4/16/2021 Southern New Hampshire University - 7-2 Problem Set: Module Seven
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MAT-136-H7409 21EW4 Intro to Quantitative Analysis, 7-2 Problem Set: Module Seven
Briana Tattersall, 4/16/21 at 1:30:25 PM EDT
Question1: Score 6/6
Find the domain of the rational function.
x−1
f (x) =
x+3
Enter your answer in interval notation.
To enter ∞, type infinity. To enter ∪, type U.
Your response Correct response
(-infinity,-3)U(-3,infinity) (-infinity,-3) U (-3, infinity)
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
Begin by setting the denominator equal to zero and solving.
x + 3 = 0
x = −3
The denominator is equal to zero when x = −3 . The domain of the function is all real numbers
except x = −3 or (−∞, −3) ∪ (−3, ∞) .
Question2: Score 9/9
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, 4/16/2021 Southern New Hampshire University - 7-2 Problem Set: Module Seven
Find the domain, vertical asymptotes, and horizontal asymptotes of the function.
x
f (x) =
2
x −9
Enter the domain in interval notation.
To enter ∞, type infinity. To enter ∪, type U.
Domain:
Your response Correct response
(-infinity,-3)U(-3,3)U(3,infinity) (-infinity,-3)U(-3,3)U(3,infinity)
Auto graded Grade: 1/1.0
The fields below accept a list of numbers or formulas separated by semicolons (e.g. 2; 4; 6 or
x + 1; x − 1 ). The order of the lists do not matter.
Vertical asymptotes:
x =
Your response Correct response
-3;3 -3;3
Auto graded Grade: 1/1.0
Horizontal asymptotes:
y =
Your response Correct response
0 0
Auto graded Grade: 1/1.0
Total grade: 1.0×1/3 + 1.0×1/3 + 1.0×1/3 = 33% + 33% + 33%
Feedback:
First, factor the denominator.
https://snhu.mobius.cloud/modules/gradeProctoredTest.Login 2/11
[PRINT]
MAT-136-H7409 21EW4 Intro to Quantitative Analysis, 7-2 Problem Set: Module Seven
Briana Tattersall, 4/16/21 at 1:30:25 PM EDT
Question1: Score 6/6
Find the domain of the rational function.
x−1
f (x) =
x+3
Enter your answer in interval notation.
To enter ∞, type infinity. To enter ∪, type U.
Your response Correct response
(-infinity,-3)U(-3,infinity) (-infinity,-3) U (-3, infinity)
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
Begin by setting the denominator equal to zero and solving.
x + 3 = 0
x = −3
The denominator is equal to zero when x = −3 . The domain of the function is all real numbers
except x = −3 or (−∞, −3) ∪ (−3, ∞) .
Question2: Score 9/9
https://snhu.mobius.cloud/modules/gradeProctoredTest.Login 1/11
, 4/16/2021 Southern New Hampshire University - 7-2 Problem Set: Module Seven
Find the domain, vertical asymptotes, and horizontal asymptotes of the function.
x
f (x) =
2
x −9
Enter the domain in interval notation.
To enter ∞, type infinity. To enter ∪, type U.
Domain:
Your response Correct response
(-infinity,-3)U(-3,3)U(3,infinity) (-infinity,-3)U(-3,3)U(3,infinity)
Auto graded Grade: 1/1.0
The fields below accept a list of numbers or formulas separated by semicolons (e.g. 2; 4; 6 or
x + 1; x − 1 ). The order of the lists do not matter.
Vertical asymptotes:
x =
Your response Correct response
-3;3 -3;3
Auto graded Grade: 1/1.0
Horizontal asymptotes:
y =
Your response Correct response
0 0
Auto graded Grade: 1/1.0
Total grade: 1.0×1/3 + 1.0×1/3 + 1.0×1/3 = 33% + 33% + 33%
Feedback:
First, factor the denominator.
https://snhu.mobius.cloud/modules/gradeProctoredTest.Login 2/11
