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Portage Learning CHEM 104 – General Chemistry II with Lab: 250+ Multiple-Choice Exam Questions & Detailed Rationales | Already Graded A+ | 100% Verified Solutions | Updated Per Latest Guidelines | 2026–2027 Edition | Aligned with Latest Portage Learning C

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Ace Portage Learning CHEM 104: General Chemistry II with Lab using this comprehensive 2026–2027 exam bank. Includes 250+ multiple-choice questions with detailed rationales and 100% verified solutions. Covers solutions, solubility & colligative properties; chemical kinetics & rate laws; equilibrium & Le Chatelier’s principle; acid-base equilibria, buffers & titration curves; Ksp; thermochemistry & thermodynamics; electrochemistry & redox; organic chemistry; biochemistry; nuclear & coordination chemistry; and laboratory techniques & calculations. Already graded A+ and aligned with the latest Portage Learning curriculum. Perfect for exam review, self-testing, and mastering general chemistry II. Instant digital download.

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Page 1 of 159




DETAILED RATIONALES | ALREADY




LATEST PORTAGE LEARNING



TABLE OF CONTENTS



| Section | Topic | Question Range | Page |

|---------|-------|----------------|------|

| **I** | **Solutions, Solubility, and Colligative Properties** | Q1–Q30 |

| **II** | **Chemical Kinetics and Rate Laws** | Q31–Q60 |

| **III** | **Chemical Equilibrium and Le Chatelier's Principle** | Q61–Q90 |

| **IV** | **Acid-Base Equilibria, Buffers, and Titration Curves** | Q91–Q125 |

| **V** | **Solubility Equilibria (Ksp)** | Q126–Q145 |

| **VI** | **Thermochemistry and Thermodynamics** | Q146–Q175 |

| **VII** | **Electrochemistry and Redox Reactions** | Q176–Q205 |

| **VIII** | **Organic Chemistry: Structure, Nomenclature, and Reactions** | Q206–Q230 |

| **IX** | **Biochemistry: Carbohydrates, Lipids, Proteins, and Nucleic Acids** | Q231–Q250 |

| **X** | **Nuclear Chemistry and Coordination Chemistry** | Q251–Q265 |

| **XI** | **Laboratory Techniques and Calculations** | Q266–Q275 |

,Page 2 of 159

SECTION I: SOLUTIONS, SOLUBILITY, AND COLLIGATIVE PROPERTIES



### Q1

**Which of the following can serve as the solvent in a solution?**


A) Liquid only

B) Solid only

C) Gas only

D) All of the above



**CorreCt Answer: D**


**Rationale:** A solvent can exist in any state of matter. The solvent is the component of a
solution present in the greatest amount and determines the physical state of the solution. Liquid
solvents are most common (e.g., water in aqueous solutions), but solid solvents exist (e.g., brass,
where zinc dissolves in copper), and gas solvents exist (e.g., air, where nitrogen acts as the
solvent for oxygen and other gases).



---


### Q2

**A homogeneous mixture consists of 12% ethanol, 28% methanol, and 60% water. What is the
solvent?**


A) Ethanol

B) Methanol

C) Water
D) All of the above

,Page 3 of 159




**CorreCt Answer: C**


**Rationale:** The solvent is the component present in the greatest amount. Water
constitutes 60% of the mixture, making it the solvent. Ethanol and methanol are solutes dissolved
in water.



---


### Q3

**Which factor does NOT affect the solubility of a solid solute in water?**



A) Temperature

B) Pressure

C) Polarity of solute
D) Surface area of solute



**CorreCt Answer: B**


**Rationale:** Pressure has minimal effect on solid/liquid solubility. Henry's Law applies
mainly to gases. Temperature, solute polarity, and surface area all influence dissolution rates and
solubility for solids.



---



### Q4
**Calculate the molarity of a solution prepared by dissolving 58.5 g of NaCl in enough water to
make 500.0 mL of solution. (Molar mass NaCl = 58.5 g/mol)**

, Page 4 of 159



A) 1.0 M

B) 2.0 M

C) 0.5 M
D) 0.1 M



**CorreCt Answer: B**


**Rationale:** Moles = 58.5 g / 58.5 g/mol = 1.0 mol. M = 1.0 mol / 0.500 L = 2.0 M.


---



### Q5

**What is the molality of a solution containing 25.0 g of glucose (C₆H₁₂O₆, molar mass = 180.16
g/mol) dissolved in 200.0 g of water?**



A) 0.139 m

B) 0.694 m

C) 0.347 m

D) 1.25 m



**CorreCt Answer: B**


**Rationale:** Moles of glucose = 25.0 g / 180.16 g/mol = 0.1388 mol. Molality = moles of
solute / kg of solvent = 0.1388 mol / 0.200 kg = 0.694 m.


---

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