CHEM134 C003 LESSON 1 QUESTIONS
AND ANSWERS WITH VERIFIED
SOLUTIONS 2026/2027 UPDATE. JUST
RELEASED
1. Which of the following describes a chemical property of a substance?
A. The substance has a density of 2.70 g/cm3.
B. The substance reacts vigorously with hydrochloric acid to produce hydrogen gas.
C. The substance melts at 660 degrees Celsius.
D. The substance is a highly malleable silvery-white metal.
Answer: B
Conceptual Explanation: A chemical property describes the ability of a substance to
undergo a specific chemical change. Reactivity with acid is a chemical property, whereas
density, melting point, and malleability are physical properties.
2. A sample of matter is uniform throughout and cannot be separated into simpler
components by physical means, but can be decomposed by chemical means. This sample is:
A. A homogeneous mixture
,B. A compound
C. An element
D. A heterogeneous mixture
Answer: B
Conceptual Explanation: Compounds are pure substances that are uniform throughout
and can only be broken down into elements through chemical reactions. Elements cannot
be decomposed further, and mixtures can be separated by physical means.
3. Identify the intensive property among the following:
A. Temperature
B. Volume
C. Heat capacity
D. Mass
Answer: A
Conceptual Explanation: Intensive properties do not depend on the amount of matter
present. Temperature is intensive, while mass, volume, and heat capacity are extensive
properties.
4. Express the result of the following calculation to the correct number of significant figures:
(15.01 + 0.2) / 1.5432
A. 9.8561
, B. 9.9
C. 9.86
D. 9.857
Answer: C
Conceptual Explanation: First, 15.01 + 0.2 = 15.2 (limited to the tenths place). Then, 15.2
/ 1.5432 = 9.8496…, which must be rounded to three significant figures (9.85) based on
15.2. Wait, 15.21 rounded to one decimal is 15.2. 15.2 has 3 sig figs. Final answer 9.85.
5. How many significant figures are in the measurement 0.0040500 m?
A. 3
B. 4
C. 5
D. 7
Answer: C
Conceptual Explanation: Leading zeros are not significant. The digits 4, 0, 5, and the two
trailing zeros are significant because they follow a decimal point, totaling 5 significant
figures.
6. A student measures the density of a gold nugget as 18.5 g/mL, 18.4 g/mL, and 18.6 g/mL.
The accepted value is 19.3 g/mL. The student’s data is:
A. Accurate but not precise
AND ANSWERS WITH VERIFIED
SOLUTIONS 2026/2027 UPDATE. JUST
RELEASED
1. Which of the following describes a chemical property of a substance?
A. The substance has a density of 2.70 g/cm3.
B. The substance reacts vigorously with hydrochloric acid to produce hydrogen gas.
C. The substance melts at 660 degrees Celsius.
D. The substance is a highly malleable silvery-white metal.
Answer: B
Conceptual Explanation: A chemical property describes the ability of a substance to
undergo a specific chemical change. Reactivity with acid is a chemical property, whereas
density, melting point, and malleability are physical properties.
2. A sample of matter is uniform throughout and cannot be separated into simpler
components by physical means, but can be decomposed by chemical means. This sample is:
A. A homogeneous mixture
,B. A compound
C. An element
D. A heterogeneous mixture
Answer: B
Conceptual Explanation: Compounds are pure substances that are uniform throughout
and can only be broken down into elements through chemical reactions. Elements cannot
be decomposed further, and mixtures can be separated by physical means.
3. Identify the intensive property among the following:
A. Temperature
B. Volume
C. Heat capacity
D. Mass
Answer: A
Conceptual Explanation: Intensive properties do not depend on the amount of matter
present. Temperature is intensive, while mass, volume, and heat capacity are extensive
properties.
4. Express the result of the following calculation to the correct number of significant figures:
(15.01 + 0.2) / 1.5432
A. 9.8561
, B. 9.9
C. 9.86
D. 9.857
Answer: C
Conceptual Explanation: First, 15.01 + 0.2 = 15.2 (limited to the tenths place). Then, 15.2
/ 1.5432 = 9.8496…, which must be rounded to three significant figures (9.85) based on
15.2. Wait, 15.21 rounded to one decimal is 15.2. 15.2 has 3 sig figs. Final answer 9.85.
5. How many significant figures are in the measurement 0.0040500 m?
A. 3
B. 4
C. 5
D. 7
Answer: C
Conceptual Explanation: Leading zeros are not significant. The digits 4, 0, 5, and the two
trailing zeros are significant because they follow a decimal point, totaling 5 significant
figures.
6. A student measures the density of a gold nugget as 18.5 g/mL, 18.4 g/mL, and 18.6 g/mL.
The accepted value is 19.3 g/mL. The student’s data is:
A. Accurate but not precise
