WGU D027 Study Guide 2026/2027 - Complete Solutions Verified Pathophysiology & Pharmacology
Summary WGU D027 Study Guide
2026/2027 Complete Solutions Verified
Pathophysiology and Pharmacology Comprehensive Exam
Aligned with WGU D027 Course Competencies · 160 Questions with Detailed Rationales
Section 1: Cellular Function, Injury, and Adaptation (Q1-15)
Cell Structure, Injury Mechanisms, Necrosis, Apoptosis, & Cellular Adaptations
Q1: A biopsy of a patient's heart muscle shows enlarged myocardial cells with no change in cell number. This cellular
adaptation is best described as:
A. Hyperplasia - increased cell number
B. Hypertrophy - increased cell size in response to increased workload [CORRECT]
C. Atrophy - decreased cell size
D. Metaplasia - change in cell type
Correct Answer: B
Rationale: Hypertrophy is an increase in cell size in response to increased workload or stress, common in cardiac (hypertension, aortic
stenosis) and skeletal muscle (resistance training). Hyperplasia (Option A) is increased cell number (e.g., glandular proliferation in
prostate BPH). Atrophy (Option C) is decreased cell size from disuse or decreased blood supply. Metaplasia (Option D) is reversible cell
type change (e.g., respiratory epithelium becoming squamous in smokers). High-yield summary: hypertrophy = bigger cells, hyperplasia
= more cells, atrophy = smaller cells, metaplasia = different cell type, dysplasia = disordered growth.
Q2: A chronic smoker undergoes bronchoscopy. The normal columnar ciliated epithelium of the bronchi has been
replaced by stratified squamous epithelium. This adaptation is:
A. Hypertrophy
B. Metaplasia - reversible replacement of one adult cell type by another [CORRECT]
C. Dysplasia
D. Anaplasia
Correct Answer: B
Rationale: Metaplasia is the reversible replacement of one differentiated adult cell type by another, often in response to chronic irritation
(smoking causes squamous metaplasia in bronchi; Barrett esophagus = intestinal metaplasia of esophageal squamous epithelium from
chronic GERD). It is adaptive but predisposes to malignant transformation. Dysplasia (Option C) is disordered growth and atypia
(precancerous). Anaplasia (Option D) is loss of differentiation (malignant). Hypertrophy (Option A) is increased cell size. High-yield
summary: metaplasia is reversible and adaptive; dysplasia is precancerous; anaplasia is cancerous.
Page 1
,WGU D027 Study Guide 2026/2027 - Complete Solutions Verified Pathophysiology & Pharmacology
Q3: A patient experiences an acute myocardial infarction. The pattern of cell death involving a localized area of
myocardium with associated inflammation and loss of cell membrane integrity is best described as:
A. Apoptosis - programmed cell death
B. Necrosis - pathologic cell death with inflammation and membrane rupture [CORRECT]
C. Atrophy
D. Autophagy
Correct Answer: B
Rationale: Necrosis is pathologic cell death characterized by cell swelling, membrane rupture, release of cellular contents, and
subsequent inflammation. Types: coagulative (most common, e.g., MI - preserves tissue architecture), liquefactive (brain infarct, abscess),
caseous (TB), fat (acute pancreatitis, breast), gangrenous (extremity with putrefaction). Apoptosis (Option A) is programmed, controlled
cell death without inflammation (membrane blebs, caspases, no inflammation). Atrophy (Option C) is decreased cell size. Autophagy
(Option D) is self-digestion. High-yield: necrosis = pathologic, inflammation, membrane rupture; apoptosis = programmed, no
inflammation, controlled.
Q4: A pathologist examining a tissue sample identifies cells undergoing programmed cell death characterized by cell
shrinkage, chromatin condensation, membrane blebbing, and apoptosis bodies. This process is:
A. Coagulative necrosis
B. Liquefactive necrosis
C. Apoptosis - programmed, energy-dependent cell death [CORRECT]
D. Caseous necrosis
Correct Answer: C
Rationale: Apoptosis is programmed, energy-dependent (ATP-requiring) cell death with characteristic features: cell shrinkage, chromatin
condensation (pyknosis), nuclear fragmentation (karyorrhexis), membrane blebbing, and formation of apoptotic bodies phagocytosed
without inflammation. Examples: embryonic development (loss of webbing between fingers), hormone-dependent tissue regression
(post-lactation breast), T-cell selection in thymus, viral hepatitis (Councilman bodies). Necrosis (Options A, B, D) is pathologic with
inflammation. High-yield summary: apoptosis = physiologic, controlled, ATP-required, no inflammation; necrosis = pathologic,
uncontrolled, inflammation present.
