A 120/240 V, 1-phase dwelling has a calculated load of 98 A. Using the NEC
optional method, what is the minimum copper THWN service-entrance
conductor size (75°C column) permitted?
A. 1/0 AWG
B. 2 AWG
C. 3 AWG
D. 4 AWG
Correct Answer: B - 2 AWG
RATIONALE
For 98 A, the next standard OCPD is 100 A. Table 310.16 (75°C,
copper) permits 2 AWG at 115 A, but 3 AWG is only 100 A - however
3 AWG is not permitted for 100 A service because 240.4(D) limits
small conductors; 2 AWG is the minimum. Options A and C are either
oversized or disallowed by 240.4(D), and 4 AWG is rated only 85 A,
insufficient.
Question 2
A Utah licensed electrical contractor signs a contract but the owner refuses to
pay. Under Utah's mechanics' lien statute, what is the deadline to file a lien for
a commercial project?
A. Within 90 days after completion of the contract
B. Within 180 days after completion of the contract
C. Within 90 days after the last day of work
D. Within 180 days after the last day of work
Correct Answer: A - Within 90 days after completion of the
contract
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, RATIONALE
Utah Code §38-1-7a requires a commercial lien to be filed within 90
days after completion of the contract, not after last work. Option C is a
common confusion with residential notice rules; 180-day periods
apply to other states or to residential pre-lien notices, not Utah
commercial liens.
Question 3
A 3-phase, 480 V delta system supplies a 75 kVA continuous load at 0.85
power factor. What is the minimum standard ampere rating of the disconnect
switch?
A. 100 A
B. 110 A
C. 125 A
D. 150 A
Correct Answer: C - 125 A
RATIONALE
Line current = 75,000 / (1.732 × 480 × 0.85) 106 A. Continuous load
requires 125% (106 × 1.25 = 132.5 A), so the next standard size is 150
A, but 240.4(B) permits the next higher standard OCPD only if the
conductor ampacity is sufficient; the disconnect must be rated at least
125% of the continuous load, so 125 A is the minimum standard size
that meets 125% of 106 A? Actually 106 × 1.25 = 132.5 A, so 150 A
is required. However, if the load is not continuous, 125 A suffices.
The question states continuous, so 150 A is correct. Wait - the correct
answer is 150 A, but the options list 125 A as C. Recalculating: 106 A
× 1.25 = 132.5 A, next standard is 150 A. So correct is D. The
explanation should reflect that. Let me correct: correct is D (150 A).
The distractors are 100 A (insufficient), 110 A (insufficient), 125 A
(insufficient for continuous).
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, Question 4
In a health care facility, which of the following wiring methods is permitted in
a patient care area for a critical branch circuit?
A. Type AC cable with an insulated equipment grounding conductor
B. Rigid metal conduit (RMC)
C. Electrical nonmetallic tubing (ENT) encased in 2 in. of concrete
D. Type MC cable with a green insulated equipment grounding conductor
Correct Answer: B - Rigid metal conduit (RMC)
RATIONALE
NEC 517.30(C)(3) permits RMC, IMC, and EMT for critical branch
circuits in patient care areas. AC cable is not permitted unless it has an
insulated grounding conductor and is listed for the purpose; ENT is
not permitted in patient care areas unless encased in at least 2 in. of
concrete, but that exception applies to certain areas only, not critical
branch. MC cable with green insulated conductor is permitted only if
it is a listed hospital-grade MC, but the question asks for a method that
is always permitted; RMC is the definitive answer.
Question 5
A 25 hp, 460 V, 3-phase motor has a nameplate FLA of 34 A. What is the
minimum ampacity of the branch-circuit conductors?
A. 34 A
B. 42.5 A
C. 53 A
D. 34 A × 1.25 = 42.5 A, then sized to 125% of 34 A = 42.5 A, but Table
430.250 for 25 hp at 460 V gives 34 A, so conductors must be 125% of
34 A = 42.5 A, next standard size 45 A? Actually 430.22 requires 125%
of FLC from Table 430.250, which is 34 A × 1.25 = 42.5 A. The
minimum conductor ampacity is 42.5 A, but standard sizes are 40 A and
45 A; 40 A is insufficient, so 45 A. However, the question asks for
minimum ampacity, which is 42.5 A. The options are 34 A, 42.5 A, 53 A,
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