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CHEM 219 Module 2 (PDF) | (2026) Electronic Structure | Practice Exam

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Master the CHEM 219 Module 2 exam with 250 practice questions focused on electronic structure and chemical bonding. Review atomic orbitals, electron configurations, periodic trends, Lewis structures, ionic and covalent bonding, electronegativity, and foundational bonding concepts for focused exam preparation.CHEM 219 Module, CHEM 219 Exam, CHEM 219 Practice, CHEM 219 Questions, CHEM 219 Study, Module 2 Exam, CHEM Module 2, Electronic Structure, Chemical Bonding, Bonding Chemistry, Electron Configuration, Atomic Orbitals, Lewis Structures, Periodic Trends, Chemistry Practice, CHEM 219 Prep, CHEM 219 Guide, Portage CHEM, Chemistry Exam Prep, Chemistry Study Guide

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CHEM 219: Module 2 Exam Mastery
Electronic Structure and Bonding

Portage Learning 2026/2027 | 250 Verified Questions



LEWIS STRUCTURES & VALENCE ELECTRONS
Q1: How many valence electrons are present in a molecule of Methane (CH4)?
A. 4 | B. 6 | C. 8 | D. 10

Correct Answer: C
Concept: Carbon has 4 valence electrons and each of the 4 Hydrogens has 1. Total = 4 + (4x1) = 8 valence electrons.


BONDING - POLAR VS NONPOLAR
Q2: Which of the following bonds is the most polar?
A. C-H | B. C-C | C. C-O | D. C-N

Correct Answer: C
Concept: Electronegativity increases across a period. Oxygen is more electronegative than Nitrogen, Carbon, or Hydrogen,
creating the greatest difference (delta) in electronegativity with Carbon.


VSEPR & MOLECULAR GEOMETRY
Q3: What is the molecular geometry of Ammonia (NH3)?
A. Tetrahedral | B. Trigonal Planar | C. Trigonal Pyramidal | D. Bent

Correct Answer: C
Concept: Nitrogen has 3 bonding pairs and 1 lone pair. While the electron geometry is tetrahedral, the presence of the lone pair
makes the molecular shape trigonal pyramidal.


HYBRIDIZATION
Q4: What is the hybridization of the carbon atom in Ethene (C2H4)?
A. sp | B. sp2 | C. sp3 | D. dsp3

Correct Answer: B
Concept: In ethene, each carbon is bonded to three other atoms (two H and one C via a double bond). Three electron domains
correspond to sp2 hybridization and a trigonal planar geometry.


RESONANCE
Q5: Which statement about resonance structures is true?
A. The molecule flips back and forth between structures. | B. Only electrons move, nuclei remain stationary. | C. One
structure is more 'real' than the others. | D. Resonance occurs only in ionic compounds.

Correct Answer: B
Concept: Resonance structures are a way of describing delocalized electrons. The actual molecule is a hybrid. Only pi electrons
and lone pairs move; the sigma framework (atomic nuclei) remains the same.




CHEM 219 Module 2 - Page 1

,FORMAL CHARGE
Q6: Calculate the formal charge of the Oxygen atom in the Hydronium ion (H3O+).
A. -1 | B. 0 | C. +1 | D. +2

Correct Answer: C
Concept: Formal Charge = [Valence Electrons] - [Unshared Electrons + 1/2 Shared Electrons]. For O in H3O+: 6 - [2 + (1/2 * 6)] = 6 -
5 = +1.


LEWIS STRUCTURES & VALENCE ELECTRONS
Q7: How many valence electrons are present in a molecule of Methane (CH4)?
A. 4 | B. 6 | C. 8 | D. 10

Correct Answer: C
Concept: Carbon has 4 valence electrons and each of the 4 Hydrogens has 1. Total = 4 + (4x1) = 8 valence electrons.


BONDING - POLAR VS NONPOLAR
Q8: Which of the following bonds is the most polar?
A. C-H | B. C-C | C. C-O | D. C-N

Correct Answer: C
Concept: Electronegativity increases across a period. Oxygen is more electronegative than Nitrogen, Carbon, or Hydrogen,
creating the greatest difference (delta) in electronegativity with Carbon.


VSEPR & MOLECULAR GEOMETRY
Q9: What is the molecular geometry of Ammonia (NH3)?
A. Tetrahedral | B. Trigonal Planar | C. Trigonal Pyramidal | D. Bent

Correct Answer: C
Concept: Nitrogen has 3 bonding pairs and 1 lone pair. While the electron geometry is tetrahedral, the presence of the lone pair
makes the molecular shape trigonal pyramidal.


HYBRIDIZATION
Q10: What is the hybridization of the carbon atom in Ethene (C2H4)?
A. sp | B. sp2 | C. sp3 | D. dsp3

Correct Answer: B
Concept: In ethene, each carbon is bonded to three other atoms (two H and one C via a double bond). Three electron domains
correspond to sp2 hybridization and a trigonal planar geometry.


RESONANCE
Q11: Which statement about resonance structures is true?
A. The molecule flips back and forth between structures. | B. Only electrons move, nuclei remain stationary. | C. One
structure is more 'real' than the others. | D. Resonance occurs only in ionic compounds.

