Gcse Edexcel 2023 Higher Mathematics Paper 2 Non Calculator Question Paper.
GCSE EDEXCEL 2023 HIGHER MATHEMATICS PAPER 2 NON CALCULATOR QUESTION PAPER. *P75150A0128* Turn over Please check the examination details below before entering your candidate information Candidate surname Other names Centre Number Candidate Number Pearson Edexcel Level 1/Level 2 GCSE (9–1) Wednesday 7 June 2023 Morning (Time: 1 hour 30 minutes) 1MA1/2H Paper reference Total Marks Mathematics PAPER 2(Calculator) Higher Tier You must have: Ruler graduated in centimetres and millimetres, protractor, pair of compasses, pen, HB pencil, eraser, calculator, Formulae Sheet (enclosed). Tracing paper may be used. Instructions • Use black ink or ball-point pen. • Fill in the boxes at the top of this page with your name, centre number and candidate number. • Answer all questions. • Answer the questions in the spaces provided – there may be more space than you need. • You must show all your working. • Diagrams are NOT accurately drawn, unless otherwise indicated. • Calculators may be used. • If your calculator does not have a π button, take the value of π to be 3.142 unless the question instructs otherwise. Information • The total mark for this paper is 80 • The marks for each question are shown in brackets – use this as a guide as to how much time to spend on each question. Advice • Read each question carefully before you start to answer it. • Try to answer every question. • Check your answers if you have time at the end. P75150A ©2023 Pearson Education Ltd. N:1/1/1/1/1/1/ *P75150A0228* D O N O T W RIT E IN T HIS A R E A D O N O T W RIT E IN T HIS A R E A D O N O T W RIT E IN T HIS A R E A DONOTWRITEINTHISAREADONOTWRITEINTHISAREADONOTWRITEINTHISAREA2 Answer ALL questions. Write your answers in the spaces provided. You must write down all the stages in your working. 1 (a) Work out the value of 25 43 87 6 2 12 . . Write down all the figures on your calculator display. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (2) (b) Work out the value of the reciprocal of 0.625 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (1) (Total for Question 1 is 3 marks) *P75150A0328* Turn over 3 D O N O T W RIT E IN T HIS A R E A D O N O T W RIT E IN T HIS A R E A D O N O T W RIT E IN T HIS A R E A D O N O T W RIT E IN T HIS A R E A D O N O T W RIT E IN T HIS A R E A D O N O T W RIT E IN T HIS A R E A 2 Write 60 as a product of its prime factors. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (Total for Question 2 is 2 marks) 3 There are 48 counters in a bag. There are only red counters and blue counters in the bag. number of red counters : number of blue counters = 1 : 2 Helen has to work out how many red counters are in the bag. She says, “There are 24 red counters in the bag because 1 is half of 2 and 24 is half of 48” Is Helen correct? You must give a reason for your answer. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (Total for Question 3 is 1 mark) *P75150A0428* D O N O T W RIT E IN T HIS A R E A D O N O T W RIT E IN T HIS A R E A D O N O T W RIT E IN T HIS A R E A DONOTWRITEINTHISAREADONOTWRITEINTHISAREADONOTWRITEINTHISAREA4 4 –2 n 5 n is an integer. (a) Write down the greatest possible value of n. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (1) (b) On the number line below, show the inequality –4 m 1 –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 m (2) (c) Solve 2 5 g – 4 6
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