FE Electrical and Computer Practice
Exam Questions And Correct Answers
(Verified Answers) Plus Rationales
2026 Q&A | Instant Download Pdf
1. A 12 V ideal voltage source is connected across a 6 Ω resistor.
What is the current through the resistor?
A. 0.5 A
B. 1 A
C. 2 A
D. 72 A
Answer: C. 2 A
Rationale: Ohm’s law gives I = V/R = 12/6 = 2 A. Therefore, the
current through the resistor is 2 A.
2. Two resistors of 4 Ω and 6 Ω are connected in series. What is their
equivalent resistance?
A. 10 Ω
B. 2.4 Ω
C. 24 Ω
D. 1.0 Ω
Answer: A. 10 Ω
Rationale: For series resistors, the equivalent resistance is the sum of
the individual resistances: R_eq = 4 + 6 = 10 Ω.
3. A 10 Ω resistor carries a current of 3 A. What power is dissipated
by the resistor?
,A. 30 W
B. 60 W
C. 90 W
D. 90 W
Answer: D. 90 W
Rationale: Resistor power is P = I²R. Thus P = (3 A)²(10 Ω) = 9 × 10 =
90 W.
4. A node has currents of 5 A and 2 A entering it. If 4 A leaves
through one branch, what current leaves through the remaining
branch?
A. 1 A
B. 3 A
C. 7 A
D. 11 A
Answer: B. 3 A
Rationale: Kirchhoff’s current law requires total current entering a
node to equal total current leaving. Thus 5 + 2 = 4 + I, giving I = 3 A.
5. A 24 V source is connected to a voltage divider consisting of 4 kΩ
and 8 kΩ resistors in series. What voltage appears across the 8 kΩ
resistor?
A. 6 V
B. 8 V
C. 16 V
D. 24 V
Answer: C. 16 V
,Rationale: The voltage-divider relation is V_out = V_in R₂/(R₁ + R₂).
Therefore V_out = 24(8/(4 + 8)) = 16 V.
6. An ideal capacitor has capacitance 20 μF and is charged to 50 V.
What charge is stored?
A. 1.0 mC
B. 0.4 mC
C. 2.5 mC
D. 1000 mC
Answer: A. 1.0 mC
Rationale: Capacitor charge is Q = CV. Thus Q = 20 × 10⁻⁶ × 50 = 1 ×
10⁻³ C = 1.0 mC.
7. An inductor has an inductance of 0.5 H and carries a current of 4
A. What energy is stored in the magnetic field?
A. 1 J
B. 2 J
C. 4 J
D. 4 J
Answer: D. 4 J
Rationale: Inductor energy is W = ½LI². Therefore W = ½(0.5)(4²) =
0.25 × 16 = 4 J.
8. What is the impedance of a 10 Ω resistor in series with a capacitor
having reactance of −j6 Ω?
A. 16 Ω
B. 10 − j6 Ω
C. 6 − j10 Ω
D. 10 + j6 Ω
, Answer: B. 10 − j6 Ω
Rationale: Series impedances add directly. The resistor contributes 10
Ω and the capacitor contributes −j6 Ω, producing Z = 10 − j6 Ω.
9. A sinusoidal voltage has a peak value of 170 V. What is its RMS
value?
A. 85 V
B. 170 V
C. 120.2 V
D. 240.4 V
Answer: C. 120.2 V
Rationale: For a sinusoid, V_RMS = V_peak/√2. Therefore 170/√2 ≈
120.2 V.
10. A 60 Hz AC circuit contains an inductor of 0.1 H. What is the
inductive reactance?
A. 6 Ω
B. 37.7 Ω
C. 60 Ω
D. 0.377 Ω
Answer: B. 37.7 Ω
Rationale: Inductive reactance is X_L = 2πfL. Thus X_L = 2π(60)(0.1)
≈ 37.7 Ω.
11. A capacitor has a capacitance of 100 μF and operates at 50
Hz. What is its capacitive reactance?
