ASQ Certified Quality Inspector
(CQI) Exam Simulation 150
Advanced Multiple-Choice
Questions with Rationales
Covering Technical Mathematics,
Metrology, Inspection and Test,
and Quality Assurance and
Improvement.
Advanced / Hard (Mixed)
Quality professionals, inspectors, and engineers preparing for the ASQ CQI
certification exam (September 1–30 testing window).
1. (Questions 1–40)
o Basic Shop Math
o Basic Algebra
o Basic Geometry
o Basic Trigonometry
, o Measurement Systems
o Numeric Conversions
o Basic Statistics and Applications
2. (Questions 41–80)
o Common Gauges and Measurement Instruments
o Special Gauges and Applications
o Gauge Selection, Handling, and Use
o Surface Plate Tools and Techniques
o Specialized Inspection Equipment
o Calibration
o Measurement System Analysis (MSA)
3. (Questions 81–120)
o Blueprints, Drawings, GD&T, and Model-Based Definitions
o Sampling
o Inspection Planning and Processes
o Testing Methods
o Software for Test Equipment
4. (Questions 121–150)
o Basic Statistics and Applications
o Statistical Process Control (SPC)
o Quality Improvement
o Quality Audits
o Quality Tools and Techniques
o Problem-Solving Tools and Continuous Improvement Techniques
An inspector measures a shaft with a nominal diameter of 25.00 mm. The allowable
tolerance is ±0.05 mm. The measured value is 24.96 mm. What is the deviation from the nominal
dimension?
,A. +0.04 mm
B. -0.04 mm
C. +0.05 mm
D. -0.05 mm
Deviation = Measured value – Nominal value = 24.96 mm – 25.00 mm = -0.04 mm. A
negative deviation indicates the part is undersized relative to the nominal.
A quality inspector needs to convert the fraction 7/16 into a decimal for a report.
What is the correct decimal equivalent?
A. 0.4375
B. 0.4250
C. 0.4750
D. 0.4180
To convert a fraction to a decimal, divide the numerator by the denominator: 7 ÷ 16 =
0.4375. This is a fundamental shop math skill used daily in inspection.
A blueprint specifies a dimension of 3.500 inches with a tolerance of +0.000/-0.010
inches. What is the Lower Specification Limit (LSL)?
A. 3.500 inches
B. 3.510 inches
C. 3.490 inches
D. 3.480 inches
The LSL is the nominal dimension minus the lower tolerance. Since the lower tolerance is -
0.010, LSL = 3.500 – 0.010 = 3.490 inches. The USL would be 3.500 inches.
A process produces parts with a nominal length of 10.0 cm. The process average is
10.2 cm. What is the percent change from the nominal value?
A. 2.0%
B. 0.2%
C. -2.0%
D. -0.2%
Percent change = ((New – Original) / Original) × 100 = ((10.2 – 10.0) / 10.0) × 100 = (0.2 /
10.0) × 100 = 2.0%.
Solve for *x* in the equation: 4*x* + 12 = 36.
A. 4
B. 6
, C. 8
D. 12
4*x* + 12 = 36 → 4*x* = 36 – 12 → 4*x* = 24 → *x* = = 6. This tests basic algebra
skills used for calculating tolerances or process parameters.
A circular inspection window has a diameter of 8 inches. What is its area?
A. 25.13 in²
B. 50.27 in²
C. 64.00 in²
D. 201.06 in²
Area of a circle = π * r². Radius (r) = diameter / 2 = = 4 inches. Area = π * 4² = π * 16 ≈
50.27 in².
An inspector is checking a right triangle on a fixture. If the opposite side is 3 units
and the adjacent side is 4 units, what is the length of the hypotenuse?
A. 5 units
B. 6 units
C. 7 units
D. 25 units
Using the Pythagorean Theorem (a² + b² = c²), where *a* = 3 and *b* = 4: c² = 3² + 4² = 9 +
16 = 25. Therefore, c = √25 = 5 units.
Convert 0.250 inches to millimeters (1 inch = 25.4 mm).
A. 6.35 mm
B. 6.00 mm
C. 7.62 mm
D. 5.08 mm
0.250 inches × 25.4 mm/inch = 6.35 mm. This is a standard conversion between the
English and metric measurement systems.
Express the number 45,000 in scientific notation.
