MASTER ELECTRICAL LICENSING EXAMINATION STUDY
GUIDE | LATEST UPDATE 2026/2027 | ACTUAL EXAM |
PRACTICE QUESTIONS AND ANSWERS | EXAM REVIEW |
100% CORRECT ANSWERS | GUARANTEED PASSING.
This comprehensive practice examination is designed for candidates preparing for electrical
licensing, certification, and professional credentialing examinations in the United States. The
assessment covers advanced electrical theory, National Electrical Code (NEC) compliance,
power distribution systems, motor controls, grounding and bonding requirements, branch
circuit and feeder calculations, overcurrent protection, hazardous locations, renewable energy
systems, and professional responsibilities. Each question is meticulously developed to mirror
the complexity and technical depth of actual licensing board examinations, allowing
candidates to assess their readiness, identify knowledge gaps, and strengthen their
preparation. The content reflects the 2026–2027 examination cycle and incorporates current
code requirements, industry standards, and practical field applications essential for
journeyman, master, contractor, and professional engineering licensure.
Table of Contents
1. Electrical Theory and Calculations
2. National Electrical Code Requirements
3. Grounding and Bonding
4. Branch Circuits and Feeders
5. Overcurrent Protection
6. Motors and Motor Controls
7. Transformers and Power Distribution
8. Hazardous Locations and Special Occupancies
9. Safety Procedures and Professional Responsibilities
1|Page
, 10. Renewable Energy and Emerging Technologies
1: A 480V, three-phase, 60Hz induction motor draws 124A at full load with a power factor of
0.82 lagging. What is the approximate true power consumed by the motor?
A) 59.5 kW
B) 84.6 kW
C) 103.1 kW
D) 148.2 kW
Correct Answer: B
True power for a three-phase system is calculated using P = √3 × V × I × PF. Substituting the
values: P = 1.732 × 480 × 124 × 0.82 = 84,600W or 84.6 kW. Option A uses the wrong formula
(V × I × PF without √3), option C uses apparent power, and option D neglects the power factor
entirely.
2: According to the National Electrical Code, what is the minimum working clearance required
in front of a 480V switchboard with exposed live parts on both sides of the working space, where
the voltage to ground is 277V and the condition is not guarded or enclosed?
A) 3 feet
B) 3 feet 6 inches
C) 4 feet
D) 5 feet
Correct Answer: C
NEC Table 110.26(A)(1) specifies working clearances based on voltage to ground and
conditions. For 277V to ground, Condition 2 (exposed live parts on one side and grounded
parts on the other) requires 3 feet 6 inches, but Condition 3 (exposed live parts on both sides)
requires 4 feet. Since the question states exposed live parts on both sides, 4 feet is correct.
2|Page
,3: In a parallel circuit containing a 12Ω resistor and an 18Ω resistor connected across a 120V
source, what is the total current supplied by the source?
A) 4.0A
B) 6.67A
C) 10.0A
D) 16.67A
Correct Answer: D
The total resistance of parallel resistors is R_total = (R1 × R2) / (R1 + R2) = (12 × 18) / 30 =
7.2Ω. Using Ohm's law, I = V / R = .2 = 16.67A. Option B incorrectly adds the
resistances, option A assumes series total, and option C is the sum of individual branch
currents if calculated incorrectly.
4: Which of the following best describes the function of a synchronous condenser in a power
distribution system?
A) To convert AC to DC for battery charging
B) To provide leading reactive power for voltage regulation
C) To protect transformers from overcurrent faults
D) To step up transmission voltage to distribution levels
Correct Answer: B
A synchronous condenser is a synchronous motor operated without mechanical load,
overexcited to supply leading reactive power (capacitive) to the system. This compensates for
lagging reactive power from inductive loads, improving power factor and voltage regulation.
Options A, C, and D describe rectifiers, protective relays, and step-up transformers
respectively.
3|Page
, 5: A single-phase transformer has a primary voltage of 7200V and a secondary voltage of 240V.
If the secondary current is 150A at unity power factor, what is the primary current, neglecting
losses?
A) 5A
B) 10A
C) 20A
D) 50A
Correct Answer: A
For an ideal transformer, the power is conserved: V_primary × I_primary = V_secondary ×
I_secondary. Thus I_primary = (240 × 150) / 7200 = 36, = 5A. Options B, C, and D
result from incorrect ratios or misuse of the turns ratio.
Page 2
6: What is the minimum size copper equipment grounding conductor required for a 200A
overcurrent protection device, according to the NEC?
A) 8 AWG
B) 6 AWG
C) 4 AWG
D) 2 AWG
Correct Answer: B
NEC Table 250.122 specifies the minimum size equipment grounding conductor based on the
rating of the overcurrent device ahead of the equipment. For a 200A OCPD, the minimum
copper EGC is 6 AWG. 8 AWG is for 100A, 4 AWG for 300A, and 2 AWG for 400A.
7: In a wye-connected three-phase system, the line-to-line voltage is 480V. What is the line-to-
neutral voltage?
