. . sinx 5 s :
Find }‘ml0 — numerically if it exists.
x -01 —0.01 -0.001 -0.0001 O 0.0001 0.001 0.01 0.1
F) -
O1
(O does not exist
O -2
O o
O 2
O
n : 3
Find the derivative of y = xcotx at x = Vi
w
\{fi'z Ca'll oC @ 'TT('
Y= dv tuv’
u=2 v'-[
& (469” y= (ohx v's "HICX
OO
o [t + X- eset =
-esdtRt a%
(ot
CdCL\ ~ (s¢* [T)
OO
\%
O
O
Find the derivative of
‘{\ (13 éf_‘.?) (g.mi - CDS.'L>
f(x) = (e* + 3)(sin x — cos x).
\ll': e = (082 - C
_ $iu )
u'v + UV'
O
O
f(x) = e*(cosx +sinx)
f'(x) = e*(cos x —sinx)
4 (e*43) (@xt sn )
e“ (51&1— l‘°x>
O f'(x)=2sinx(e* +3) = M*Zgfl\ + 3loS3+ 35inoC.
O f(x) =2e*sinx +3cosx + 3sinx e’cSch‘fz;;x
O f'(x)=2¢*sinx Ne*sin X 4 Jeosx +3 SN
O f(x)=3cosx—3sinx
): _9«1-1' -I"f. +I
The function, s(t) = —2t? + t + 1, describes the position, in meters, of a moving particle on a straight line in terms
of time ¢, in hours. At what time does the particle stop? S+
-yt 11 = 0
O t=1hour
QO t=2hours
O t=1hour
QO t=2hours
QO t=2hour
QO t=1hour
prel = Yoot?- #ot AT
i
A population of ants has the following population after ¢t months:
P(t) = 400t* — 756t + 587
What is the rate of change of the population after 2 months (in ants/month)?
yodt — 54
88
(P2 oo (1) - 356
> O OOO0
(600 ~356 7 344
1483
1265
325
e
, U 0/
O 844
uc.fl .
\‘-"’.4;1“““‘
For % P e o
x? =3, x< -2
f(x)={ —4x + 1, x> -2
Choose the correct statement(s) below.
L lim2 f(x) does not exist.
X——
IL. f(x) is continuous at x = —2, =¥ n"'..l' M ’}D cil'fi'
M. lim f)=1 -
(q >
S e
(O OnlyIandII are true
(O Only Lis true
<z ; Only I and III are true >
(O Only I is true
(O Only II and III are true &
<314 tWEZ>
(O Only Il is true
Given
f=
x> —5x+6
x2—T7x+12°
1c"=9cm‘—57t1"é
e
%™
SN
. :)_.1-1’1\_
YL [(L-3) (x4
}
which of the following are true?
5 hoe -
et= O
(a.) f(x) has a hole at x = 2.
cc-?"@(li)«‘“’] =t
(b.) f(x) has a vertical asymptote at x = 2.
(c.) f(x) has a hole at x = 3.
(d.) f(x) has a vertical asymptote at x = 3. A= E; ’7C
(e.) f(x) has ahole at x = 4.
(f.) f(x) has a vertical asymptote at x = 4. () (3 ]4
Vertical
M,h”“
O candd s
a 4(“"*3
o ‘9‘“9
O aandb
O dande
O bandc
O aandf
Find
xlin; x=3"
O o
O 2
=) O =
O1
O 1
[ Given p(t) = 3t +2 , find p’(25).k
Ve+2
Find }‘ml0 — numerically if it exists.
x -01 —0.01 -0.001 -0.0001 O 0.0001 0.001 0.01 0.1
F) -
O1
(O does not exist
O -2
O o
O 2
O
n : 3
Find the derivative of y = xcotx at x = Vi
w
\{fi'z Ca'll oC @ 'TT('
Y= dv tuv’
u=2 v'-[
& (469” y= (ohx v's "HICX
OO
o [t + X- eset =
-esdtRt a%
(ot
CdCL\ ~ (s¢* [T)
OO
\%
O
O
Find the derivative of
‘{\ (13 éf_‘.?) (g.mi - CDS.'L>
f(x) = (e* + 3)(sin x — cos x).
\ll': e = (082 - C
_ $iu )
u'v + UV'
O
O
f(x) = e*(cosx +sinx)
f'(x) = e*(cos x —sinx)
4 (e*43) (@xt sn )
e“ (51&1— l‘°x>
O f'(x)=2sinx(e* +3) = M*Zgfl\ + 3loS3+ 35inoC.
O f(x) =2e*sinx +3cosx + 3sinx e’cSch‘fz;;x
O f'(x)=2¢*sinx Ne*sin X 4 Jeosx +3 SN
O f(x)=3cosx—3sinx
): _9«1-1' -I"f. +I
The function, s(t) = —2t? + t + 1, describes the position, in meters, of a moving particle on a straight line in terms
of time ¢, in hours. At what time does the particle stop? S+
-yt 11 = 0
O t=1hour
QO t=2hours
O t=1hour
QO t=2hours
QO t=2hour
QO t=1hour
prel = Yoot?- #ot AT
i
A population of ants has the following population after ¢t months:
P(t) = 400t* — 756t + 587
What is the rate of change of the population after 2 months (in ants/month)?
yodt — 54
88
(P2 oo (1) - 356
> O OOO0
(600 ~356 7 344
1483
1265
325
e
, U 0/
O 844
uc.fl .
\‘-"’.4;1“““‘
For % P e o
x? =3, x< -2
f(x)={ —4x + 1, x> -2
Choose the correct statement(s) below.
L lim2 f(x) does not exist.
X——
IL. f(x) is continuous at x = —2, =¥ n"'..l' M ’}D cil'fi'
M. lim f)=1 -
(q >
S e
(O OnlyIandII are true
(O Only Lis true
<z ; Only I and III are true >
(O Only I is true
(O Only II and III are true &
<314 tWEZ>
(O Only Il is true
Given
f=
x> —5x+6
x2—T7x+12°
1c"=9cm‘—57t1"é
e
%™
SN
. :)_.1-1’1\_
YL [(L-3) (x4
}
which of the following are true?
5 hoe -
et= O
(a.) f(x) has a hole at x = 2.
cc-?"@(li)«‘“’] =t
(b.) f(x) has a vertical asymptote at x = 2.
(c.) f(x) has a hole at x = 3.
(d.) f(x) has a vertical asymptote at x = 3. A= E; ’7C
(e.) f(x) has ahole at x = 4.
(f.) f(x) has a vertical asymptote at x = 4. () (3 ]4
Vertical
M,h”“
O candd s
a 4(“"*3
o ‘9‘“9
O aandb
O dande
O bandc
O aandf
Find
xlin; x=3"
O o
O 2
=) O =
O1
O 1
[ Given p(t) = 3t +2 , find p’(25).k
Ve+2
