CWEA E&I Technologist Grade 1 —Q&A
CWEA
Electrical/Instrumentation Technologist Grade 1
Questions and Answers | Latest Update| Pass Guaranteed
1. A circuit has a source voltage of 120 V and a resistance of 24 ohms. What is the
current flowing in the circuit?
A. 2 A
B. 5 A
C. 12 A
D. 48 A
Answer: B
Rationale: Using Ohm's Law, I = V / R = 120 V / 24 ohms = 5 A. Ohm's Law is the
fundamental relationship between voltage, current, and resistance and is tested
extensively on the exam.
2. A heater draws 10 A at 240 V. What is the power consumed?
A. 24 W
B. 240 W
C. 2,400 W
D. 24,000 W
Answer: C
Rationale: Power (P) = V x I = 240 V x 10 A = 2,400 W. This is the basic power
formula used for sizing loads and circuit protection.
3. Three resistors of 10, 20, and 30 ohms are connected in series. What is the total
resistance?
A. 5.45 ohms
B. 20 ohms
C. 60 ohms
D. 600 ohms
Answer: C
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, CWEA E&I Technologist Grade 1 —Q&A
Rationale: In a series circuit, total resistance is the simple sum of all resistances: 10
+ 20 + 30 = 60 ohms. Current is the same through every component in a series circuit.
4. Two 10-ohm resistors are connected in parallel. What is the total resistance?
A. 2 ohms
B. 5 ohms
C. 10 ohms
D. 20 ohms
Answer: B
Rationale: For two equal resistors in parallel, Rtotal = R / n = = 5 ohms. Total
resistance in a parallel circuit is always less than the smallest individual resistor.
5. Kirchhoff's Current Law states that:
A. Voltage around a closed loop sums to zero
B. The sum of currents entering a node equals the sum of currents leaving that node
C. Current is inversely proportional to resistance
D. Power equals voltage times current
Answer: B
Rationale: Kirchhoff's Current Law (KCL) is based on conservation of charge: the
total current flowing into a junction must equal the total current flowing out of it.
6. Kirchhoff's Voltage Law states that:
A. The algebraic sum of all voltages around a closed loop equals zero
B. Current entering a node equals current leaving a node
C. Resistance in series circuits is additive
D. Voltage is inversely proportional to current
Answer: A
Rationale: Kirchhoff's Voltage Law (KVL) is based on conservation of energy: the
sum of the voltage rises and drops around any closed loop in a circuit must equal zero.
7. The unit of capacitance is the:
A. Henry
B. Farad
C. Ohm
D. Weber
Answer: B
Page 2 of 31
, CWEA E&I Technologist Grade 1 —Q&A
Rationale: Capacitance is measured in farads (F). Because a farad is a large unit,
most practical capacitors are rated in microfarads (uF) or picofarads (pF).
8. The unit of inductance is the:
A. Farad
B. Ohm
C. Henry
D. Tesla
Answer: C
Rationale: Inductance is measured in henries (H). Inductors oppose changes in
current, which is important in motor windings, transformers, and filter circuits.
9. A resistor has the color bands yellow, violet, orange, gold. What is its resistance?
A. 4.7 k-ohm +/-5%
B. 47 k-ohm +/-5%
C. 470 ohm +/-5%
D. 4.7 ohm +/-5%
Answer: B
Rationale: Yellow = 4, Violet = 7, Orange = x1,000 multiplier, Gold = 5% tolerance.
This gives 47 x 1,000 = 47,000 ohms (47 k-ohm) with a 5% tolerance.
10. Which of the following is the best example of an electrical insulator?
A. Copper
B. Aluminum
C. Rubber
D. Silver
Answer: C
Rationale: Rubber has very high electrical resistance and does not readily allow
current flow, making it a common insulating material for wire jacketing and
protective gloves. Copper, aluminum, and silver are all good conductors.
11. In the United States, the standard frequency for utility-supplied AC power is:
A. 25 Hz
B. 50 Hz
C. 60 Hz
D. 400 Hz
Answer: C
Page 3 of 31
, CWEA E&I Technologist Grade 1 —Q&A
Rationale: The standard utility power frequency in the United States is 60 Hz,
meaning the current alternates direction 60 times per second. Most of Europe and
Asia use 50 Hz.
12. Excessive voltage drop in a conductor is most often caused by:
A. Conductor sized too large for the load
B. Conductor resistance and length being excessive for the current carried
C. Too much insulation on the conductor
D. Low ambient temperature
Answer: B
Rationale: Voltage drop increases with conductor resistance, which increases with
conductor length and decreases with larger cross-sectional area. Undersized or
excessively long conductors carrying high current cause unacceptable voltage drop at
the load.
13. The primary purpose of equipment grounding is to:
A. Reduce voltage drop in the circuit
B. Provide a low-impedance path to clear a fault and protect personnel from shock
C. Increase circuit current capacity
D. Improve power factor
Answer: B
Rationale: Equipment grounding bonds non-current-carrying metal parts to earth and
provides a low-impedance return path so that, in the event of a fault, protective
devices operate quickly and touch voltage on the equipment enclosure is minimized.
14. A short circuit is best described as:
A. A break in the conductor that stops current flow
B. An unintended, low-resistance path that causes excessive current flow
C. A circuit with too much resistance
D. A normal condition in a properly loaded circuit
Answer: B
Rationale: A short circuit occurs when current bypasses the intended load through a
path of abnormally low resistance, resulting in very high current flow that can
damage equipment or start a fire if not cleared quickly by protective devices.
