INP1501 ASSIMENT 2 MEMO
1. question1.cpp:
//Vending machine menu
#include <iostream>
#include <iomanip> using
namespace std;
int main()
{
int beverage, number; //define an integer variable
const float COFFEE = 15.00, TEA = 12.50, HOT_CHOCOLATE = 17.00, CAPPUCCINO = 22.50; float cost;
cout << "Please enter the choice of drink "
<< "(a number from 1 to 4 or 0 to quit) " << endl; cout
<< "Hot beverage menu" << endl << endl;
cout << "1: Coffee " << endl; cout
<< "2: Tea " << endl; cout << "3:
Hot Chocolate " << endl; cout << "4:
Cappuccino " << endl;
cout << "0: QUIT " << endl << endl << endl; cin >>
beverage;
while (beverage > 4 || beverage < 0)
{
cout << "Invalid choice - Please re-enter "; cin
>> beverage;
}
cout << "You have selected option number " << beverage << endl;
cout << "How many cups would you like? "; cin >> number;
cout.setf(ios::fixed); cout.precision(2);
switch(beverage)
{
case 1: cost = COFFEE * number;
cout << "The total cost is R" << cost << endl; break;
case 2: cost = TEA * number;
cout << "The total cost is R" << cost << endl; break;
case 3: cost = HOT_CHOCOLATE * number; cout
<< "The total cost is R" << cost << endl; break;
case 4: cost = CAPPUCCINO * number; cout
<< "The total cost is R" << cost << endl; break;
case 0: cout << "Please come again" << endl;
break; default:
cout << "Invalid selection"
<< "Try again please" << endl;
}
return 0;
}
,2. Question 2:
a. question2a.cpp:
//Convert for loop to while loop
//Loop must execute 10 times
//Add any variable initializitions that are deemed necessary
#include <iostream> using
namespace std;
int main()
{ int i, n; n =
10; i = 1;
while (i <= n)
{
cout << i; //Displays the amount of times the loop executes if (i
< 5 && i != 2)
cout << 'X'; //Displays X for everytime i is less than 5 and also not equal to 2 cout
<< endl;
i++;
}
return 0;
}
b. Question 2b:
, b.i. Explain what the output of the code will be: next = 2 , which initiates loop - while (next
<=5) { next++; product = product * next;}
1st while loop (next = 2): count is initialized (next++) next = 2 + 1 = 3, product = 1 * 3 =
3
2nd while loop (next = 3): count is initialized (next++) next =3 + 1 = 4, product = 3 * 4 =
12
3rd while loop (next = 4): count is initialized (next++) next = 4 + 1 = 5, product = 12 * 5 = 60
4th while loop (next = 5): count is initialized (next++) next = 5 + 1 =6, product = 60 * 6 =
360
5th while loop (Next = 6): loop terminates because condition is not met
What is the logical error?:
Program is written in such a way that it’s calculating the product of numbers 3 through
6
instead of 2 through 5.
b.ii. Make necessary changes to to fix the code so that it displays what it is intended to display:
Option A:
If you wish to keep next that it initializes count before product is calculated then you need
to:
- change next before the loop such that next = 1
- change the condition of the loop to while (next < 5)
question2b.cpp:
//Calculate the product of numbers 2 through 5
#include <iostream> using
namespace std; int main()
{
int next = 1, product = 1; while
(next < 5)
{
1. question1.cpp:
//Vending machine menu
#include <iostream>
#include <iomanip> using
namespace std;
int main()
{
int beverage, number; //define an integer variable
const float COFFEE = 15.00, TEA = 12.50, HOT_CHOCOLATE = 17.00, CAPPUCCINO = 22.50; float cost;
cout << "Please enter the choice of drink "
<< "(a number from 1 to 4 or 0 to quit) " << endl; cout
<< "Hot beverage menu" << endl << endl;
cout << "1: Coffee " << endl; cout
<< "2: Tea " << endl; cout << "3:
Hot Chocolate " << endl; cout << "4:
Cappuccino " << endl;
cout << "0: QUIT " << endl << endl << endl; cin >>
beverage;
while (beverage > 4 || beverage < 0)
{
cout << "Invalid choice - Please re-enter "; cin
>> beverage;
}
cout << "You have selected option number " << beverage << endl;
cout << "How many cups would you like? "; cin >> number;
cout.setf(ios::fixed); cout.precision(2);
switch(beverage)
{
case 1: cost = COFFEE * number;
cout << "The total cost is R" << cost << endl; break;
case 2: cost = TEA * number;
cout << "The total cost is R" << cost << endl; break;
case 3: cost = HOT_CHOCOLATE * number; cout
<< "The total cost is R" << cost << endl; break;
case 4: cost = CAPPUCCINO * number; cout
<< "The total cost is R" << cost << endl; break;
case 0: cout << "Please come again" << endl;
break; default:
cout << "Invalid selection"
<< "Try again please" << endl;
}
return 0;
}
,2. Question 2:
a. question2a.cpp:
//Convert for loop to while loop
//Loop must execute 10 times
//Add any variable initializitions that are deemed necessary
#include <iostream> using
namespace std;
int main()
{ int i, n; n =
10; i = 1;
while (i <= n)
{
cout << i; //Displays the amount of times the loop executes if (i
< 5 && i != 2)
cout << 'X'; //Displays X for everytime i is less than 5 and also not equal to 2 cout
<< endl;
i++;
}
return 0;
}
b. Question 2b:
, b.i. Explain what the output of the code will be: next = 2 , which initiates loop - while (next
<=5) { next++; product = product * next;}
1st while loop (next = 2): count is initialized (next++) next = 2 + 1 = 3, product = 1 * 3 =
3
2nd while loop (next = 3): count is initialized (next++) next =3 + 1 = 4, product = 3 * 4 =
12
3rd while loop (next = 4): count is initialized (next++) next = 4 + 1 = 5, product = 12 * 5 = 60
4th while loop (next = 5): count is initialized (next++) next = 5 + 1 =6, product = 60 * 6 =
360
5th while loop (Next = 6): loop terminates because condition is not met
What is the logical error?:
Program is written in such a way that it’s calculating the product of numbers 3 through
6
instead of 2 through 5.
b.ii. Make necessary changes to to fix the code so that it displays what it is intended to display:
Option A:
If you wish to keep next that it initializes count before product is calculated then you need
to:
- change next before the loop such that next = 1
- change the condition of the loop to while (next < 5)
question2b.cpp:
//Calculate the product of numbers 2 through 5
#include <iostream> using
namespace std; int main()
{
int next = 1, product = 1; while
(next < 5)
{
