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NSG 530 Exam 1 | Advanced Pathophysiology – Wilkes | 2026/2027 Verified Questions & Answers | PDF

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INSTANT PDF DOWNLOAD — Verified NSG 530 Exam 1 | Advanced Pathophysiology | Wilkes University | Q & A | 100% Correct 2026/2027 Edition (PDF). Features actual exam questions, cellular adaptation (hypertrophy, hyperplasia, dysplasia, metaplasia), cellular injury mechanisms, oxidative stress, apoptosis vs. necrosis, genetic inheritance patterns (autosomal dominant/recessive, X-linked), fluid and electrolyte imbalances (hyponatremia, hyperkalemia), and acid-base disturbances (metabolic vs. respiratory acidosis/alkalosis with compensation) with detailed pathophysiological rationales. Guaranteed 100% correctness. Ideal for NSG 530 Exam 1 PDF, Wilkes University Graduate Nursing Test Bank, and Verified Answers.

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, NSG 530 EXAM 1
Advanced Pathophysiology
Wilkes University
100-Question Practice Examination
2026/2027 Edition

1. A skeletal muscle cell exposed to sustained workload enlarges without increasing cell number. Which
adaptation best explains this response?
A) Hyperplasia
B) Metaplasia
C) Dysplasia
D) Hypertrophy

Correct Answer: Hypertrophy
Rationale: Hypertrophy is an increase in individual cell size caused by increased synthesis of structural proteins
and organelles. It is typical in tissues with limited proliferative capacity, such as skeletal and cardiac muscle.
Hyperplasia increases cell number, whereas metaplasia and dysplasia describe changes in cell phenotype or
organization rather than simple enlargement.
2. Endometrial tissue increases in cell number in response to estrogenic stimulation. This change is
classified as which cellular adaptation?
A) Hyperplasia
B) Hypertrophy
C) Atrophy
D) Metaplasia

Correct Answer: Hyperplasia
Rationale: Hyperplasia reflects an increase in the number of cells in a tissue and occurs when cells retain the
capacity to divide. Hormonal stimulation can produce physiologic or pathologic hyperplasia. Hypertrophy enlarges
existing cells, atrophy reduces cell size or number, and metaplasia substitutes one differentiated cell type for
another.
3. A smoker develops replacement of normal ciliated columnar bronchial epithelium by stratified
squamous epithelium. What process has occurred?
A) Dysplasia
B) Anaplasia
C) Metaplasia
D) Hyperplasia

Correct Answer: Metaplasia
Rationale: Metaplasia is a reversible adaptive substitution of one mature cell type by another better able to
tolerate chronic stress. In smokers, squamous cells resist irritation but sacrifice mucociliary function. Dysplasia
involves disordered growth, anaplasia denotes loss of differentiation, and hyperplasia increases the number of
cells without changing their mature lineage.
4. During prolonged immobilization, a limb muscle decreases in size and strength. Which mechanism
contributes most directly?
A) Persistent mitochondrial biogenesis



NSG 530 Exam 1 | Practice Examination | 2026/2027 Edition | Page 1

, B) Increased DNA replication
C) Sustained cellular edema
D) Increased protein degradation with reduced protein synthesis

Correct Answer: Increased protein degradation with reduced protein synthesis
Rationale: Disuse atrophy develops when protein synthesis falls and proteolysis increases, often through
ubiquitin-proteasome and autophagic pathways. The result is smaller cells and reduced functional capacity.
Mitochondrial biogenesis and DNA replication would not explain shrinkage, while transient cellular edema causes
swelling rather than loss of mass.
5. Loss of ATP during ischemia most immediately impairs which membrane process?
A) Na+/K+-ATPase activity
B) Passive oxygen diffusion
C) Steroid hormone transport
D) Aquaporin expression

Correct Answer: Na+/K+-ATPase activity
Rationale: ATP depletion quickly disables energy-dependent ion pumps, especially the sodium-potassium
ATPase. Sodium and water then accumulate intracellularly, producing cellular swelling, while potassium leaks out.
Passive diffusion does not require ATP, and altered aquaporin expression or steroid transport is not the earliest
mechanism responsible for ischemic swelling.
6. A myocardial cell becomes swollen after brief hypoxia but recovers when oxygen is restored. This
finding is most consistent with what type of injury?
A) Reversible cellular injury
B) Coagulative necrosis
C) Apoptosis
D) Liquefactive necrosis

Correct Answer: Reversible cellular injury
Rationale: Early hypoxic injury can be reversible when ATP production and membrane ion gradients are restored
before irreversible membrane and mitochondrial damage occurs. Cellular swelling is a classic early manifestation.
Necrosis denotes irreversible injury with membrane disruption, whereas apoptosis is a regulated form of cell death
rather than transient hypoxic dysfunction.
7. Which intracellular change is most characteristic of irreversible cell injury?
A) Temporary ribosomal detachment
B) Inability to reverse mitochondrial dysfunction
C) Mild cellular swelling
D) Transient glycogen depletion

Correct Answer: Inability to reverse mitochondrial dysfunction
Rationale: Irreversible injury is marked by failure to restore mitochondrial function and severe membrane
damage. Once oxidative phosphorylation cannot recover, ATP depletion becomes critical and destructive
pathways accelerate. Ribosomal detachment, glycogen loss, and cellular swelling can occur during reversible
injury and may resolve if the stressor is removed promptly.
8. A patient with an acute myocardial infarction develops death of cardiac myocytes in the affected region.
Which pattern of necrosis is expected?
A) Coagulative necrosis
B) Liquefactive necrosis

NSG 530 Exam 1 | Practice Examination | 2026/2027 Edition | Page 2

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