• Wrong document? Swap it for free
  • Written by students who passed
  • Immediately available after payment
  • Read online or as PDF
Sell
Where do you study
Your language
Document preview thumbnail
Preview 2 out of 13 pages
Exam (elaborations)

Dynamics Chapter 12

Document preview thumbnail
Preview 2 out of 13 pages

only a mass - CORRECT ANSWER-In dynamics, a particle is assumed to have _________. A) both translation and rotational motions B) only a mass C) a mass but the size and shape cannot be neglected D) no mass or size or shape, it is just a point sT/Δt - CORRECT ANSWER-The average speed is defined as __________. A) Δr/Δt B) Δs/Δt

Content preview

Dynamics Chapter 12 Questions and Answers 2025/2026




only a mass - CORRECT ANSWER-In dynamics, a particle is assumed to have _________.

A) both translation and rotational motions

B) only a mass

C) a mass but the size and shape cannot be neglected

D) no mass or size or shape, it is just a point



sT/Δt - CORRECT ANSWER-The average speed is defined as __________.

A) Δr/Δt

B) Δs/Δt

C) sT/Δt

D) None of the above.



1.6 m/s2 ← - CORRECT ANSWER-A particle moves along a horizontal path with its velocity
varying with time as shown. The average acceleration of the particle is _________.

A) 0.4 m/s2 → B) 0.4 m/s2 ←

C) 1.6 m/s2 → D) 1.6 m/s2 ←



0 ft/s



(Can we calculate average speed from this problem statement? No! We do not know the total
path distance) - CORRECT ANSWER-A particle has an initial velocity of 30 ft/s to the left. If it
then passes through the same location 5 seconds later with a velocity of 50 ft/s to the right, the
average velocity of the particle during the 5 s time interval is _______.

, A) 10 ft/s → B) 40 ft/s →

C) 16 m/s → D) 0 ft/s



0.0 ft



s = s0 + v0t + ½ at^2 ; s = (0) + (-3)(3) + .5(2)(3)^2 = -9 + 9 = 0 - CORRECT ANSWER-A particle has
an initial velocity of 3 ft/s to the left at

s0 = 0 ft. Determine its position when t = 3 s if the acceleration is 2 ft/s2 to the right.

A) 0.0 ft B) 6.0 ft ←

C) 18.0 ft → D) 9.0 ft →



100 ft



v^2 = v02 + 2ac(s - so); (30)^2 = (12)^2 + 2(3.78)(s - 0); s = 100 ft - CORRECT ANSWER-A particle
is moving with an initial velocity of v = 12 ft/s and constant acceleration of 3.78 ft/s2 in the
same direction as the velocity. Determine the distance the particle has traveled when the
velocity reaches 30 ft/s



A) 50 ft B) 100 ft C) 150 ft D) 200 ft



acceleration. - CORRECT ANSWER-The slope of a v-t graph at any instant represents
instantaneous

A) velocity. B) acceleration.

C) position. D) jerk.



v-t - CORRECT ANSWER-Displacement of a particle over a given time interval equals the area
under the ___ graph during that time.

A) a-t B) a-s

Document information

Uploaded on
August 30, 2026
Number of pages
13
Written in
2026/2027
Type
Exam (elaborations)
Contains
Questions & answers
$13.99

Wrong document? Swap it for free Within 14 days of purchase and before downloading, you can choose a different document. You can simply spend the amount again.
Written by students who passed
Immediately available after payment
Read online or as PDF

Sold
0
Followers
0
Items
226
Last sold
-



Why students choose Stuvia

Created by fellow students, verified by reviews

Quality you can trust: written by students who passed their tests and reviewed by others who've used these notes.

Didn't get what you expected? Choose another document

No worries! You can instantly pick a different document that better fits what you're looking for.

Pay as you like, start learning right away

No subscription, no commitments. Pay the way you're used to via credit card and download your PDF document instantly.

Student with book image

“Bought, downloaded, and aced it. It really can be that simple.”

Alisha Student

Working on your references?

Create accurate citations in APA, MLA and Harvard with our free citation generator.

Working on your references?

Frequently asked questions