumidification - ANSWERmust be at least equal to the rate of evaporation.
True or False - ANSWERElevated vapor pressure in a room Can cause secondary damage to hygroscopic materials
True or False - ANSWERThe control of temperature is important to enhance both evaporation and dehumidification for effective drying
True or False - ANSWERWhen temperature increases evaporation of absorbed water increases and water vapor suspended in air also increases.
Classification of Water Intrusion - ANSWERdescribed as Class 1, 2, 3, or 4. Must be determined to calculate the amount of dehumidification required in drying process, based on the amount of wet surface area, permeance/porosity of materials in drying area.
Class 1 - ANSWERis the least amount of water absorption and evaporation load, affecting less 5% of porous materials with minimal absorption into low evaporation materials.
Class 2 - ANSWERhas a significant amount of water absorption and evaporation load, affection 5-40% porous materials, with minimal absorption into low evaporated materials Class 3 - ANSWERhas the greatest amount of water absorption and evaporation load, affecting more than 40% porous materials and minimal absorption into low evaporated materials
Class 4 - ANSWERhas deeply held or bound water, and significant absorption into low evaporation materials.
Determine the Class of water for a 20' x 20' x 8 ' room, with an entirely wet floor.. - ANSWERAffected area/Total SF = % affected
400/1440 = .27777 x 100 = 28% 28% = Class 2
Determine the Class of Water for a 20' x 20' x 8' room, with only half the floor affected and arriving within 24 hours of loss. - ANSWERAffected area/total sf = % affected
200/1440 = .13888 x 100 = 14%
14% = Class 2
Determine Class of water for a 20' x 20' x 8' room, with entirely wet plywood subfloor arriving 48 hours after loss - ANSWERaffected area/total sf = % affected
Class 4 due to deeply bound water sitting for long time
Categories of Water - ANSWERthere are four categories - determined by range of contamination of the source and quality of water
Category 1 water - ANSWERWater originating from sanitary water source, with no deterioration, does not pose risk to skin or if ingested
Category 2 Water - ANSWERWater containing significant contamination from materials,
unsafe levels of microorganisms, causes discomfort or sickness.
Category 3 Water - ANSWERWater grossly contaminated with pathogens, toxins, bacteria, causes sickness
Regulated or Hazardous Material and Mold - ANSWERthe last category of water, without number designation, requiring a specialized environmental expert (EIP) to assist
where government regulations apply.
The ANSI/IICRC S500 - ANSWERIs the standard of care for the water damage restoration industry, providing foundation for basic principles of proper restoration practices.
When the ANSI/IICRC S500 uses the word "Shall" it means - ANSWERit is something mandatory due to laws/regulations
When the ANSI/IICRC S500 uses the word "Should" it means - ANSWERit is something
that is mandatory but not due to laws
The homeowner - ANSWERis responsible to take the necessary steps to preserve and protect their property from further damage
Four principles of water damage restoration: - ANSWERProvide for health and safety of workers and occupants; Document everything; Mitigate, and Dry
Four principles of drying - ANSWERExtract, Evaporate, dehumidify, control temp
Extraction - ANSWERis removing excess water and is the first step in mitigation
Evaporation - ANSWERis achieved by using energy (heat) to transform water trapped in
porous materials into a vapor, thereby releasing the moisture from the materials.
Dehumidification - ANSWERthe process of removing water vapor from the air.
Rate of Dehumidification - ANSWERmust be at least equal to the rate of evaporation.
True or False - ANSWERElevated vapor pressure in a room Can cause secondary damage to hygroscopic materials
True or False - ANSWERThe control of temperature is important to enhance both evaporation and dehumidification for effective drying
True or False - ANSWERWhen temperature increases evaporation of absorbed water increases and water vapor suspended in air also increases.
Classification of Water Intrusion - ANSWERdescribed as Class 1, 2, 3, or 4. Must be determined to calculate the amount of dehumidification required in drying process, based on the amount of wet surface area, permeance/porosity of materials in drying area.
Class 1 - ANSWERis the least amount of water absorption and evaporation load, affecting less 5% of porous materials with minimal absorption into low evaporation materials.
Class 2 - ANSWERhas a significant amount of water absorption and evaporation load, affection 5-40% porous materials, with minimal absorption into low evaporated materials Class 3 - ANSWERhas the greatest amount of water absorption and evaporation load, affecting more than 40% porous materials and minimal absorption into low evaporated materials
Class 4 - ANSWERhas deeply held or bound water, and significant absorption into low evaporation materials.
Determine the Class of water for a 20' x 20' x 8 ' room, with an entirely wet floor.. - ANSWERAffected area/Total SF = % affected
400/1440 = .27777 x 100 = 28% 28% = Class 2
Determine the Class of Water for a 20' x 20' x 8' room, with only half the floor affected and arriving within 24 hours of loss. - ANSWERAffected area/total sf = % affected
200/1440 = .13888 x 100 = 14%
14% = Class 2
Determine Class of water for a 20' x 20' x 8' room, with entirely wet plywood subfloor arriving 48 hours after loss - ANSWERaffected area/total sf = % affected
Class 4 due to deeply bound water sitting for long time
Categories of Water - ANSWERthere are four categories - determined by range of contamination of the source and quality of water
Category 1 water - ANSWERWater originating from sanitary water source, with no deterioration, does not pose risk to skin or if ingested
Category 2 Water - ANSWERWater containing significant contamination from materials,
unsafe levels of microorganisms, causes discomfort or sickness.
Category 3 Water - ANSWERWater grossly contaminated with pathogens, toxins, bacteria, causes sickness
Regulated or Hazardous Material and Mold - ANSWERthe last category of water, without number designation, requiring a specialized environmental expert (EIP) to assist
where government regulations apply.
The ANSI/IICRC S500 - ANSWERIs the standard of care for the water damage restoration industry, providing foundation for basic principles of proper restoration practices.
When the ANSI/IICRC S500 uses the word "Shall" it means - ANSWERit is something mandatory due to laws/regulations
When the ANSI/IICRC S500 uses the word "Should" it means - ANSWERit is something
that is mandatory but not due to laws
