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Exam (elaborations)

Practice Paper with Mark Scheme: AQA A Level Biology 7402/01 (Paper 1)

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An original full-length 91-mark practice paper for AQA A Level Biology Paper 1, followed by a detailed mark scheme with worked answers, levels guidance and examiner tips. Independent practice material written by AcePapers; not an official AQA paper.

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Practice Paper: AQA A Level Biology 7402/01
(Paper 1)
Topics 1–4 with extended response questions

Question paper

Written by AcePapers


Independent practice paper written for revision. Not an official AQA paper and not
affiliated with or endorsed by AQA.



Time allowed: 2 hours Total: 91 marks


You will need
• A pen, a pencil, a ruler and a scientific calculator.

Instructions
• Answer every question, writing your answers in the lined spaces. You may not
need all of the lines.
• Show your working in calculations and give units where they are needed.
• Parts 04.2, 06.4 and 10.1 are extended response questions (15 marks in total).
Write in continuous, logically ordered prose.
• The mark for each part is printed in brackets. Plan your time with it.
• Organisms and data labelled fictional, invented or illustrative were made up for
this paper.

Name: ______________________________________ Date: ________________




Practice Paper 7402/01 (Paper 1) – Question paper Written by AcePapers | Page 1

, Question 01
Lipids and proteins are both polymers or are built from smaller units.
01.1 Name the bond that forms between glycerol and a fatty acid.
[1 mark]



01.2 Explain how phospholipids arrange themselves into a bilayer in water.
[2 marks]




01.3 Describe how you would test a food sample for the presence of lipid.
[2 marks]




01.4 Explain two ways in which triglycerides are suited to storing energy.
[2 marks]




01.5 Name the type of reaction that joins two amino acids, and the molecule
released.
[1 mark]



Question 01 total: 8 marks




Practice Paper 7402/01 (Paper 1) – Question paper Written by AcePapers | Page 2

, Question 02
Scientists measured the initial rate of an enzyme-controlled reaction at different
substrate concentrations, with no inhibitor, with inhibitor X and with inhibitor Y. The
concentration of enzyme was the same throughout. Table 1 shows the results.

Substrate concentration (mmol
1 2 4 8 16 32
dm−3)

Rate, no inhibitor (arbitrary units) 12 21 33 44 51 54

Rate with inhibitor X 5 9 16 26 38 50

Rate with inhibitor Y 6 11 17 22 26 27
Table 1 (invented data)


02.1 Which inhibitor is a competitive inhibitor? Explain your answer using Table 1.
[3 marks]




02.2 Explain how inhibitor Y reduces the rate of reaction.
[2 marks]




02.3 Calculate the percentage decrease in rate caused by inhibitor Y at a substrate
concentration of 8 mmol dm−3.
[2 marks]




Answer: ______________________ %
02.4 Explain why the rate with no inhibitor changes very little between 16 and 32
mmol dm−3.
[2 marks]




Practice Paper 7402/01 (Paper 1) – Question paper Written by AcePapers | Page 3

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Uploaded on
October 14, 2026
Number of pages
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Written in
2026/2027
Type
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