geometry final exam
Final Exam Review -
Solutions
Geometry Matters
(University)
, lOMoARcPSD|10935195
)LQDO([DP5HYLHZ
1RWH
7KLVLVQRWPHDQWWREHDQH[KDXVWLYHOLVWRI WKHW\SHVRISUREOHPVWKDWPLJKW
DSSHDURQWKHH[DP 7KHVHSUREOHPVZHUHVHOHFWHGEHFDXVH WKH\DUHUHSUHVHQWDWLYHRIPDQ\RIWKH
ELJLGHDVZH¶YHFRYHUHGWKXVIDUDQGFDQWKHUHIRUHKHOS\RXLGHQWLI\WRSLFV\RXQHHGWRUHYLHZPRUHRI
,WLVDJRRGLGHDWRUHYLHZROGKRPHZRUNSUREOHPVFODVVH[HUFLVHVDQGSUHYLRXVH[DPVDVZHOO
)LOOLQWKHEODQNVEHORZZLWKWKHFRUUHFWWHUPLQRORJ\
EDVHGRQWKHGLDJUDPDWULJKW
D $QJOHDDQGDQJOHEDUHFRQJUXHQWEHFDXVHWKH\
DUHBBBBBBBBBBBBBBBBBBBBB
opposite angles
(a.k.a .
vertical angles)
E ,I/DQG0DUHSDUDOOHOWKH3DUDOOHO3RVWXODWHWHOOV
XVWKDWDQJOHEDQGDQJOHFDUHFRQJUXHQWEHFDXVH
WKH\DUHBBBBBBBBBBBBBBBBBBBBB
corresponding angles
F ,I/DQG0DUHSDUDOOHOWKH3DUDOOHO3RVWXODWHWHOOVXVWKDWDQJOHEDQGDQJOHGDUH
FRQJUXHQWEHFDXVHWKH\DUHBBBBBBBBBBBBBBBBBBBBB
alternate interior angles
/DQG0DUHSDUDOOHOOLQHV'HWHUPLQHWKHXQNQRZQDQJOHV%ULHIO\H[SODLQKRZ\RXIRXQGHDFK
DQJOH
109° =b
= a
71° 109°
64° 116° 109 __
116° 64°
710
WI 45°
=
135°
A and Z are alternate interior angles so 2- = 64° . Using
and fill all the other
opposite supplementary angles ,
we can
we
angles around 2- in .
Using opposite and supplementary angles ,
can fill in all the angles around b. Then 9=1090 ( corresponding
640+710 -1W 180°
angles There's triangle so or w -45 ? This
-
.
now a =
,
,
to 1800-450=135 ?
is supplementary ✗ so ✗ =
Downloaded by Abdra Sree ()
, lOMoARcPSD|10935195
7UXHRUIDOVH
DQJOHDDQGDQJOHEPXVWEHFRQJUXHQW,IWUXHKRZGR\RXNQRZ",IIDOVHZKDW
LQIRUPDWLRQZRXOGWHOO\RXWKDWWKHVHDUHFRQJUXHQW EHVLGHVDQJOHPHDVXUHPHQWV " 'RQRW
PDNHDVVXPSWLRQVDERXWWKHGLDJUDP
if
False ! They 'll only be congruent
the two lines are parallel .
:KDWLVWKHVXPRIWKHLQWHULRUDQJOHVRIWKHLUUHJXODUJRQEHORZ"<RXVKRXOGVXSSRUW\RXU
DQVZHUZLWKDSLFWXUHDQGQRWMXVWXVHDIRUPXOD
We can break the 7- gon up so that its
The
split across
5 triangles .
angles are
the
to 180°, so
angles
in each triangle sum
to 5.1800=9000
the 7- gon sum
in
angles
)LOOLQWKHEODQNVEHORZZLWKWKHPRVWDFFXUDWHZRUGSRVVLEOH
quadrilateral
D $SRO\JRQZLWKVLGHVLVFDOOHGDBBBBBBBBBBBBB
trapezoid
E $SRO\JRQZLWKVLGHVZLWKDWOHDVWRQHSDLURISDUDOOHOVLGHVLVDBBBBBBBBBBBBBBBB
F $SRO\JRQZLWKVLGHVZLWKWZRSDLUVRISDUDOOHOVLGHVLVDBBBBBBBBBBBBBBBB
parallelogram
G $SRO\JRQZLWKVLGHVWKDWDUHDOOFRQJUXHQWLVDBBBBBBBBBBBBBBBB
rhombus
H $SRO\JRQZLWKVLGHVWKDWKDVDOORILWVDQJOHVHTXDOLVDBBBBBBBBBBBBBBBB
rectangle
equilateral
I $SRO\JRQWKDWKDVDOORILWVVLGHVHTXDOLVFDOOHGD Q BBBBBBBBBBBBBBBBSRO\JRQ
J $SRO\JRQWKDWKDVDOORILWVDQJOHVHTXDOLVFDOOHGD Q BBBBBBBBBBBBBBBBSRO\JRQ
equiangular
K $SRO\JRQWKDWKDVDOORILWVVLGHVHTXDODQGDOORILWVDQJOHVHTXDOLVFDOOHGD Q
BBBBBBBBBBBBBBBBSRO\JRQ
regular
Downloaded by Abdra Sree ()
Final Exam Review -
Solutions
Geometry Matters
(University)
, lOMoARcPSD|10935195
)LQDO([DP5HYLHZ
1RWH
7KLVLVQRWPHDQWWREHDQH[KDXVWLYHOLVWRI WKHW\SHVRISUREOHPVWKDWPLJKW
DSSHDURQWKHH[DP 7KHVHSUREOHPVZHUHVHOHFWHGEHFDXVH WKH\DUHUHSUHVHQWDWLYHRIPDQ\RIWKH
ELJLGHDVZH¶YHFRYHUHGWKXVIDUDQGFDQWKHUHIRUHKHOS\RXLGHQWLI\WRSLFV\RXQHHGWRUHYLHZPRUHRI
,WLVDJRRGLGHDWRUHYLHZROGKRPHZRUNSUREOHPVFODVVH[HUFLVHVDQGSUHYLRXVH[DPVDVZHOO
)LOOLQWKHEODQNVEHORZZLWKWKHFRUUHFWWHUPLQRORJ\
EDVHGRQWKHGLDJUDPDWULJKW
D $QJOHDDQGDQJOHEDUHFRQJUXHQWEHFDXVHWKH\
DUHBBBBBBBBBBBBBBBBBBBBB
opposite angles
(a.k.a .
