CHEM 103
CHEM 103 Question 1 Click this link to access the Periodic Table. This may be helpful throughout the exam. 1. Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0. Question 2 Click this link to access the Periodic Table. This may be helpful throughout the exam. Do the conversions shown below, showing all work: 1. 246oK = ? oC 2. 45oC = ? oF 3. 18oF = ? oK 1. 246oK - 273 = -27 oC oK → oC (make smaller) -273 2. 45oC x 1.8 + 32 = 113 oF oC → oF (make larger) x 1.8 + 32 3. 18oF - 32 ÷ 1.8 = -7.8 + 273 = 265.2 oK oF → oC → oK Question 3 Click this link to access the Periodic Table. This may be helpful throughout the exam. Show the calculation of the number of moles in the given amount of the following substances. Report your answer to 3 significant figures. 1. Moles = grams / molecular weight = 12.0 / 132.15 = 0.0908 mole 2. Moles = grams / molecular weight = 15.0 / 179.17 = 0.0837 mole
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