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FE Civil Mathematics & Probability Practice Test 2027 Edition | Updated 2026–2027 Questions with Correct Answers & Detailed Rationales

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Prepare for the FE Civil Exam 2026–2027 with this updated Mathematics & Probability Practice Test 2027 Edition. Designed for comprehensive FE Civil preparation, this resource covers essential mathematical and probabilistic concepts, including algebra, equations, geometry, trigonometry, vectors, calculus, differential equations, statistics, probability, probability distributions, and engineering applications. Each question includes the correct answer and detailed rationale, helping you strengthen mathematical reasoning, improve calculation accuracy, identify knowledge gaps, and become more efficient with FE-style problems. Ideal for self-assessment, targeted review, mock-exam practice, and final preparation for the 2027 FE Civil examination.

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FE Civil Mathematics & Probability
Practice Test 2027 Edition | Updated
2026–27 Questions, Correct Answers &
Detailed Rationales


1. A function is defined by f(x)=x3−6x2+9x+4f(x)=x^3-6x^2+9x+4. At which
value of xx does the function have a local maximum?

A. 1
B. 2
C. 3
D. 4

Answer: x=1x=1

Rationale: The derivative is f′(x)=3x2−12x+9=3(x−1)(x−3)f'(x)=3x^2-12x+9=3(x-
1)(x-3). The derivative changes from positive to negative at x=1x=1, so x=1x=1 is
the local maximum.



2. Evaluate the definite integral

,∫02(3x2−4x+5) dx\int_0^2 (3x^2-4x+5)\,dx

A. 8
B. 10
C. 12
D. 14

Answer: 10

Rationale: The antiderivative is x3−2x2+5xx^3-2x^2+5x. Evaluating from 0 to 2
gives 8−8+10=108-8+10=10.



3. A civil engineering model uses y=Ce0.15xy=Ce^{0.15x}. If y=20y=20 when
x=0x=0, what is yy when x=10x=10?

A. 67.2
B. 78.4
C. 89.6
D. 94.8

Answer: 89.6

Rationale: Since C=20C=20,
y=20e0.15(10)=20e1.5≈89.6y=20e^{0.15(10)}=20e^{1.5}\approx89.6.



4. Find the solution to

ln⁡(x−2)+ln⁡(x+2)=ln⁡21\ln(x-2)+\ln(x+2)=\ln 21

A. 3
B. 4
C. 5
D. 6

Answer: x=5x=5

,Rationale: Combining logarithms gives ln⁡(x2−4)=ln⁡21\ln(x^2-4)=\ln21, so
x2=25x^2=25. Because x>2x>2, the valid solution is x=5x=5.



5. A matrix equation is

[2134][xy]=[718]\begin{bmatrix} 2&1\\ 3&4 \end{bmatrix}
\begin{bmatrix}x\\y\end{bmatrix} = \begin{bmatrix}7\\18\end{bmatrix}

What is xx?

A. 1
B. 2
C. 3
D. 4

Answer: 2

Rationale: The equations are 2x+y=72x+y=7 and 3x+4y=183x+4y=18. From the
first equation, y=7−2xy=7-2x. Substitution gives 3x+28−8x=183x+28-8x=18,
resulting in x=2x=2.



6. What is the magnitude of the vector v=6i−8j+3k\mathbf{v}=6\mathbf{i}-
8\mathbf{j}+3\mathbf{k}?

A. 9.22
B. 10.44
C. 11.00
D. 12.37

Answer: 10.44

Rationale: The magnitude is 62+(−8)2+32=109≈10.44\sqrt{6^2+(-
8)^2+3^2}=\sqrt{109}\approx10.44.

, 7. Two vectors are a=(3,−2,4)\mathbf{a}=(3,-2,4) and
b=(1,5,−2)\mathbf{b}=(1,5,-2). What is a⋅b\mathbf{a}\cdot\mathbf{b}?

A. -15
B. -5
C. 7
D. 15

Answer: -15

Rationale: The dot product is 3(1)+(−2)(5)+4(−2)=3−10−8=−153(1)+(-2)(5)+4(-
2)=3-10-8=-15.



8. Determine the eigenvalues of

A=[4123]A= \begin{bmatrix} 4&1\\ 2&3 \end{bmatrix}

A. 1 and 6
B. 2 and 5
C. 3 and 4
D. 2 and 7

Answer: 2 and 5

Rationale: The characteristic equation is (4−λ)(3−λ)−2=0(4-\lambda)(3-\lambda)-
2=0, which simplifies to λ2−7λ+10=0\lambda^2-7\lambda+10=0. Thus
λ=2,5\lambda=2,5.



9. A quantity is modeled by Q(t)=100(1−e−0.2t)Q(t)=100(1-e^{-0.2t}). What is
dQ/dtdQ/dt at t=5t=5?

A. 0.368
B. 7.358

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