vertical angles)
E ,I/DQG0DUHSDUDOOHOWKH3DUDOOHO3RVWXODWHWHOOV
XVWKDWDQJOHEDQGDQJOHFDUHFRQJUXHQWEHFDXVH
WKH\DUHBBBBBBBBBBBBBBBBBBBBB
corresponding angles
F ,I/DQG0DUHSDUDOOHOWKH3DUDOOHO3RVWXODWHWHOOVXVWKDWDQJOHEDQGDQJOHGDUH
FRQJUXHQWEHFDXVHWKH\DUHBBBBBBBBBBBBBBBBBBBBB
alternate interior angles
/DQG0DUHSDUDOOHOOLQHV'HWHUPLQHWKHXQNQRZQDQJOHV%ULHIO\H[SODLQKRZ\RXIRXQGHDFK
DQJOH
109° =b
= a
71° 109°
64° 116° 109 __
116° 64°
710
WI 45°
=
135°
A and Z are alternate interior angles so 2- = 64° . Using
and fill all the other
opposite supplementary angles ,
we can
we
angles around 2- in .
Using opposite and supplementary angles ,
can fill in all the angles around b. Then 9=1090 ( corresponding
640+710 -1W 180°
angles There's triangle so or w -45 ? This
-
.
now a =
,
,
to 1800-450=135 ?
is supplementary ✗ so ✗ =
Downloaded by Abdra Sree ()
, lOMoARcPSD|10935195
7UXHRUIDOVH
DQJOHDDQGDQJOHEPXVWEHFRQJUXHQW,IWUXHKRZGR\RXNQRZ",IIDOVHZKDW
LQIRUPDWLRQZRXOGWHOO\RXWKDWWKHVHDUHFRQJUXHQW EHVLGHVDQJOHPHDVXUHPHQWV " 'RQRW
PDNHDVVXPSWLRQVDERXWWKHGLDJUDP
if
False ! They 'll only be congruent
the two lines are parallel .
:KDWLVWKHVXPRIWKHLQWHULRUDQJOHVRIWKHLUUHJXODUJRQEHORZ"<RXVKRXOGVXSSRUW\RXU
DQVZHUZLWKDSLFWXUHDQGQRWMXVWXVHDIRUPXOD
We can break the 7- gon up so that its
The
split across
5 triangles .
angles are
the
to 180°, so
angles
in each triangle sum
to 5.1800=9000
the 7- gon sum
in
angles
)LOOLQWKHEODQNVEHORZZLWKWKHPRVWDFFXUDWHZRUGSRVVLEOH
quadrilateral
D $SRO\JRQZLWKVLGHVLVFDOOHGDBBBBBBBBBBBBB
trapezoid
E $SRO\JRQZLWKVLGHVZLWKDWOHDVWRQHSDLURISDUDOOHOVLGHVLVDBBBBBBBBBBBBBBBB
F $SRO\JRQZLWKVLGHVZLWKWZRSDLUVRISDUDOOHOVLGHVLVDBBBBBBBBBBBBBBBB
parallelogram
G $SRO\JRQZLWKVLGHVWKDWDUHDOOFRQJUXHQWLVDBBBBBBBBBBBBBBBB
rhombus
H $SRO\JRQZLWKVLGHVWKDWKDVDOORILWVDQJOHVHTXDOLVDBBBBBBBBBBBBBBBB
rectangle
equilateral
I $SRO\JRQWKDWKDVDOORILWVVLGHVHTXDOLVFDOOHGD Q BBBBBBBBBBBBBBBBSRO\JRQ
J $SRO\JRQWKDWKDVDOORILWVDQJOHVHTXDOLVFDOOHGD Q BBBBBBBBBBBBBBBBSRO\JRQ
equiangular
K $SRO\JRQWKDWKDVDOORILWVVLGHVHTXDODQGDOORILWVDQJOHVHTXDOLVFDOOHGD Q
BBBBBBBBBBBBBBBBSRO\JRQ
regular
Downloaded by Abdra Sree ()