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CHEM 103 EXAM LATEST UPDATE QUESTIONS AND CORRECT ANSWERS ALREADY GRADED A+
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Show the balanced equation and the calculation of the number of moles and grams of Al2(SO4)3 formed from 15.3 grams of H2SO4. Show your answers to 3 significant figures. Al(OH)3 + H2SO4 → Al2(SO4)3 + H2O Your Answer: 2 Al(OH)3 + 3 H2SO4 →Al2(SO4)3 + 6 H2O 15.3g H2SO4 X 1 mol H2SO4/98 g X 1 mole Al2(SO4)3 /3 mol H2SO4 =0.0520 mole Al2(SO4)3 0.0520 mol Al2(SO4)3 X 34.15g /1 mol Al2(SO4)3 = 17.8g Al2(SO4)3
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