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CHEM 121 Module 4 Exam Foundations of General Chemistry w/Lab | Portage | 26/27 Actual (PDF)

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INSTANT PDF DOWNLOAD — Verified CHEM 121 Foundations of General Chemistry with Lab Module 4 Exam | Portage Learning | 2026/2027 Edition (PDF) resource featuring complete exam Q&A, NGN‑style case studies, SATA formats, and 100% correct answers. Module 4 emphasizes thermochemistry and energy in chemical reactions, covering enthalpy, calorimetry, heat transfer, Hess’s law, and energy conservation principles. Students practice lab applications including calorimetric experiments, reaction enthalpy calculations, and quantitative data analysis. Emphasis on molecular interactions, problem‑solving, and clinical correlations ensures exam readiness. Designed for guaranteed Grade A performance and full alignment with Portage Learning curriculum, this study guide is perfect for students searching CHEM 121 Module 4 Exam PDF, Foundations of Chemistry Study Guide, CHEM 121 Test Bank, CHEM 121 Verified Answers, CHEM 121 Exam Prep 2026/2027, ATI Style Nursing Practice, CHEM 121 Quiz PDF, CHEM 121 Study Guide Review, and CHEM 121 Comprehensive Solution.

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,CHEM 121 Module 4 Exam Foundations of General
Chemistry w/Lab | Portage | 26/27 Actual (PDF)
1. What is the formula mass of calcium nitrate, Ca(NO₃)₂?



A) 102.09 amu

B) 164.09 amu

C) 132.09 amu

D) 116.09 amu



Correct Answer: 164.09 amu



Rationale: Formula mass = 1(Ca) + 2(N) + 6(O) = 40.08 + 2(14.01) + 6(16.00) = 40.08 + 28.02 + 96.00 =
164.10 amu. Option A omits the nitrate contribution, option C uses only one nitrogen, and option D
miscalculates oxygen atoms. Options A, C, and D are incorrect.



2. How many moles of oxygen atoms are present in 3.0 moles of Al₂(SO₄)₃?



A) 12 moles

B) 3.0 moles

C) 36 moles

D) 18 moles



Correct Answer: 36 moles



Rationale: Each formula unit of Al₂(SO₄)₃ contains 12 oxygen atoms (3 × 4 = 12). Therefore, 3.0 moles
of the compound contain 3.0 × 12 = 36 moles of oxygen atoms. Options A, B, and D are incorrect
because they do not account for the total number of oxygen atoms per formula unit.



3. A compound is composed of 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. What is its
empirical formula?

,A) C₂H₄O

B) CH₂O

C) C₂H₆O

D) CHO



Correct Answer: CH₂O



Rationale: Assuming 100 g, moles: C = 40.0/12.01 = 3.33, H = 6.7/1.008 = 6.65, O = 53.3/16.00 = 3.33.
Dividing by the smallest (3.33) gives C: 1, H: 2, O: 1, so the empirical formula is CH₂O. Options A, C, and
D have incorrect ratios.



4. What is the molarity of a solution prepared by dissolving 25.0 g of NaCl (molar mass = 58.44 g/mol)
in enough water to make 500.0 mL of solution?



A) 0.428 M

B) 0.856 M

C) 2.14 M

D) 0.214 M



Correct Answer: 0.856 M



Rationale: Moles of NaCl = 25.0 g / 58.44 g/mol = 0.428 mol. Volume = 0.5000 L. Molarity = 0.428
mol / 0.5000 L = 0.856 M. Option A is the number of moles, option C is double the correct value, and
option D is half the correct value.



5. When the following equation is balanced with the smallest whole-number coefficients, what is the
coefficient of O₂? __ C₃H₈ + __ O₂ → __ CO₂ + __ H₂O



A) 5

B) 7

, C) 3

D) 4



Correct Answer: 5



Rationale: Balancing C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O gives coefficients 1, 5, 3, 4. The coefficient of O₂ is 5.
Options B, C, and D do not satisfy the conservation of mass for this combustion reaction.



6. Which of the following is a precipitation reaction?



A) HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

B) 2 H₂(g) + O₂(g) → 2 H₂O(g)

C) AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)

D) Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s)



Correct Answer: AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)



Rationale: A precipitation reaction produces an insoluble solid (precipitate) from aqueous reactants.
AgCl(s) is the precipitate in option C. Option A is acid-base neutralization, option B is a synthesis
reaction, and option D is a single-replacement redox reaction.



7. What is the oxidation state of manganese in KMnO₄?



A) +2

B) +4

C) +7

D) +6



Correct Answer: +7

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