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MAT 251 Benchmark 2 Checkpoints 1-2; Attempt review With a complete solution Updated RATED A+

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MAT 251 Benchmark 2 Checkpoints 1-2; Attempt review With a complete solution Updated RATED A+

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MAT 251 Benchmark 2: Checkpoints 1-2; Attempt
review With a complete solution Updated RATED A+
NEW EDITION Straighterline


SECTION A: UNDERSTANDING STRAIGHTERLINE ASSESSMENTS




Benchmarks test mastery of course concepts. You have 3 attempts, and your
highest score counts. Checkpoints are quick knowledge checks on important course
concepts. All are open-book, and most have 1-3 attempts [citation:6].




SECTION B: RELATED RATES – VOLUME PROBLEMS




QUESTION 1

The volume of a spherical balloon is increasing at a constant rate of 3 m³/s. At
which of the following rates is the radius of the balloon increasing at the instant its
radius is 2 meters? [citation:1]



A) 3/(8π) m/s

B) 9/(8π) m/s


1

,C) 7/(16π) m/s

D) 3/(16π) m/s



Correct Answer: D


Solution:

Volume of a sphere: V = (4/3)πr³

Given dV/dt = 3 m³/s, r = 2 m



Differentiate implicitly:

dV/dt = 4πr²(dr/dt)



Solve for dr/dt:

dr/dt = (dV/dt) / (4πr²)

dr/dt = 3 / (4π × 2²)

dr/dt = 3 / (16π) m/s




SECTION C: DERIVATIVES – QUOTIENT RULE




2

,QUESTION 2

Find the derivative of y = (x² + 1) / (x² - 1). [citation:1]



A) -4x / (x² - 1)²

B) 4x³ / (x² - 1)²

C) 4x / (x² - 1)²

D) 4x⁴ / (x² - 1)²



Correct Answer: A


Solution:

Using the quotient rule: (u/v)' = (u'v - uv') / v²

u = x² + 1, u' = 2x

v = x² - 1, v' = 2x



y' = [2x(x² - 1) - (x² + 1)(2x)] / (x² - 1)²

y' = [2x³ - 2x - 2x³ - 2x] / (x² - 1)²

y' = -4x / (x² - 1)²




3

, SECTION D: OPTIMIZATION – MAXIMUM DEFLECTION




QUESTION 3

The deflection of a hardwood beam of length L is given by:

D(x) = (9/4)x⁴ - 7Lx³ + 5L²x²

where x is the distance from the fixed end of the beam. Which of the following
values of x yields the maximum deflection? [citation:1]



A) 2L/3

B) 5L/3

C) 2L/3 and 5L/3

D) L



Correct Answer: C


Solution:

Find critical points by taking derivative and setting to zero:

D'(x) = 9x³ - 21Lx² + 10L²x

D'(x) = x(9x² - 21Lx + 10L²)




4

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