Chemistry: The Molecular Nature of Matter and Change 3rd Edition by Martin Silberberg Test Bank | 2026

martin
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Chemistry
silberberg the
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molecular nature of matter and change 3rd ce edition by martin silberberg tbChemistr



Student name:__________
-3
1) Which of the following correctly shows how to convert a density of 20.1 g cm to units
of kg m -3?



A)

B)

C)

D)

E)




2) Which one of the following numbers contains a digit or digits which is/are not
significant?


A) 970.0
B) 502
C) .300
D) .0043
E) 20.01




3) A car tire is rated for 34.0 psi (pounds per square inch). The pressure gauge used only
reports pressure in kPa (kilopascal). Given that 1 psi = 6895 Pa, calculate the tire rating in kPa.


A) 234 kPa
B) 101 kPa
C) 652 kPa
D) 89.1 kPa
E) 760 kPa




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natureChemistry
of matterthe
andmolecular
change 3rd
nature
ce edition
of matter
by martin
and change
silberberg
3rd ce
tb!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!~~~~~~~~~~~~
edition by martin silberberg tb!!!!!!!!!!!

,martin
~~~&&&&&&&&############################@@@@@@@@@@@@@@@@22/2026//2027
Chemistry
silberberg the
tb!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~&&&&&&&&#########
molecular nature of matter and change 3rd ce edition by martin silberberg tbChemistr




4) The result of (3.8621 × 1.5630) - 5.98 is properly written as


A) 0.06
B) 0.056
C) 0.0565
D) 0.05646
E) 0.056462




3
5) Given that 1 inch = 2.54 cm, 1 cm is equal to


A) 16.4 in 3
B) 6.45 in 3
C) 0.394 in 3
D) 0.155 in 3
E) 0.0610 in 3




6) At room temperature, a hydrogen molecule moves at an average velocity of 2.20 km/s.
What is it's velocity in m/s?


A) 2.20 × 10 4 m/s
B) 0.0220 m/s
C) 2.20 × 10 -2 m/s
D) 2.20 × 10 3 m/s
E) 2.20 × 10 2 m/s




7) The distance between carbon atoms in ethylene is 134 picometers. Which of the
following expresses that distance in meters?




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~~~&&&&&&&&############################@@@@@@@@@@@@@@@@22/2026//2027
natureChemistry
of matterthe
andmolecular
change 3rd
nature
ce edition
of matter
by martin
and change
silberberg
3rd ce
tb!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!~~~~~~~~~~~~
edition by martin silberberg tb!!!!!!!!!!!

,martin
~~~&&&&&&&&############################@@@@@@@@@@@@@@@@22/2026//2027
Chemistry
silberberg the
tb!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~&&&&&&&&#########
molecular nature of matter and change 3rd ce edition by martin silberberg tbChemistr




-13
A) 1.34 × 10 m
-12
B) 1.34 × 10 m
-10
C) 1.34 × 10 m
-7
D) 1.34 × 10 m
-6
E) 1.34 × 10 m




8) The average distance from Earth to the Sun is 150 megameters. What is that distance in
meters?


8
A) 1.5 × 10 m
6
B) 1.5 × 10 m
5
C) 1.5 × 10 m
3
D) 1.5 × 10 m
-6
E) 1.5 × 10 m




9) A flask has a mass of 78.23 g when empty and 593.63 g when filled with water. When
the same flask is filled with concentrated sulfuric acid, H 2SO 4, its mass is 1026.57 g. What is
the density of concentrated sulfuric acid? (Assume water has a density of 1.00 g/cm 3 at the
temperature of the measurement.)


3
A) 1.992 g/cm
3
B) 1.840 g/cm
3
C) 1.729 g/cm
3
D) 1.598 g/cm
3
E) 0.543 g/cm




10) Which of the following represents the largest volume?




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~~~&&&&&&&&############################@@@@@@@@@@@@@@@@22/2026//2027
natureChemistry
of matterthe
andmolecular
change 3rd
nature
ce edition
of matter
by martin
and change
silberberg
3rd ce
tb!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!~~~~~~~~~~~~
edition by martin silberberg tb!!!!!!!!!!!

,martin
~~~&&&&&&&&############################@@@@@@@@@@@@@@@@22/2026//2027
Chemistry
silberberg the
tb!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~&&&&&&&&#########
molecular nature of matter and change 3rd ce edition by martin silberberg tbChemistr




A) 10,000 µL
B) 1000 pL
C) 100 mL
D) 10 nL
E) 10 cm 3




11) The joule is the S.I. unit of energy, and is equal to 1 kg m 2 s -2. The erg is another
energy unit, equal to 1 g cm 2 s -2. Use unit conversion methods to work out how many ergs
are there in 1 joule.


A) 10 -1 ergs
B) 10 ergs
C) 10 2 ergs
D) 10 5 ergs
E) 10 7 ergs




12) The S.I. prefix nano- (n) means


A) 10 -6
B) 10 -3
C) 10 -12
D) 10 6
E) 10 -9.




13) Select the answer that expresses the result of this calculation with the correct number of
significant figures and with correct units. 16.18 cm × 9.6114 g ÷ 1.4783 cm 2 =




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~~~&&&&&&&&############################@@@@@@@@@@@@@@@@22/2026//2027
natureChemistry
of matterthe
andmolecular
change 3rd
nature
ce edition
of matter
by martin
and change
silberberg
3rd ce
tb!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!~~~~~~~~~~~~
edition by martin silberberg tb!!!!!!!!!!!