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BIO 325 Final Exam Review Questions and Answers Graded A+ 2026

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Ribosomal genes are transcribed by RNA Polymerase ___ -Correct Answer -I In Prokaryotes, cluster of genes can be regulated together. This cluster of genes is called an ____ -Correct Answer -operon E. coli's heat shock response is controlled by alternative ______ factors that recognize different promoter sequences. -Correct Answer -sigma "Certain covalent modifications of Histone can dictate the fate of gene expression at given loci" is referred as _____ _____ hypothesis. -Correct Answer -Histone Code p53 can induce programmed cell death if the damage cannot be repaired through a process called ______ . -Correct Answer -apoptosis Generally speaking, cancer is due to abnormal or uncontrolled _____ division -Correct Answer -cell XXY male would have ____ Barr body(ies) -Correct Answer -1 In an old view of heredity, __________ inheritance assumes that parental traits become mixed and forever changed in offspring. -Correct Answer -blending A short single-stranded piece of DNA that is labeled and used in hybridization experiments is called a(n) ________ -Correct Answer -probe T/F: Genotype frequency can change until the population comes to equilibrium. -Correct Answer -True T/F: Trimethylation at Histone H3 Lys 27 usually associated with transcriptionally repressed chromatins -Correct Answer -True T/F: After meiosis I, chromosome set number is n. -Correct Answer -True T/F: High concentration of Glucose is necessary for the maximum induction of Lac operon genes. -Correct Answer -False T/F: A man with blood type "A," whose father was blood type "O," married a woman of blood type "B" whose mother was blood type "O." Children of this couple can have all possible blood types -Correct Answer -True T/F: HIV contains reverse transcriptase. -Correct Answer -True T/F: cDNAs from eukaryotic organisms contain promoter region. -Correct Answer -False T/F: The map of a chromosome interval is A--10 m.u.--B-- 40 m.u.--C. From the cross Abc/aBC × abc/abc, you observed 10 double crossovers from 1000 progeny. In this case, interference is 0.5 -Correct Answer -False T/F: Population at Hardy-Weinberg equilibrium assumes that there is no new mutation over generations. -Correct Answer -True T/F: Nimblegen array uses photo-activating building blocks to construct DNA array on the slide. -Correct Answer -True If grandparents are heterozygous for the trait, what is the probability that a child in question would NOT have the trait (disease). A. 1/4 B. 3/4 C. 1/3 D. 2/3 -Correct Answer -D (2/3)

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BIO 325 Final Exam Review Questions
and Answers Graded A+ 2026
Ribosomal genes are transcribed by RNA Polymerase ___ -Correct Answer ✔-I

In Prokaryotes, cluster of genes can be regulated together. This cluster of genes is
called an ____ -Correct Answer ✔-operon

E. coli's heat shock response is controlled by alternative ______ factors that
recognize different promoter sequences. -Correct Answer ✔-sigma

"Certain covalent modifications of Histone can dictate the fate of gene expression
at given loci" is referred as _____ _____ hypothesis. -Correct Answer ✔-Histone
Code

p53 can induce programmed cell death if the damage cannot be repaired through
a process called ______ . -Correct Answer ✔-apoptosis

Generally speaking, cancer is due to abnormal or uncontrolled _____ division -
Correct Answer ✔-cell

XXY male would have ____ Barr body(ies) -Correct Answer ✔-1

In an old view of heredity, __________ inheritance assumes that parental traits
become mixed and forever changed in offspring. -Correct Answer ✔-blending

A short single-stranded piece of DNA that is labeled and used in hybridization
experiments is called a(n) ________ -Correct Answer ✔-probe

T/F: Genotype frequency can change until the population comes to equilibrium. -
Correct Answer ✔-True

,T/F: Trimethylation at Histone H3 Lys 27 usually associated with transcriptionally
repressed chromatins -Correct Answer ✔-True

T/F: After meiosis I, chromosome set number is n. -Correct Answer ✔-True

T/F: High concentration of Glucose is necessary for the maximum induction of Lac
operon genes. -Correct Answer ✔-False

T/F: A man with blood type "A," whose father was blood type "O," married a
woman of blood type "B" whose mother was blood type "O." Children of this
couple can have all possible blood types -Correct Answer ✔-True

T/F: HIV contains reverse transcriptase. -Correct Answer ✔-True

T/F: cDNAs from eukaryotic organisms contain promoter region. -Correct Answer
✔-False

T/F: The map of a chromosome interval is A--10 m.u.--B-- 40 m.u.--C. From the
cross Abc/aBC × abc/abc, you observed 10 double crossovers from 1000 progeny.
In this case, interference is 0.5 -Correct Answer ✔-False

T/F: Population at Hardy-Weinberg equilibrium assumes that there is no new
mutation over generations. -Correct Answer ✔-True

T/F: Nimblegen array uses photo-activating building blocks to construct DNA array
on the slide. -Correct Answer ✔-True

If grandparents are heterozygous for the trait, what is the probability that a child
in question would NOT have the trait (disease).
A. 1/4
B. 3/4
C. 1/3
D. 2/3 -Correct Answer ✔-D (2/3)

, What technique would be used to best study a phenocopy?
A. RNAi
B. Transgene
C. Isolation of mutations
D. QTL mapping analysis
E. Microarray -Correct Answer ✔-A (RNAi)

In eukaryotes, transcriptional activity is low when:
A. DNA is hypermethylated.
B. Histone is hyperacetylated.
C. Histone H3 Lys 4 is methylated. D. Histone H3 Lys 36 is methylated E. none of
the above. -Correct Answer ✔-A (DNA is hypermethylated)

Which of the following is property of Enhancer?
A. it is one of tran-acting components in gene regulation. B. it is always located
immediate 5' end of a gene.
C. it is always located immediate 3' end of a gene.
D. its orientation is not important. -Correct Answer ✔-D (its orientation is not
important)

The Rb activity is regulated by
A. its phosphorylation state.
B. its methylation level
C. cyclin A.
D. E2F
E. its polyA tail. -Correct Answer ✔-A (its phosphorylation state)

In humans, brachydactyly is a dominant condition. Six thousand four hundred
people in a population of 10,000 show the disease (1,600 are BB, 4,800 are Bb)
and 3,600 are normal phenotypes (bb). The frequency of the b allele is
A. 0.6
B. 0.4
C. 0.36
D. 0.48

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