Geschreven door studenten die geslaagd zijn Direct beschikbaar na je betaling Online lezen of als PDF Verkeerd document? Gratis ruilen 4,6 TrustPilot
logo-home
Document preview thumbnail
Voorbeeld 4 van de 46 pagina's
Tentamen (uitwerkingen)

WGU D115 Advanced Pathophysiology OA Exam 2025/2026 – Complete Exam Questions and Answers

Document preview thumbnail
Voorbeeld 4 van de 46 pagina's

WGU D115 Advanced Pathophysiology OA Exam 2025/2026 – Complete Exam Questions and Answers

Voorbeeld van de inhoud

WGU D115 Advanced Pathophysiology OA
Exam 2025/2026 – Complete Exam Questions
and Answers
1. A 62-year-old patient with chronic hypertension develops left ventricular hypertrophy. Which
cellular adaptation best describes this change?

A) Hyperplasia — increase in cell number
B) Metaplasia — replacement of one cell type with another
C) Hypertrophy — increase in cell size
D) Dysplasia — abnormal cell growth and organization

Correct Answer: C) Hypertrophy — increase in cell size

Rationale: Hypertrophy is an increase in cell size in response to increased workload. Chronic
hypertension increases afterload on the left ventricle, causing myocardial cells to hypertrophy to
meet the increased demand. Because cardiac myocytes cannot significantly divide, the heart
compensates by increasing cell size rather than cell number .



2. A researcher studying a cell line that lost the ability to undergo apoptosis after DNA damage
finds absent p53 protein expression. Loss of p53 function most directly affects which cellular
process?

A) Ras protein GTPase activity
B) Cyclin D-CDK4 complex formation
C) Activation of pro-apoptotic Bax and Bak proteins
D) Telomerase reverse transcriptase expression

Correct Answer: C) Activation of pro-apoptotic Bax and Bak proteins

Rationale: p53 activates the intrinsic apoptotic pathway by upregulating pro-apoptotic Bax
and Bak while suppressing anti-apoptotic Bcl-2. Loss of p53 function prevents apoptosis of cells
with DNA damage, allowing potentially malignant cells to survive and proliferate .



3. A patient with COPD develops squamous metaplasia in the bronchial epithelium. Which
statement best describes this cellular change?

,A) An increase in cell size
B) A reversible replacement of one differentiated cell type with another
C) An increase in the number of cells
D) A decrease in cell size

Correct Answer: B) A reversible replacement of one differentiated cell type with another

Rationale: Metaplasia is a reversible change in which one differentiated cell type is replaced
by another. In COPD, chronic irritation from smoking causes the normal ciliated columnar
epithelium of the bronchi to be replaced by stratified squamous epithelium, which is more
resilient but loses protective functions .



4. Which statement accurately describes the difference between necrosis and apoptosis?

A) Necrosis is programmed cell death; apoptosis is unregulated
B) Necrosis triggers an inflammatory response; apoptosis does not
C) Apoptosis always leads to cell swelling; necrosis does not
D) Necrosis is energy-dependent; apoptosis is not

Correct Answer: B) Necrosis triggers an inflammatory response; apoptosis does not

Rationale: Necrosis is unregulated cell death that triggers inflammation due to the release
of cellular contents. Apoptosis is a highly regulated, energy-dependent process that does not
elicit an inflammatory response .



5. The cellular adaptation characterized by a decrease in cell size and function in response to
decreased workload is called:

A) Hypertrophy
B) Atrophy
C) Hyperplasia
D) Metaplasia

Correct Answer: B) Atrophy

Rationale: Atrophy is a decrease in cell size due to reduced workload, disuse, denervation,
or decreased blood supply. It is a common adaptation in immobilized muscles or aging tissues .



6. Ischemia causes cellular injury primarily through which mechanism?

,A) Excess ATP production
B) Decreased oxygen delivery leading to anaerobic metabolism and lactic acidosis
C) Hyperkalemia from cell rupture
D) Increased protein synthesis

Correct Answer: B) Decreased oxygen delivery leading to anaerobic metabolism and lactic
acidosis

Rationale: Ischemia reduces oxygen delivery to cells. This forces the cell into anaerobic
metabolism, which produces lactic acid and decreases ATP production, leading to cell swelling
and injury .



