UT AUSTIN GENERAL
CHEMISTRY I MIDTERM EXAM
2026
150 Questions with Answers and Detailed Rationales
100 PERCENT GUARANTEED PASS
INSTANT DOWNLOAD ANSWERS INCLUDED
IMPORTANCE OF THIS DOCUMENT
This comprehensive examination preparation guide has been meticulously developed to help you succeed in the
UT AUSTIN GENERAL CHEMISTRY I MIDTERM EXAM 2026. It contains 150 carefully selected questions that
reflect the most current exam content and testing strategies. Each question is accompanied by a correct answer
and a detailed rationale that explains the underlying pathophysiology, pharmacology, or clinical reasoning.
Self-Assessment – Test your knowledge and Exam Preparation – Familiarize yourself with the
identify areas requiring further question format and content
study areas
Concept Reinforcement – Deepen your Confidence Building – Develop test-taking
understanding through strategies and reduce
evidence-based exam anxiety
rationales
Time Management – Practice answering
questions under simulated
exam conditions
Review Summary 150 Questions
Foundations - Application - UT Austin General Chemistry I 2026 Chemistry Undergraduate YEAR 1
General Chemistry I
All answers with rationales
,Table of Contents
Content Area Questions Key Topics
Atomic Structure AND 1-25 Reaction, Sample, Polar, Quantum Numbers, Electron
Periodicity
Chemical Bonding AND 26-50 Reaction, Electron, Point, Sample, First
Molecular Geometry
Stoichiometry AND Chemical 51-75 Reaction, Polar, Temperature, Electron, Sample
Reactions
Gases AND GAS LAWS 76-100 Reaction, Sample, Correctly, Constant, Polar
Thermochemistry AND 101-125 Reaction, Sample, Temperature, Correctly, Quantum Numbers
Thermodynamics
Solutions AND Colligative 126-150 Reaction, Point, Sample, Doubling, Titrated
Properties
TOTAL 150 All questions include answers and detailed rationales
,Section A - Atomic Structure AND Periodicity
Q1.
The quantum numbers for the outermost electron in an atom are n=4, l=1, ml=0, ms=+1/2.
Which element is this?
A. Gallium (Ga) B. Germanium (Ge)
C. Arsenic (As) D. Selenium (Se)
Correct: A - Gallium (Ga)
Rationale:The quantum numbers indicate a 4p electron with one electron in the 4p subshell
(ml=0, ms=+1/2). The electron configuration ends in 4p1, which corresponds to gallium (Ga).
Germanium has two 4p electrons, arsenic three, and selenium four.
Why the other answers are wrong:
B. Germanium has two electrons in the 4p subshell, so its outermost electron would have a
different set of quantum numbers.
C. Arsenic has three electrons in the 4p subshell, so the given quantum numbers do not match
its outermost electron.
D. Selenium has four electrons in the 4p subshell, so the given quantum numbers do not match
its outermost electron.
Reference: Brown, T.L. et al. (2022). Chemistry: The Central Science, 15th Ed., Ch. 6
Q2.
A 25.0 mL sample of 0.100 M HCl is titrated with 0.100 M NaOH. What is the pH after 25.0
mL of NaOH have been added?
A. 1.00 B. 7.00
C. 12.00 D. 2.00
Correct: B - 7.00
Rationale:At the equivalence point, equal moles of HCl and NaOH have reacted, producing
NaCl and water. The resulting solution is neutral, so the pH is 7.00 at 25°C.
Why the other answers are wrong:
A. A pH of 1.00 would be expected before any NaOH is added, not after neutralization.
C. A pH of 12.00 would result if excess NaOH were present, but here the acid and base are
stoichiometrically equivalent.
D. A pH of 2.00 would indicate an acidic solution, but neutralization has occurred.
Reference: Zumdahl, S.S. & Zumdahl, S.A. (2020). Chemistry, 10th Ed., Ch. 15
Page 3
, Section A - Atomic Structure AND Periodicity
Q3.
Which of the following molecules is polar?
