MATH 110 Module 3 Exam
Find the answer to each of the following by first reducing the fractions as much as possible: a) P(850,4)= p(n,r) = n! / (n-r)! n = 850 r = 4 850 - 4 = 846 p(850, 4) = 850! / 846! 850x849x848x847 = 400 P(850,4) = 400 b) C(530,4)= c(n,r) = n! / r! (n-r)! n = 530 r = 4 530 - 4 = 526 c(530,4) = 530! / (4!)(526!) (530x529x528x527) / (4x3x2x1) = 20 / 24= 0 C(530,4) = 0 ................................................................................................CONTINUE
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