7. Free radicals cause cellular damage by which mechanism?

A) Promoting DNA repair
B) Stealing electrons from cellular structures like DNA, lipids, and proteins
C) Increasing ATP production
D) Activating apoptosis pathways only

Correct Answer: B) Stealing electrons from cellular structures like DNA, lipids, and
proteins

Rationale: Free radicals are highly reactive molecules with unpaired electrons. They cause
oxidative stress by stealing electrons from cellular structures, leading to DNA damage, lipid
peroxidation, and protein dysfunction .



8. A patient with prolonged immobilization is at risk for which cellular adaptation in skeletal
muscle?

A) Hypertrophy
B) Hyperplasia
C) Disuse atrophy
D) Metaplasia

Correct Answer: C) Disuse atrophy

Rationale: Disuse atrophy occurs in skeletal muscle when there is decreased workload from
prolonged immobility, resulting in decreased muscle mass and function .

, 9. Which of the following is an example of pathologic hyperplasia?

A) Breast tissue enlargement during pregnancy
B) Endometrial hyperplasia from unopposed estrogen
C) Liver regeneration after partial hepatectomy
D) Erythrocyte production in high altitude

Correct Answer: B) Endometrial hyperplasia from unopposed estrogen

Rationale: Endometrial hyperplasia from unopposed estrogen is a pathologic hyperplasia
that increases the risk of endometrial cancer. The others are physiologic responses to normal
stimuli .



10. The hallmark of irreversible cellular injury is:

A) Cellular swelling
B) Fatty change
C) Mitochondrial amorphous densities
D) Membrane blebbing

Correct Answer: C) Mitochondrial amorphous densities

Rationale: Flocculent densities in the mitochondrial matrix are an irreversible marker of cell
death, indicating severe membrane damage. This is the "point of no return" where cell death is
inevitable even if the stressor is removed .



11. What is the earliest reversible morphologic sign of cell injury?

A) Nuclear pyknosis
B) Cellular swelling (hydropic change)
C) Fatty change
D) Karyolysis

Correct Answer: B) Cellular swelling (hydropic change)

Rationale: Cellular swelling is the earliest reversible sign of cell injury, caused by ATP
depletion leading to failure of the Na⁺/K⁺ pump and subsequent water influx. This is followed by
fatty change in some organs .

Documentinformatie

Geüpload op
20 september 2026
Aantal pagina's
46
Geschreven in
2026/2027
Type
Tentamen (uitwerkingen)
Bevat
Vragen en antwoorden
$25.99

Verkeerd document? Gratis ruilen Binnen 14 dagen na aankoop en voor het downloaden kun je een ander document kiezen. Je kunt het bedrag gewoon opnieuw besteden.
Geschreven door studenten die geslaagd zijn
Direct beschikbaar na je betaling
Online lezen of als PDF

Verkocht
0
Volgers
0
Items
157
Laatst verkocht
-



Waarom studenten kiezen voor Stuvia

Gemaakt door medestudenten, geverifieerd door reviews

Kwaliteit die je kunt vertrouwen: geschreven door studenten die slaagden en beoordeeld door anderen die dit document gebruikten.

Niet tevreden? Kies een ander document

Geen zorgen! Je kunt voor hetzelfde geld direct een ander document kiezen dat beter past bij wat je zoekt.

Betaal zoals je wilt, start meteen met leren

Geen abonnement, geen verplichtingen. Betaal zoals je gewend bent via iDeal of creditcard en download je PDF-document meteen.

Student with book image

“Gekocht, gedownload en geslaagd. Zo makkelijk kan het dus zijn.”

Alisha Student

Bezig met je bronvermelding?

Maak nauwkeurige citaten in APA, MLA en Harvard met onze gratis bronnengenerator.

Bezig met je bronvermelding?

Veelgestelde vragen