A. 4.5 × 10⁴
B. 45 × 10³
C. 4.5 × 10³
D. 0.45 × 10⁵
(CQI) Exam Simulation 150
Advanced Multiple-Choice
Questions with Rationales
Covering Technical Mathematics,
Metrology, Inspection and Test,
and Quality Assurance and
Improvement.
Advanced / Hard (Mixed)
Quality professionals, inspectors, and engineers preparing for the ASQ CQI
certification exam (September 1–30 testing window).
1. (Questions 1–40)
o Basic Shop Math
o Basic Algebra
o Basic Geometry
o Basic Trigonometry
, o Measurement Systems
o Numeric Conversions
o Basic Statistics and Applications
2. (Questions 41–80)
o Common Gauges and Measurement Instruments
o Special Gauges and Applications
o Gauge Selection, Handling, and Use
o Surface Plate Tools and Techniques
o Specialized Inspection Equipment
o Calibration
o Measurement System Analysis (MSA)
3. (Questions 81–120)
o Blueprints, Drawings, GD&T, and Model-Based Definitions
o Sampling
o Inspection Planning and Processes
o Testing Methods
o Software for Test Equipment
4. (Questions 121–150)
o Basic Statistics and Applications
o Statistical Process Control (SPC)
o Quality Improvement
o Quality Audits
o Quality Tools and Techniques
o Problem-Solving Tools and Continuous Improvement Techniques
An inspector measures a shaft with a nominal diameter of 25.00 mm. The allowable
tolerance is ±0.05 mm. The measured value is 24.96 mm. What is the deviation from the nominal
dimension?
,A. +0.04 mm
B. -0.04 mm
C. +0.05 mm
D. -0.05 mm
Deviation = Measured value – Nominal value = 24.96 mm – 25.00 mm = -0.04 mm. A
negative deviation indicates the part is undersized relative to the nominal.
A quality inspector needs to convert the fraction 7/16 into a decimal for a report.
What is the correct decimal equivalent?
A. 0.4375
B. 0.4250
C. 0.4750
D. 0.4180
To convert a fraction to a decimal, divide the numerator by the denominator: 7 ÷ 16 =
0.4375. This is a fundamental shop math skill used daily in inspection.
A blueprint specifies a dimension of 3.500 inches with a tolerance of +0.000/-0.010
inches. What is the Lower Specification Limit (LSL)?
A. 3.500 inches
B. 3.510 inches
C. 3.490 inches
D. 3.480 inches
The LSL is the nominal dimension minus the lower tolerance. Since the lower tolerance is -
0.010, LSL = 3.500 – 0.010 = 3.490 inches. The USL would be 3.500 inches.
A process produces parts with a nominal length of 10.0 cm. The process average is
10.2 cm. What is the percent change from the nominal value?
A. 2.0%
B. 0.2%
C. -2.0%
D. -0.2%
Percent change = ((New – Original) / Original) × 100 = ((10.2 – 10.0) / 10.0) × 100 = (0.2 /
10.0) × 100 = 2.0%.
Solve for *x* in the equation: 4*x* + 12 = 36.
A. 4
B. 6
, C. 8
D. 12
4*x* + 12 = 36 → 4*x* = 36 – 12 → 4*x* = 24 → *x* = = 6. This tests basic algebra
skills used for calculating tolerances or process parameters.
A circular inspection window has a diameter of 8 inches. What is its area?
A. 25.13 in²
B. 50.27 in²
C. 64.00 in²
D. 201.06 in²
Area of a circle = π * r². Radius (r) = diameter / 2 = = 4 inches. Area = π * 4² = π * 16 ≈
50.27 in².
An inspector is checking a right triangle on a fixture. If the opposite side is 3 units
and the adjacent side is 4 units, what is the length of the hypotenuse?
A. 5 units
B. 6 units
C. 7 units
D. 25 units
Using the Pythagorean Theorem (a² + b² = c²), where *a* = 3 and *b* = 4: c² = 3² + 4² = 9 +
16 = 25. Therefore, c = √25 = 5 units.
Convert 0.250 inches to millimeters (1 inch = 25.4 mm).
A. 6.35 mm
B. 6.00 mm
C. 7.62 mm
D. 5.08 mm
0.250 inches × 25.4 mm/inch = 6.35 mm. This is a standard conversion between the
English and metric measurement systems.
Express the number 45,000 in scientific notation.
A. 4.5 × 10⁴
B. 45 × 10³
C. 4.5 × 10³
D. 0.45 × 10⁵
