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Formularium Computationeel denken | Examengeschikte versie

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Compact en overzichtelijk A4-formularium voor Computationeel denken. Dit is de examengeschikte versie van mijn persoonlijk formularium, opgesteld tijdens het vak en nagekeken door de docent. Het bevat de belangrijkste Python-syntax, datastructuren, operatoren en functies op één pagina. Op mijn profiel vind je ook een gratis A3-studieversie van hetzelfde formularium met extra uitleg en geheugensteuntjes. Die versie is uitgebreider en handig om de leerstof in te studeren, terwijl dit document specifiek geoptimaliseerd is om compact en examengeschikt te blijven, zonder uitleg. Inhoud: - Lists, tuples en dictionaries - Stringmethodes - Bestandverwerking - Operatoren en logica - math- en random-functies - Indexering en slicing

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format(number, ‘a,.bc’) [‘list’]
math.cos() type(object) append(item)
math.tan() count(item)
len(object)
math.sin() index(item)
math.acos() insert(index,item)
math.atan() pop(index)
match parameter
math.asin() remove(item)
case pattern
math.floor(2.1) sort()
math.ceil(2.9) case _
reverse()
math.degrees(π/2) clear()
math.radrians(90) copy()
math.exp(e) extend()
math.log() def naam:
global var (‘tuple’)
math.log10() count(item)
math.sqrt() …
index(item)
return var
{‘key’:’value-dict’}
math.e
del dict[key]
math.inf
clear()
math.nan pass copy()
math.pi
fromkeys(keys,.value)
math.tau
items()
keys()
random.randrange([start],]stop[,stap) values()
random.randint([start],[stop]) get(key,default)
random.random() pop(key,default)
random.uniform([start],[stop]) popitem()
update()


range(start^=0 , stop=-1 , step^=1)


lst/tup[.[start]=0:.]stop[=-1:.step=1]
str()
isalnum()
isalpha()
bestand = open(‘bestandsnaam’,’r/w/a/x’) isascii()
read(aantal) isdigit()
readline() islower()
lijn = lijn.rstrip(‘\n’) isupper()
readlines(aantal) isspace()
write(tekst) startswith(str, start, end)
close() endswith(str, start, end)

lower()
upper()
capitalize()
+ lstrip(karakters)
\n
- rstrip(karakters)
\t
* strip(karakters)
\’
5/2 replace(oud,nieuw,max)
\”
5^/2 center(length,opvulling)
\\
5%2
5^*2 count(str,start,end)
< find(str,start,end)
> (not x) or (y and z) index(char,start,end)
not rindex(char,start,end)
< =
> = and
or teksttussen.join(tup/lst/str)
= = split(sep,max)
! = swapcase()
splitlines(keeplinebreaks)

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September 18, 2026
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