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Relation and function

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It’s math notes containing detailed description of chapter relation and function.

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RElAtIoNs & FUnCtIoNs
LEcTuRe 1
A 1

b 2

C 3

d 4




A B




z Ith ke basics
muumuu


Two sets :
Input set , output set

t

Cartesian product of 2 sets is AXB →
output set

t

input
set

here element A maps to
each
of
element B
every of .




For Ln : I a

2 b A =L 1.2.34 ) s { 13123133443
3 c B -

-
Sa b. e3 ,
4,21 41,33
Y
B
A

A- XB is { (I ,
a ) ,
d. b 1,11 ,
c ) ,
( 2. a) 12 ,
b) ,
12 ,
c) ,(3. at ,( 3 b)
, ,
( 3. c) .




( Y at
, ,
4. b) 14,41


Now any subset of AXB is a Relation from A to B .




for En s
s cha ) ,
(2. a ) ,
( 3. all is a RELATION .

, •
In a relation ,
one input can have multiple outputs .




•
In a relation R in the form ( n , y) ,
n is element from input set &

y is from output set .




•
Also IM me
padha tha ki a relation is called a Function if input
has unique output .




'm
12 ke relation me hum A XA me Relations dekhen.ge .




And But
types of relations padhenge . use
peke knock basic questions bar eete hai -




Q, Set A is { 1,2 , 3 , 4 } & R & P are relations on AXA such that ,




R = ( ( 2,1 ) (2 , ,
1) ,
(1,2 ) ,
12,31 14 , 1) ,
/
P =
I ( 2,41 , 6,4 ) , 14 ,
I 1 , 4,213
which of these relations is a
function ? ?


Are In R ,
I is related to 1 & 2 ,
ie input 14 has 2 outputs 142 ie not

a function .




In P .
Each of the input 1,2 , 3,4 has only L output ,
ie P is a function .




*

Important :
If a relation defined on A XB , if the relations has more elements

than no .

of elements of A then ,
it CANNOT be a
function .




Par Kyun ? ?

Dekho A
input set hai .

Agar A me in elements hai to manimum

case me bhi agar Koi relation ho jisme Saare elements of A are



mapped &
function is created then only in pairs will enlist .




*
Q, How many number of relations can be defined from set A of m elements ?
d
AXA
A- No AXA
.


of relations = no .



of subsets of
No .


of elements in AXA = mxm = m2
Now ,
no .

of subsets = 2K ( where k = no .



of elements in that set )

So ,




It no .



of relations are possible .




Proof [No of .
subsets in a set ] : P = { a , .az . - .
an }


{ a } 1923 . .
.
.
. San } La .az } Ear 933 ,
.
. . .




n
"
Cn
"
C, subsets Cz
→ Moth C , th Cz th Cz .
. .




- { a , ,
Az 0373 .
. -




E )
,




→ 20h ' I '
h
Cz

Document information

School year
4
Uploaded on
March 7, 2022
Number of pages
10
Written in
2021/2022
Type
Interview
Company
Unknown
Person
Unknown
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