15. An open circuit is best described as:
A. A path of zero resistance
B. A break in the current path that stops current flow entirely
Page 4 of 31
CWEA
Electrical/Instrumentation Technologist Grade 1
Questions and Answers | Latest Update| Pass Guaranteed
1. A circuit has a source voltage of 120 V and a resistance of 24 ohms. What is the
current flowing in the circuit?
A. 2 A
B. 5 A
C. 12 A
D. 48 A
Answer: B
Rationale: Using Ohm's Law, I = V / R = 120 V / 24 ohms = 5 A. Ohm's Law is the
fundamental relationship between voltage, current, and resistance and is tested
extensively on the exam.
2. A heater draws 10 A at 240 V. What is the power consumed?
A. 24 W
B. 240 W
C. 2,400 W
D. 24,000 W
Answer: C
Rationale: Power (P) = V x I = 240 V x 10 A = 2,400 W. This is the basic power
formula used for sizing loads and circuit protection.
3. Three resistors of 10, 20, and 30 ohms are connected in series. What is the total
resistance?
A. 5.45 ohms
B. 20 ohms
C. 60 ohms
D. 600 ohms
Answer: C
Page 1 of 31
, CWEA E&I Technologist Grade 1 —Q&A
Rationale: In a series circuit, total resistance is the simple sum of all resistances: 10
+ 20 + 30 = 60 ohms. Current is the same through every component in a series circuit.
4. Two 10-ohm resistors are connected in parallel. What is the total resistance?
A. 2 ohms
B. 5 ohms
C. 10 ohms
D. 20 ohms
Answer: B
Rationale: For two equal resistors in parallel, Rtotal = R / n = = 5 ohms. Total
resistance in a parallel circuit is always less than the smallest individual resistor.
5. Kirchhoff's Current Law states that:
A. Voltage around a closed loop sums to zero
B. The sum of currents entering a node equals the sum of currents leaving that node
C. Current is inversely proportional to resistance
D. Power equals voltage times current
Answer: B
Rationale: Kirchhoff's Current Law (KCL) is based on conservation of charge: the
total current flowing into a junction must equal the total current flowing out of it.
6. Kirchhoff's Voltage Law states that:
A. The algebraic sum of all voltages around a closed loop equals zero
B. Current entering a node equals current leaving a node
C. Resistance in series circuits is additive
D. Voltage is inversely proportional to current
Answer: A
Rationale: Kirchhoff's Voltage Law (KVL) is based on conservation of energy: the
sum of the voltage rises and drops around any closed loop in a circuit must equal zero.
7. The unit of capacitance is the:
A. Henry
B. Farad
C. Ohm
D. Weber
Answer: B
Page 2 of 31
, CWEA E&I Technologist Grade 1 —Q&A
Rationale: Capacitance is measured in farads (F). Because a farad is a large unit,
most practical capacitors are rated in microfarads (uF) or picofarads (pF).
8. The unit of inductance is the:
A. Farad
B. Ohm
C. Henry
D. Tesla
Answer: C
Rationale: Inductance is measured in henries (H). Inductors oppose changes in
current, which is important in motor windings, transformers, and filter circuits.
9. A resistor has the color bands yellow, violet, orange, gold. What is its resistance?
A. 4.7 k-ohm +/-5%
B. 47 k-ohm +/-5%
C. 470 ohm +/-5%
D. 4.7 ohm +/-5%
Answer: B
Rationale: Yellow = 4, Violet = 7, Orange = x1,000 multiplier, Gold = 5% tolerance.
This gives 47 x 1,000 = 47,000 ohms (47 k-ohm) with a 5% tolerance.
10. Which of the following is the best example of an electrical insulator?
A. Copper
B. Aluminum
C. Rubber
D. Silver
Answer: C
Rationale: Rubber has very high electrical resistance and does not readily allow
current flow, making it a common insulating material for wire jacketing and
protective gloves. Copper, aluminum, and silver are all good conductors.
11. In the United States, the standard frequency for utility-supplied AC power is:
A. 25 Hz
B. 50 Hz
C. 60 Hz
D. 400 Hz
Answer: C
Page 3 of 31
, CWEA E&I Technologist Grade 1 —Q&A
Rationale: The standard utility power frequency in the United States is 60 Hz,
meaning the current alternates direction 60 times per second. Most of Europe and
Asia use 50 Hz.
12. Excessive voltage drop in a conductor is most often caused by:
A. Conductor sized too large for the load
B. Conductor resistance and length being excessive for the current carried
C. Too much insulation on the conductor
D. Low ambient temperature
Answer: B
Rationale: Voltage drop increases with conductor resistance, which increases with
conductor length and decreases with larger cross-sectional area. Undersized or
excessively long conductors carrying high current cause unacceptable voltage drop at
the load.
13. The primary purpose of equipment grounding is to:
A. Reduce voltage drop in the circuit
B. Provide a low-impedance path to clear a fault and protect personnel from shock
C. Increase circuit current capacity
D. Improve power factor
Answer: B
Rationale: Equipment grounding bonds non-current-carrying metal parts to earth and
provides a low-impedance return path so that, in the event of a fault, protective
devices operate quickly and touch voltage on the equipment enclosure is minimized.
14. A short circuit is best described as:
A. A break in the conductor that stops current flow
B. An unintended, low-resistance path that causes excessive current flow
C. A circuit with too much resistance
D. A normal condition in a properly loaded circuit
Answer: B
Rationale: A short circuit occurs when current bypasses the intended load through a
path of abnormally low resistance, resulting in very high current flow that can
damage equipment or start a fire if not cleared quickly by protective devices.
15. An open circuit is best described as:
A. A path of zero resistance
B. A break in the current path that stops current flow entirely
Page 4 of 31