4|Page
GUIDE | LATEST UPDATE 2026/2027 | ACTUAL EXAM |
PRACTICE QUESTIONS AND ANSWERS | EXAM REVIEW |
100% CORRECT ANSWERS | GUARANTEED PASSING.
This comprehensive practice examination is designed for candidates preparing for electrical
licensing, certification, and professional credentialing examinations in the United States. The
assessment covers advanced electrical theory, National Electrical Code (NEC) compliance,
power distribution systems, motor controls, grounding and bonding requirements, branch
circuit and feeder calculations, overcurrent protection, hazardous locations, renewable energy
systems, and professional responsibilities. Each question is meticulously developed to mirror
the complexity and technical depth of actual licensing board examinations, allowing
candidates to assess their readiness, identify knowledge gaps, and strengthen their
preparation. The content reflects the 2026–2027 examination cycle and incorporates current
code requirements, industry standards, and practical field applications essential for
journeyman, master, contractor, and professional engineering licensure.
Table of Contents
1. Electrical Theory and Calculations
2. National Electrical Code Requirements
3. Grounding and Bonding
4. Branch Circuits and Feeders
5. Overcurrent Protection
6. Motors and Motor Controls
7. Transformers and Power Distribution
8. Hazardous Locations and Special Occupancies
9. Safety Procedures and Professional Responsibilities
1|Page
, 10. Renewable Energy and Emerging Technologies
1: A 480V, three-phase, 60Hz induction motor draws 124A at full load with a power factor of
0.82 lagging. What is the approximate true power consumed by the motor?
A) 59.5 kW
B) 84.6 kW
C) 103.1 kW
D) 148.2 kW
Correct Answer: B
True power for a three-phase system is calculated using P = √3 × V × I × PF. Substituting the
values: P = 1.732 × 480 × 124 × 0.82 = 84,600W or 84.6 kW. Option A uses the wrong formula
(V × I × PF without √3), option C uses apparent power, and option D neglects the power factor
entirely.
2: According to the National Electrical Code, what is the minimum working clearance required
in front of a 480V switchboard with exposed live parts on both sides of the working space, where
the voltage to ground is 277V and the condition is not guarded or enclosed?
A) 3 feet
B) 3 feet 6 inches
C) 4 feet
D) 5 feet
Correct Answer: C
NEC Table 110.26(A)(1) specifies working clearances based on voltage to ground and
conditions. For 277V to ground, Condition 2 (exposed live parts on one side and grounded
parts on the other) requires 3 feet 6 inches, but Condition 3 (exposed live parts on both sides)
requires 4 feet. Since the question states exposed live parts on both sides, 4 feet is correct.
2|Page
,3: In a parallel circuit containing a 12Ω resistor and an 18Ω resistor connected across a 120V
source, what is the total current supplied by the source?
A) 4.0A
B) 6.67A
C) 10.0A
D) 16.67A
Correct Answer: D
The total resistance of parallel resistors is R_total = (R1 × R2) / (R1 + R2) = (12 × 18) / 30 =
7.2Ω. Using Ohm's law, I = V / R = .2 = 16.67A. Option B incorrectly adds the
resistances, option A assumes series total, and option C is the sum of individual branch
currents if calculated incorrectly.
4: Which of the following best describes the function of a synchronous condenser in a power
distribution system?
A) To convert AC to DC for battery charging
B) To provide leading reactive power for voltage regulation
C) To protect transformers from overcurrent faults
D) To step up transmission voltage to distribution levels
Correct Answer: B
A synchronous condenser is a synchronous motor operated without mechanical load,
overexcited to supply leading reactive power (capacitive) to the system. This compensates for
lagging reactive power from inductive loads, improving power factor and voltage regulation.
Options A, C, and D describe rectifiers, protective relays, and step-up transformers
respectively.
3|Page
, 5: A single-phase transformer has a primary voltage of 7200V and a secondary voltage of 240V.
If the secondary current is 150A at unity power factor, what is the primary current, neglecting
losses?
A) 5A
B) 10A
C) 20A
D) 50A
Correct Answer: A
For an ideal transformer, the power is conserved: V_primary × I_primary = V_secondary ×
I_secondary. Thus I_primary = (240 × 150) / 7200 = 36, = 5A. Options B, C, and D
result from incorrect ratios or misuse of the turns ratio.
Page 2
6: What is the minimum size copper equipment grounding conductor required for a 200A
overcurrent protection device, according to the NEC?
A) 8 AWG
B) 6 AWG
C) 4 AWG
D) 2 AWG
Correct Answer: B
NEC Table 250.122 specifies the minimum size equipment grounding conductor based on the
rating of the overcurrent device ahead of the equipment. For a 200A OCPD, the minimum
copper EGC is 6 AWG. 8 AWG is for 100A, 4 AWG for 300A, and 2 AWG for 400A.
7: In a wye-connected three-phase system, the line-to-line voltage is 480V. What is the line-to-
neutral voltage?
4|Page