A. CO2 B. BF3
C. CH2Cl2 D. CCl4
Correct: C - CH2Cl2
Rationale:CH2Cl2 has a tetrahedral geometry with two different types of substituents (H and
Cl), so the bond dipoles do not cancel, resulting in a net dipole moment. CO2, BF3, and CCl4
are symmetrical and nonpolar.
Why the other answers are wrong:
A. CO2 is linear and the two C=O bond dipoles cancel, making it nonpolar.
B. BF3 is trigonal planar and the three B-F bond dipoles cancel, making it nonpolar.
D. CCl4 is tetrahedral with four identical Cl atoms, so the bond dipoles cancel, making it
nonpolar.
Reference: Petrucci, R.H. et al. (2017). General Chemistry: Principles and Modern Applications, 11th
Ed., Ch. 10
Q4.
Given the following data: N2(g) + O2(g) -> 2 NO(g) H = +180.5 kJ; 2 NO(g) + O2(g) -> 2
NO2(g) H = -114.1 kJ. What is H for the reaction N2(g) + 2 O2(g) -> 2 NO2(g)?
A. +66.4 kJ B. -66.4 kJ
C. +294.6 kJ D. -294.6 kJ
Correct: A - +66.4 kJ
Rationale:Adding the two reactions gives N2(g) + 2 O2(g) !’ 2 NO2(g). The enthalpy change
is the sum: (+180.5 kJ) + (-114.1 kJ) = +66.4 kJ. Thus, H = +66.4 kJ.
Why the other answers are wrong:
B. The sign is incorrect; the sum of the enthalpies is positive.
C. This would be the sum if the second reaction were reversed, but it is not.
D. This would be the sum if both reactions were reversed and the second had a positive sign.
Reference: Atkins, P. & Jones, L. (2018). Chemical Principles: The Quest for Insight, 7th Ed., Ch. 6
Q5.
A sample of an ideal gas occupies 2.00 L at 1.00 atm and 300 K. What volume will it
occupy at 2.00 atm and 600 K?
A. 1.00 L B. 2.00 L
Page 4
CHEMISTRY I MIDTERM EXAM
2026
150 Questions with Answers and Detailed Rationales
100 PERCENT GUARANTEED PASS
INSTANT DOWNLOAD ANSWERS INCLUDED
IMPORTANCE OF THIS DOCUMENT
This comprehensive examination preparation guide has been meticulously developed to help you succeed in the
UT AUSTIN GENERAL CHEMISTRY I MIDTERM EXAM 2026. It contains 150 carefully selected questions that
reflect the most current exam content and testing strategies. Each question is accompanied by a correct answer
and a detailed rationale that explains the underlying pathophysiology, pharmacology, or clinical reasoning.
Self-Assessment – Test your knowledge and Exam Preparation – Familiarize yourself with the
identify areas requiring further question format and content
study areas
Concept Reinforcement – Deepen your Confidence Building – Develop test-taking
understanding through strategies and reduce
evidence-based exam anxiety
rationales
Time Management – Practice answering
questions under simulated
exam conditions
Review Summary 150 Questions
Foundations - Application - UT Austin General Chemistry I 2026 Chemistry Undergraduate YEAR 1
General Chemistry I
All answers with rationales
,Table of Contents
Content Area Questions Key Topics
Atomic Structure AND 1-25 Reaction, Sample, Polar, Quantum Numbers, Electron
Periodicity
Chemical Bonding AND 26-50 Reaction, Electron, Point, Sample, First
Molecular Geometry
Stoichiometry AND Chemical 51-75 Reaction, Polar, Temperature, Electron, Sample
Reactions
Gases AND GAS LAWS 76-100 Reaction, Sample, Correctly, Constant, Polar
Thermochemistry AND 101-125 Reaction, Sample, Temperature, Correctly, Quantum Numbers
Thermodynamics
Solutions AND Colligative 126-150 Reaction, Point, Sample, Doubling, Titrated
Properties
TOTAL 150 All questions include answers and detailed rationales
,Section A - Atomic Structure AND Periodicity
Q1.