Q5: A 60-year-old patient with chronic hypertension has left ventricular hypertrophy (LVH). This is an example of:
A. Pathologic hypertrophy - in response to disease-induced increased workload [CORRECT]
B. Physiologic hypertrophy - in response to exercise
C. Hyperplasia
D. Metaplasia
Correct Answer: A
Rationale: Pathologic hypertrophy occurs in response to disease-induced increased workload (LVH in hypertension or aortic stenosis,
hypertrophic cardiomyopathy). Physiologic hypertrophy occurs in response to normal demands (uterus in pregnancy, skeletal muscle with
exercise). LVH is initially compensatory but progresses to heart failure due to decreased contractility, fibrosis, and increased oxygen
demand. Hyperplasia (Option C) is increased cell number. Metaplasia (Option D) is cell type change. High-yield: pathologic hypertrophy
is maladaptive long-term; physiologic is adaptive.
Page 2
,WGU D027 Study Guide 2026/2027 - Complete Solutions Verified Pathophysiology & Pharmacology
Q6: A patient with chronic gastric reflux develops intestinal-type epithelium in the distal esophagus (Barrett
esophagus). This is an example of:
A. Intestinal metaplasia - adaptive change predisposing to adenocarcinoma [CORRECT]
B. Hypertrophy
C. Dysplasia
D. Anaplasia
Correct Answer: A
Rationale: Barrett esophagus is intestinal metaplasia of the normal squamous esophageal epithelium due to chronic GERD. It is adaptive
(resistant to acid) but predisposes to esophageal adenocarcinoma (30x risk). Surveillance endoscopy with biopsies is recommended.
Dysplasia (Option C) may develop in Barrett (precancerous). Anaplasia (Option D) is cancer. Hypertrophy (Option B) is increased cell
size. High-yield: metaplasia is reversible and adaptive but premalignant; surveillance recommended for Barrett esophagus.
Q7: A decrease in cell size due to decreased workload, denervation, or decreased nutrition is called:
A. Hypertrophy
B. Atrophy - decrease in cell size due to decreased activity or blood supply [CORRECT]
C. Hyperplasia
D. Metaplasia
Correct Answer: B
Rationale: Atrophy is a decrease in cell size due to decreased workload (immobilization, bed rest), denervation (spinal cord injury),
decreased blood supply (atherosclerosis), inadequate nutrition (cachexia), or aging. May be reversible if cause corrected (e.g., physical
therapy after immobilization). Common examples: disuse atrophy of limbs post-cast, brain atrophy in Alzheimer's. Hypertrophy (Option
A) is increased cell size. Hyperplasia (Option C) is increased cell number. Metaplasia (Option D) is cell type change. High-yield
summary: atrophy = shrinkage; common causes = disuse, denervation, ischemia, malnutrition, aging.
Q8: Cellular injury from ischemia initially causes:
A. Immediate cell membrane rupture
B. Decreased ATP production leading to failure of Na+/K+ ATPase, cell swelling, and intracellular calcium accumulation
[CORRECT]
C. Apoptosis activation
D. Increased protein synthesis
Correct Answer: B
Rationale: Ischemic injury sequence: decreased O2 → decreased oxidative phosphorylation → decreased ATP → failure of Na+/K+
ATPase → intracellular Na+ accumulation → cell swelling (hydropic change) and K+ efflux. Ca2+ ATPase also fails → intracellular
Ca2+ accumulation → activate phospholipases, proteases, endonucleases → membrane damage, protein denaturation, DNA
fragmentation. Reversible if perfusion restored; irreversible if mitochondria rupture, membrane damage severe. Apoptosis (Option C) is
later. Options A, D incorrect. High-yield: ischemia → ATP depletion → Na/K pump failure → cell swelling and Ca2+ accumulation.
Page 3
, WGU D027 Study Guide 2026/2027 - Complete Solutions Verified Pathophysiology & Pharmacology
Q9: Reperfusion injury after restoration of blood flow to ischemic tissue is primarily caused by:
A. Restoration of oxygen causing generation of reactive oxygen species (ROS) and inflammation [CORRECT]
B. Improved cellular function
C. Decreased calcium influx
D. Decreased inflammation
Correct Answer: A
Rationale: Reperfusion injury occurs when blood flow is restored to ischemic tissue, paradoxically worsening damage due to: (1)
generation of reactive oxygen species (ROS - superoxide, hydrogen peroxide, hydroxyl radical) from damaged mitochondria, (2) influx of
inflammatory cells (neutrophils) releasing proteases, (3) complement activation, (4) intracellular calcium overload. Clinical examples:
thrombolytics in MI, tPA in stroke, organ transplant reperfusion. Treatment strategies under research: antioxidants, complement
inhibitors. High-yield: reperfusion injury = ROS + inflammation after blood flow restoration.
