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Physics 1 - Test 3 (Torque & Equilibrium) | Questions and Answers | 2026/27 Update | 100% Correct Graded + The torque applied to the wrench is the force exerted at the end with a perpendicular component at an unknown angle that when multiplied by 0.
Preview 2 out of 10 pages
Physics 1 - Test 3 (Torque & Equilibrium) | Questions and Answers | 2026/27 Update | 100% Correct Graded + The torque applied to the wrench is the force exerted at the end with a perpendicular component at an unknown angle that when multiplied by 0.32 m will provide 15 Nm of torque. In this case, the perpendicular component is the sine of angle. Therefore, 15 Nm = (95 N) (sin(Θ)) (0.32 m). Solving for Θ we get, sin(Θ) = 15 Nm / (95 N) (0.32 m) [Notice that the units cancel out as they should]. sin(Θ) = 15 / 30.4 = 0.4934. Θ = arcsin(0.4934) = 29.56 = 30° Torque: A 95-N force exerted at the en
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