IRRSP Test with all Correct & 100% Verified Answers |
Actual Complete Update |Already Graded A+
The term "Curie" defines:
a. The exposure of a radioactive source
b. The intensity of a radioactive source
c. The activity of a radioactive source
d. The output of a radioactive source ✔Correct Answer-The activity of a radioactive source
Which of the following are symptoms of an acute extremity overexposure?
a. Nausea, vomiting, diarrhea
b. Fatigue, nausea, reddening of the skin
c. Diarrhea, blistering, loss of hair
d. Reddening of the skin, loss of hair, blistering ✔Correct Answer-Reddening of the skin, loss
of hair, blistering
The reason the gamma radiation emitted from a Cobalt-60 source is more penetrating than the
gamma radiation emitted from Iridium-192 is due to the:
a. Higher output per Curie from the Co-60
b. Longer half life of the Co-60
c. Greater intensity from the Co-60
d. Higher gamma ray energy from the Co-60 ✔Correct Answer-Higher gamma ray energy from
the Co-60
A 0.400 inch piece of lead shielding will reduce the radiation intensity from an Iridium-192
source by:
a. 3/4
b. 1/2
c. 1/4
d. 1/8 ✔Correct Answer-3/4
When shielding against high-energy gamma rays, which of the following characteristics provide
the most effective shield?
a. Thick section of material
b. Thick section of high atomic number material
c. Thick section of low atomic number material
d. Thick section of low density material ✔Correct Answer-Thick section of high atomic
number material
The radiation intensity at 1 foot from an Iridium-192 source is 452.4 R/hr. What is the radiation
intensity at 14 feet?
a. 2.31 R/hr
, b. 226.2 R/hr
c. 113.1 R/hr
d. 32.3 R/hr ✔Correct Answer-2.31 R/hr
Gamma radiation can be defined as:
(Answer with A, B, C, or D)
a. Particles having the mass and charge of two protons and two neutrons emitted from the
nucleus of an unstable atom
b. Very light negatively charged particles emitted from the nucleus of an unstable atom
c. Very short wavelength electromagnetic radiation emitted from the nucleus of an unstable
atom
d. Particles emitted from an unstable atom with an energy in the range of 1 to 10 M.E.V.
✔Correct Answer-C
The term that describes how gamma or x-rays are reduced in intensity when passing through
shielding material is:
a. Penetration
b. Scatter
c. Reflection
d. Attenuation ✔Correct Answer-Attenuation
The annual radiation exposure limits for a radiographer or an assistant can be summarized by:
a. 1.25 Rem to the whole body, 18.75 Rem to the extremities
b. 20 Rem to the whole body, 200 Rem to the extremities
c. 5 mRem to the whole body, 50 mRem to the extremities
d. 5 Rem to the whole body, 50 Rem to the extremities ✔Correct Answer-5 Rem to the whole
body, 50 Rem to the extremities
A 50 Curie Cobalt-60 source has decayed 4 half lives. What is the remaining activity?
a. 6.25 Curies
b. 3.125 Curies
c. 0.195 Curies
d. 1.56 Curies ✔Correct Answer-3.125 Curies
The radiation intensity from a point source is inversely proportional to the square of the
distance from the source. This is known as:
a. Inverse Square Law
b. Linear Absorption Coefficient
c. Photoelectric Attenuation Process
d. Ohm's Law ✔Correct Answer-Inverse Square Law
The thickness of shielding material required to reduce a radiation intensity to one-half it's
original value is known as the:
a. Tenth value layer
Actual Complete Update |Already Graded A+
The term "Curie" defines:
a. The exposure of a radioactive source
b. The intensity of a radioactive source
c. The activity of a radioactive source
d. The output of a radioactive source ✔Correct Answer-The activity of a radioactive source
Which of the following are symptoms of an acute extremity overexposure?
a. Nausea, vomiting, diarrhea
b. Fatigue, nausea, reddening of the skin
c. Diarrhea, blistering, loss of hair
d. Reddening of the skin, loss of hair, blistering ✔Correct Answer-Reddening of the skin, loss
of hair, blistering
The reason the gamma radiation emitted from a Cobalt-60 source is more penetrating than the
gamma radiation emitted from Iridium-192 is due to the:
a. Higher output per Curie from the Co-60
b. Longer half life of the Co-60
c. Greater intensity from the Co-60
d. Higher gamma ray energy from the Co-60 ✔Correct Answer-Higher gamma ray energy from
the Co-60
A 0.400 inch piece of lead shielding will reduce the radiation intensity from an Iridium-192
source by:
a. 3/4
b. 1/2
c. 1/4
d. 1/8 ✔Correct Answer-3/4
When shielding against high-energy gamma rays, which of the following characteristics provide
the most effective shield?
a. Thick section of material
b. Thick section of high atomic number material
c. Thick section of low atomic number material
d. Thick section of low density material ✔Correct Answer-Thick section of high atomic
number material
The radiation intensity at 1 foot from an Iridium-192 source is 452.4 R/hr. What is the radiation
intensity at 14 feet?
a. 2.31 R/hr
, b. 226.2 R/hr
c. 113.1 R/hr
d. 32.3 R/hr ✔Correct Answer-2.31 R/hr
Gamma radiation can be defined as:
(Answer with A, B, C, or D)
a. Particles having the mass and charge of two protons and two neutrons emitted from the
nucleus of an unstable atom
b. Very light negatively charged particles emitted from the nucleus of an unstable atom
c. Very short wavelength electromagnetic radiation emitted from the nucleus of an unstable
atom
d. Particles emitted from an unstable atom with an energy in the range of 1 to 10 M.E.V.
✔Correct Answer-C
The term that describes how gamma or x-rays are reduced in intensity when passing through
shielding material is:
a. Penetration
b. Scatter
c. Reflection
d. Attenuation ✔Correct Answer-Attenuation
The annual radiation exposure limits for a radiographer or an assistant can be summarized by:
a. 1.25 Rem to the whole body, 18.75 Rem to the extremities
b. 20 Rem to the whole body, 200 Rem to the extremities
c. 5 mRem to the whole body, 50 mRem to the extremities
d. 5 Rem to the whole body, 50 Rem to the extremities ✔Correct Answer-5 Rem to the whole
body, 50 Rem to the extremities
A 50 Curie Cobalt-60 source has decayed 4 half lives. What is the remaining activity?
a. 6.25 Curies
b. 3.125 Curies
c. 0.195 Curies
d. 1.56 Curies ✔Correct Answer-3.125 Curies
The radiation intensity from a point source is inversely proportional to the square of the
distance from the source. This is known as:
a. Inverse Square Law
b. Linear Absorption Coefficient
c. Photoelectric Attenuation Process
d. Ohm's Law ✔Correct Answer-Inverse Square Law
The thickness of shielding material required to reduce a radiation intensity to one-half it's
original value is known as the:
a. Tenth value layer