Q10: A patient develops renal cell carcinoma. The tumor suppressor gene most commonly mutated in this and many
other cancers is:
A. p53 - the 'guardian of the genome' that triggers apoptosis in DNA-damaged cells [CORRECT]
B. BRCA1
C. Rb (retinoblastoma)
D. APC
Correct Answer: A
Rationale: p53 is the most commonly mutated gene in human cancers (>50%). Located on chromosome 17p. Functions: activates DNA
repair genes (p21), induces apoptosis if DNA damage irreparable, arrests cell cycle at G1. Mutated in Li-Fraumeni syndrome
(multi-cancer). Rb (Option C) is mutated in retinoblastoma, osteosarcoma, small cell lung cancer. BRCA1/2 (Option B) in hereditary
breast/ovarian. APC (Option D) in familial adenomatous polyposis coli. High-yield: p53 is the 'guardian of the genome,' most commonly
mutated tumor suppressor in cancer.
Q11: An increase in cell number in response to hormonal stimulation is best exemplified by:
A. Skeletal muscle hypertrophy in weight lifters
B. Endometrial hyperplasia in response to unopposed estrogen [CORRECT]
C. Cerebral atrophy in Alzheimer's
D. Squamous metaplasia in smokers
Correct Answer: B
Rationale: Hyperplasia is increased cell number in response to hormonal or growth factor stimulation. Examples: endometrial
hyperplasia (unopposed estrogen; risk of endometrial cancer), benign prostatic hyperplasia (androgens), glandular hyperplasia in breast,
compensatory hyperplasia after partial hepatectomy. Skeletal muscle in weight lifters is hypertrophy (Option A) - muscle cells cannot
divide (terminally differentiated). Atrophy (Option C) is shrinkage. Metaplasia (Option D) is cell type change. High-yield: hyperplasia =
more cells from hormones/growth factors; hypertrophy = bigger cells from workload.
Page 4
Summary WGU D027 Study Guide
2026/2027 Complete Solutions Verified
Pathophysiology and Pharmacology Comprehensive Exam
Aligned with WGU D027 Course Competencies · 160 Questions with Detailed Rationales
Section 1: Cellular Function, Injury, and Adaptation (Q1-15)
Cell Structure, Injury Mechanisms, Necrosis, Apoptosis, & Cellular Adaptations
Q1: A biopsy of a patient's heart muscle shows enlarged myocardial cells with no change in cell number. This cellular
adaptation is best described as:
A. Hyperplasia - increased cell number
B. Hypertrophy - increased cell size in response to increased workload [CORRECT]
C. Atrophy - decreased cell size
D. Metaplasia - change in cell type
Correct Answer: B
Rationale: Hypertrophy is an increase in cell size in response to increased workload or stress, common in cardiac (hypertension, aortic
stenosis) and skeletal muscle (resistance training). Hyperplasia (Option A) is increased cell number (e.g., glandular proliferation in
prostate BPH). Atrophy (Option C) is decreased cell size from disuse or decreased blood supply. Metaplasia (Option D) is reversible cell
type change (e.g., respiratory epithelium becoming squamous in smokers). High-yield summary: hypertrophy = bigger cells, hyperplasia
= more cells, atrophy = smaller cells, metaplasia = different cell type, dysplasia = disordered growth.
Q2: A chronic smoker undergoes bronchoscopy. The normal columnar ciliated epithelium of the bronchi has been
replaced by stratified squamous epithelium. This adaptation is:
A. Hypertrophy
B. Metaplasia - reversible replacement of one adult cell type by another [CORRECT]
C. Dysplasia
D. Anaplasia
Correct Answer: B
Rationale: Metaplasia is the reversible replacement of one differentiated adult cell type by another, often in response to chronic irritation
(smoking causes squamous metaplasia in bronchi; Barrett esophagus = intestinal metaplasia of esophageal squamous epithelium from
chronic GERD). It is adaptive but predisposes to malignant transformation. Dysplasia (Option C) is disordered growth and atypia
(precancerous). Anaplasia (Option D) is loss of differentiation (malignant). Hypertrophy (Option A) is increased cell size. High-yield
summary: metaplasia is reversible and adaptive; dysplasia is precancerous; anaplasia is cancerous.
