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Solutions for Numerical Methods in Chemical Engineering Using Python® and Simulink®, 1st Edition Ghasem (All Chapters included)

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Complete Solutions Manual for Numerical Methods in Chemical Engineering Using Python® and Simulink®, 1st Edition by Nayef Ghasem ; ISBN13: 9781032419466. (Full Chapters included Chapter 1 to 9)....1. Introduction. 2. Numerical Solutions of Linear Systems. 3. Bracketing Numerical Methods for Solving Systems of Nonlinear Equations. 4. Open Numerical Methods for Solving Systems of Nonlinear Equations. 5. Initial Value Problem Differential Equations. 6. Numerical Integration of Definite Functions. 7. Numerical Solution of Ordinary Differential Equations. 8. Simultaneous Systems of Differential Equations. 9. Boundary Value Problems Ordinary Differential Equations.

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Uploaded on
March 20, 2024
Number of pages
219
Written in
2023/2024
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Numerical Methods in Chemical
Engineering Using Python® and
Simulink®, 1st Edition by Nayef
Ghasem




Complete Chapter Solutions Manual
are included (Ch 1 to 9)




** Immediate Download
** Swift Response
** All Chapters included
** Program Files included

, Chapter 1

Introduction to Numerical Methods




Problems

1. Solve the following linear algebraic equation.

𝑥 + 7 = 12

Find the value of 𝑥



Solution

𝑥 = 12 − 7 = 5

2. Solve the following system of linear algebraic equations.

2𝑥 + 𝑦 = 6

𝑥+𝑦 =4

Find the value of 𝑥, 𝑦

Solution

2𝑥 + 𝑦 = 6 (1)

𝑥+𝑦 =4 (2)

(1) − (2): 𝑥 = 2

Substitute 𝑥 = 2 𝑖𝑛 (2) → 𝑦 = 2



3. A system of nonlinear equations consists of two or more equations with at least one

equation that is not linear

𝑥 2 + 𝑦 2 = 25

3𝑥 + 4𝑦 = 0




1

, Find the value of 𝑥, 𝑦

Solution

𝑥 2 + 𝑦 2 = 25 (1)

3𝑥 + 4𝑦 = 0 (2)
3
From (2) 4𝑦 = −3𝑥 ==> 𝑦 = − 4 𝑥

Substitute in (1)

2
3 2
𝑥 + (− 𝑥) = 25
4
9 2
𝑥2 + 𝑥 = 25
16
16 + 9 2
𝑥 = 25
16

25 2
𝑥 = 25
16
16
𝑥 2 = 25 ∗ = 16
25

𝑥 = ∓4



4. Solve the system of two nonlinear equations

𝑥 2 + 𝑦 2 = 45

𝑥 2 − 𝑦 2 = −27

Find the value of 𝑥, 𝑦

Solution

𝑥 2 + 𝑦 2 = 45 (1)

𝑥 2 − 𝑦 2 = −27 (2)

Add (1) and (2)

2𝑥 2 = 45 − 27 = 18

𝑥2 = 9

Hence




2

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