A. 3.18 Ω
B. 31.8 Ω
Exam Questions And Correct Answers
(Verified Answers) Plus Rationales
2026 Q&A | Instant Download Pdf
1. A 12 V ideal voltage source is connected across a 6 Ω resistor.
What is the current through the resistor?
A. 0.5 A
B. 1 A
C. 2 A
D. 72 A
Answer: C. 2 A
Rationale: Ohm’s law gives I = V/R = 12/6 = 2 A. Therefore, the
current through the resistor is 2 A.
2. Two resistors of 4 Ω and 6 Ω are connected in series. What is their
equivalent resistance?
A. 10 Ω
B. 2.4 Ω
C. 24 Ω
D. 1.0 Ω
Answer: A. 10 Ω
Rationale: For series resistors, the equivalent resistance is the sum of
the individual resistances: R_eq = 4 + 6 = 10 Ω.
3. A 10 Ω resistor carries a current of 3 A. What power is dissipated
by the resistor?
,A. 30 W
B. 60 W
C. 90 W
D. 90 W
Answer: D. 90 W
Rationale: Resistor power is P = I²R. Thus P = (3 A)²(10 Ω) = 9 × 10 =
90 W.
4. A node has currents of 5 A and 2 A entering it. If 4 A leaves
through one branch, what current leaves through the remaining
branch?
A. 1 A
B. 3 A
C. 7 A
D. 11 A
Answer: B. 3 A
Rationale: Kirchhoff’s current law requires total current entering a
node to equal total current leaving. Thus 5 + 2 = 4 + I, giving I = 3 A.
5. A 24 V source is connected to a voltage divider consisting of 4 kΩ
and 8 kΩ resistors in series. What voltage appears across the 8 kΩ
resistor?
A. 6 V
B. 8 V
C. 16 V
D. 24 V
Answer: C. 16 V
,Rationale: The voltage-divider relation is V_out = V_in R₂/(R₁ + R₂).
Therefore V_out = 24(8/(4 + 8)) = 16 V.
6. An ideal capacitor has capacitance 20 μF and is charged to 50 V.
What charge is stored?
A. 1.0 mC
B. 0.4 mC
C. 2.5 mC
D. 1000 mC
Answer: A. 1.0 mC
Rationale: Capacitor charge is Q = CV. Thus Q = 20 × 10⁻⁶ × 50 = 1 ×
10⁻³ C = 1.0 mC.
7. An inductor has an inductance of 0.5 H and carries a current of 4
A. What energy is stored in the magnetic field?
A. 1 J
B. 2 J
C. 4 J
D. 4 J
Answer: D. 4 J
Rationale: Inductor energy is W = ½LI². Therefore W = ½(0.5)(4²) =
0.25 × 16 = 4 J.
8. What is the impedance of a 10 Ω resistor in series with a capacitor
having reactance of −j6 Ω?
A. 16 Ω
B. 10 − j6 Ω
C. 6 − j10 Ω
D. 10 + j6 Ω
, Answer: B. 10 − j6 Ω
Rationale: Series impedances add directly. The resistor contributes 10
Ω and the capacitor contributes −j6 Ω, producing Z = 10 − j6 Ω.
9. A sinusoidal voltage has a peak value of 170 V. What is its RMS
value?
A. 85 V
B. 170 V
C. 120.2 V
D. 240.4 V
Answer: C. 120.2 V
Rationale: For a sinusoid, V_RMS = V_peak/√2. Therefore 170/√2 ≈
120.2 V.
10. A 60 Hz AC circuit contains an inductor of 0.1 H. What is the
inductive reactance?
A. 6 Ω
B. 37.7 Ω
C. 60 Ω
D. 0.377 Ω
Answer: B. 37.7 Ω
Rationale: Inductive reactance is X_L = 2πfL. Thus X_L = 2π(60)(0.1)
≈ 37.7 Ω.
11. A capacitor has a capacitance of 100 μF and operates at 50
Hz. What is its capacitive reactance?
A. 3.18 Ω
B. 31.8 Ω