Page 1
,WGU D027 Study Guide 2026/2027 - Complete Solutions Verified Pathophysiology & Pharmacology
Q3: A patient experiences an acute myocardial infarction. The pattern of cell death involving a localized area of
myocardium with associated inflammation and loss of cell membrane integrity is best described as:
A. Apoptosis - programmed cell death
B. Necrosis - pathologic cell death with inflammation and membrane rupture [CORRECT]
C. Atrophy
D. Autophagy
Correct Answer: B
Rationale: Necrosis is pathologic cell death characterized by cell swelling, membrane rupture, release of cellular contents, and
subsequent inflammation. Types: coagulative (most common, e.g., MI - preserves tissue architecture), liquefactive (brain infarct, abscess),
caseous (TB), fat (acute pancreatitis, breast), gangrenous (extremity with putrefaction). Apoptosis (Option A) is programmed, controlled
cell death without inflammation (membrane blebs, caspases, no inflammation). Atrophy (Option C) is decreased cell size. Autophagy
(Option D) is self-digestion. High-yield: necrosis = pathologic, inflammation, membrane rupture; apoptosis = programmed, no
inflammation, controlled.
Q4: A pathologist examining a tissue sample identifies cells undergoing programmed cell death characterized by cell
shrinkage, chromatin condensation, membrane blebbing, and apoptosis bodies. This process is:
A. Coagulative necrosis
B. Liquefactive necrosis
C. Apoptosis - programmed, energy-dependent cell death [CORRECT]
D. Caseous necrosis
Correct Answer: C
Rationale: Apoptosis is programmed, energy-dependent (ATP-requiring) cell death with characteristic features: cell shrinkage, chromatin
condensation (pyknosis), nuclear fragmentation (karyorrhexis), membrane blebbing, and formation of apoptotic bodies phagocytosed
without inflammation. Examples: embryonic development (loss of webbing between fingers), hormone-dependent tissue regression
(post-lactation breast), T-cell selection in thymus, viral hepatitis (Councilman bodies). Necrosis (Options A, B, D) is pathologic with
inflammation. High-yield summary: apoptosis = physiologic, controlled, ATP-required, no inflammation; necrosis = pathologic,
uncontrolled, inflammation present.
Q5: A 60-year-old patient with chronic hypertension has left ventricular hypertrophy (LVH). This is an example of:
A. Pathologic hypertrophy - in response to disease-induced increased workload [CORRECT]
B. Physiologic hypertrophy - in response to exercise
C. Hyperplasia
D. Metaplasia
Correct Answer: A
Rationale: Pathologic hypertrophy occurs in response to disease-induced increased workload (LVH in hypertension or aortic stenosis,
hypertrophic cardiomyopathy). Physiologic hypertrophy occurs in response to normal demands (uterus in pregnancy, skeletal muscle with
exercise). LVH is initially compensatory but progresses to heart failure due to decreased contractility, fibrosis, and increased oxygen
demand. Hyperplasia (Option C) is increased cell number. Metaplasia (Option D) is cell type change. High-yield: pathologic hypertrophy
is maladaptive long-term; physiologic is adaptive.
Page 2
,WGU D027 Study Guide 2026/2027 - Complete Solutions Verified Pathophysiology & Pharmacology
Q6: A patient with chronic gastric reflux develops intestinal-type epithelium in the distal esophagus (Barrett
esophagus). This is an example of:
A. Intestinal metaplasia - adaptive change predisposing to adenocarcinoma [CORRECT]
B. Hypertrophy
C. Dysplasia
D. Anaplasia
Correct Answer: A
Rationale: Barrett esophagus is intestinal metaplasia of the normal squamous esophageal epithelium due to chronic GERD. It is adaptive
(resistant to acid) but predisposes to esophageal adenocarcinoma (30x risk). Surveillance endoscopy with biopsies is recommended.
Dysplasia (Option C) may develop in Barrett (precancerous). Anaplasia (Option D) is cancer. Hypertrophy (Option B) is increased cell
size. High-yield: metaplasia is reversible and adaptive but premalignant; surveillance recommended for Barrett esophagus.