The quantum numbers for the outermost electron in an atom are n=4, l=1, ml=0, ms=+1/2.
Which element is this?
A. Gallium (Ga) B. Germanium (Ge)
C. Arsenic (As) D. Selenium (Se)
Correct: A - Gallium (Ga)
Rationale:The quantum numbers indicate a 4p electron with one electron in the 4p subshell
(ml=0, ms=+1/2). The electron configuration ends in 4p1, which corresponds to gallium (Ga).
Germanium has two 4p electrons, arsenic three, and selenium four.
Why the other answers are wrong:
B. Germanium has two electrons in the 4p subshell, so its outermost electron would have a
different set of quantum numbers.
C. Arsenic has three electrons in the 4p subshell, so the given quantum numbers do not match
its outermost electron.
D. Selenium has four electrons in the 4p subshell, so the given quantum numbers do not match
its outermost electron.
Reference: Brown, T.L. et al. (2022). Chemistry: The Central Science, 15th Ed., Ch. 6
Q2.
A 25.0 mL sample of 0.100 M HCl is titrated with 0.100 M NaOH. What is the pH after 25.0
mL of NaOH have been added?
A. 1.00 B. 7.00
C. 12.00 D. 2.00
Correct: B - 7.00
Rationale:At the equivalence point, equal moles of HCl and NaOH have reacted, producing
NaCl and water. The resulting solution is neutral, so the pH is 7.00 at 25°C.
Why the other answers are wrong:
A. A pH of 1.00 would be expected before any NaOH is added, not after neutralization.
C. A pH of 12.00 would result if excess NaOH were present, but here the acid and base are
stoichiometrically equivalent.
D. A pH of 2.00 would indicate an acidic solution, but neutralization has occurred.
Reference: Zumdahl, S.S. & Zumdahl, S.A. (2020). Chemistry, 10th Ed., Ch. 15
Page 3
, Section A - Atomic Structure AND Periodicity
Q3.
Which of the following molecules is polar?
A. CO2 B. BF3
C. CH2Cl2 D. CCl4
Correct: C - CH2Cl2
Rationale:CH2Cl2 has a tetrahedral geometry with two different types of substituents (H and
Cl), so the bond dipoles do not cancel, resulting in a net dipole moment. CO2, BF3, and CCl4
are symmetrical and nonpolar.
Why the other answers are wrong:
A. CO2 is linear and the two C=O bond dipoles cancel, making it nonpolar.
B. BF3 is trigonal planar and the three B-F bond dipoles cancel, making it nonpolar.
D. CCl4 is tetrahedral with four identical Cl atoms, so the bond dipoles cancel, making it
nonpolar.
Reference: Petrucci, R.H. et al. (2017). General Chemistry: Principles and Modern Applications, 11th
Ed., Ch. 10
Q4.
Given the following data: N2(g) + O2(g) -> 2 NO(g) H = +180.5 kJ; 2 NO(g) + O2(g) -> 2
NO2(g) H = -114.1 kJ. What is H for the reaction N2(g) + 2 O2(g) -> 2 NO2(g)?
A. +66.4 kJ B. -66.4 kJ
C. +294.6 kJ D. -294.6 kJ
Correct: A - +66.4 kJ
Rationale:Adding the two reactions gives N2(g) + 2 O2(g) !’ 2 NO2(g). The enthalpy change
is the sum: (+180.5 kJ) + (-114.1 kJ) = +66.4 kJ. Thus, H = +66.4 kJ.
Why the other answers are wrong:
B. The sign is incorrect; the sum of the enthalpies is positive.
C. This would be the sum if the second reaction were reversed, but it is not.
D. This would be the sum if both reactions were reversed and the second had a positive sign.
Reference: Atkins, P. & Jones, L. (2018). Chemical Principles: The Quest for Insight, 7th Ed., Ch. 6
Q5.
A sample of an ideal gas occupies 2.00 L at 1.00 atm and 300 K. What volume will it
occupy at 2.00 atm and 600 K?
A. 1.00 L B. 2.00 L
Page 4