Q7: A decrease in cell size due to decreased workload, denervation, or decreased nutrition is called:
A. Hypertrophy
B. Atrophy - decrease in cell size due to decreased activity or blood supply [CORRECT]
C. Hyperplasia
D. Metaplasia
Correct Answer: B
Rationale: Atrophy is a decrease in cell size due to decreased workload (immobilization, bed rest), denervation (spinal cord injury),
decreased blood supply (atherosclerosis), inadequate nutrition (cachexia), or aging. May be reversible if cause corrected (e.g., physical
therapy after immobilization). Common examples: disuse atrophy of limbs post-cast, brain atrophy in Alzheimer's. Hypertrophy (Option
A) is increased cell size. Hyperplasia (Option C) is increased cell number. Metaplasia (Option D) is cell type change. High-yield
summary: atrophy = shrinkage; common causes = disuse, denervation, ischemia, malnutrition, aging.
Q8: Cellular injury from ischemia initially causes:
A. Immediate cell membrane rupture
B. Decreased ATP production leading to failure of Na+/K+ ATPase, cell swelling, and intracellular calcium accumulation
[CORRECT]
C. Apoptosis activation
D. Increased protein synthesis
Correct Answer: B
Rationale: Ischemic injury sequence: decreased O2 → decreased oxidative phosphorylation → decreased ATP → failure of Na+/K+
ATPase → intracellular Na+ accumulation → cell swelling (hydropic change) and K+ efflux. Ca2+ ATPase also fails → intracellular
Ca2+ accumulation → activate phospholipases, proteases, endonucleases → membrane damage, protein denaturation, DNA
fragmentation. Reversible if perfusion restored; irreversible if mitochondria rupture, membrane damage severe. Apoptosis (Option C) is
later. Options A, D incorrect. High-yield: ischemia → ATP depletion → Na/K pump failure → cell swelling and Ca2+ accumulation.
Page 3
, WGU D027 Study Guide 2026/2027 - Complete Solutions Verified Pathophysiology & Pharmacology
Q9: Reperfusion injury after restoration of blood flow to ischemic tissue is primarily caused by:
A. Restoration of oxygen causing generation of reactive oxygen species (ROS) and inflammation [CORRECT]
B. Improved cellular function
C. Decreased calcium influx
D. Decreased inflammation
Correct Answer: A
Rationale: Reperfusion injury occurs when blood flow is restored to ischemic tissue, paradoxically worsening damage due to: (1)
generation of reactive oxygen species (ROS - superoxide, hydrogen peroxide, hydroxyl radical) from damaged mitochondria, (2) influx of
inflammatory cells (neutrophils) releasing proteases, (3) complement activation, (4) intracellular calcium overload. Clinical examples:
thrombolytics in MI, tPA in stroke, organ transplant reperfusion. Treatment strategies under research: antioxidants, complement
inhibitors. High-yield: reperfusion injury = ROS + inflammation after blood flow restoration.
Q10: A patient develops renal cell carcinoma. The tumor suppressor gene most commonly mutated in this and many
other cancers is:
A. p53 - the 'guardian of the genome' that triggers apoptosis in DNA-damaged cells [CORRECT]
B. BRCA1
C. Rb (retinoblastoma)
D. APC
Correct Answer: A
Rationale: p53 is the most commonly mutated gene in human cancers (>50%). Located on chromosome 17p. Functions: activates DNA
repair genes (p21), induces apoptosis if DNA damage irreparable, arrests cell cycle at G1. Mutated in Li-Fraumeni syndrome
(multi-cancer). Rb (Option C) is mutated in retinoblastoma, osteosarcoma, small cell lung cancer. BRCA1/2 (Option B) in hereditary
breast/ovarian. APC (Option D) in familial adenomatous polyposis coli. High-yield: p53 is the 'guardian of the genome,' most commonly
mutated tumor suppressor in cancer.
Q11: An increase in cell number in response to hormonal stimulation is best exemplified by:
A. Skeletal muscle hypertrophy in weight lifters
B. Endometrial hyperplasia in response to unopposed estrogen [CORRECT]
C. Cerebral atrophy in Alzheimer's
D. Squamous metaplasia in smokers
Correct Answer: B
Rationale: Hyperplasia is increased cell number in response to hormonal or growth factor stimulation. Examples: endometrial
hyperplasia (unopposed estrogen; risk of endometrial cancer), benign prostatic hyperplasia (androgens), glandular hyperplasia in breast,
compensatory hyperplasia after partial hepatectomy. Skeletal muscle in weight lifters is hypertrophy (Option A) - muscle cells cannot
divide (terminally differentiated). Atrophy (Option C) is shrinkage. Metaplasia (Option D) is cell type change. High-yield: hyperplasia =
more cells from hormones/growth factors; hypertrophy = bigger cells from workload.
Page 4