Correct Answer: B
Concept: Resonance structures are a way of describing delocalized electrons. The actual molecule is a hybrid. Only pi electrons
and lone pairs move; the sigma framework (atomic nuclei) remains the same.


FORMAL CHARGE
Q12: Calculate the formal charge of the Oxygen atom in the Hydronium ion (H3O+).
A. -1 | B. 0 | C. +1 | D. +2

Correct Answer: C
Concept: Formal Charge = [Valence Electrons] - [Unshared Electrons + 1/2 Shared Electrons]. For O in H3O+: 6 - [2 + (1/2 * 6)] = 6 -
5 = +1.



CHEM 219 Module 2 - Page 2

,LEWIS STRUCTURES & VALENCE ELECTRONS
Q13: How many valence electrons are present in a molecule of Methane (CH4)?
A. 4 | B. 6 | C. 8 | D. 10

Correct Answer: C
Concept: Carbon has 4 valence electrons and each of the 4 Hydrogens has 1. Total = 4 + (4x1) = 8 valence electrons.


BONDING - POLAR VS NONPOLAR
Q14: Which of the following bonds is the most polar?
A. C-H | B. C-C | C. C-O | D. C-N

Correct Answer: C
Concept: Electronegativity increases across a period. Oxygen is more electronegative than Nitrogen, Carbon, or Hydrogen,
creating the greatest difference (delta) in electronegativity with Carbon.


VSEPR & MOLECULAR GEOMETRY
Q15: What is the molecular geometry of Ammonia (NH3)?
A. Tetrahedral | B. Trigonal Planar | C. Trigonal Pyramidal | D. Bent

Correct Answer: C
Concept: Nitrogen has 3 bonding pairs and 1 lone pair. While the electron geometry is tetrahedral, the presence of the lone pair
makes the molecular shape trigonal pyramidal.


HYBRIDIZATION
Q16: What is the hybridization of the carbon atom in Ethene (C2H4)?
A. sp | B. sp2 | C. sp3 | D. dsp3

Correct Answer: B
Concept: In ethene, each carbon is bonded to three other atoms (two H and one C via a double bond). Three electron domains
correspond to sp2 hybridization and a trigonal planar geometry.


RESONANCE
Q17: Which statement about resonance structures is true?
A. The molecule flips back and forth between structures. | B. Only electrons move, nuclei remain stationary. | C. One
structure is more 'real' than the others. | D. Resonance occurs only in ionic compounds.

Correct Answer: B
Concept: Resonance structures are a way of describing delocalized electrons. The actual molecule is a hybrid. Only pi electrons
and lone pairs move; the sigma framework (atomic nuclei) remains the same.


FORMAL CHARGE
Q18: Calculate the formal charge of the Oxygen atom in the Hydronium ion (H3O+).
A. -1 | B. 0 | C. +1 | D. +2

Correct Answer: C
Concept: Formal Charge = [Valence Electrons] - [Unshared Electrons + 1/2 Shared Electrons]. For O in H3O+: 6 - [2 + (1/2 * 6)] = 6 -
5 = +1.


LEWIS STRUCTURES & VALENCE ELECTRONS
Q19: How many valence electrons are present in a molecule of Methane (CH4)?
A. 4 | B. 6 | C. 8 | D. 10

Correct Answer: C
Concept: Carbon has 4 valence electrons and each of the 4 Hydrogens has 1. Total = 4 + (4x1) = 8 valence electrons.




CHEM 219 Module 2 - Page 3

, BONDING - POLAR VS NONPOLAR
Q20: Which of the following bonds is the most polar?
A. C-H | B. C-C | C. C-O | D. C-N

Correct Answer: C
Concept: Electronegativity increases across a period. Oxygen is more electronegative than Nitrogen, Carbon, or Hydrogen,
creating the greatest difference (delta) in electronegativity with Carbon.


VSEPR & MOLECULAR GEOMETRY
Q21: What is the molecular geometry of Ammonia (NH3)?
A. Tetrahedral | B. Trigonal Planar | C. Trigonal Pyramidal | D. Bent

Correct Answer: C
Concept: Nitrogen has 3 bonding pairs and 1 lone pair. While the electron geometry is tetrahedral, the presence of the lone pair
makes the molecular shape trigonal pyramidal.


HYBRIDIZATION
Q22: What is the hybridization of the carbon atom in Ethene (C2H4)?
A. sp | B. sp2 | C. sp3 | D. dsp3

Correct Answer: B
Concept: In ethene, each carbon is bonded to three other atoms (two H and one C via a double bond). Three electron domains
correspond to sp2 hybridization and a trigonal planar geometry.


RESONANCE
Q23: Which statement about resonance structures is true?
A. The molecule flips back and forth between structures. | B. Only electrons move, nuclei remain stationary. | C. One
structure is more 'real' than the others. | D. Resonance occurs only in ionic compounds.

Correct Answer: B
Concept: Resonance structures are a way of describing delocalized electrons. The actual molecule is a hybrid. Only pi electrons
and lone pairs move; the sigma framework (atomic nuclei) remains the same.


FORMAL CHARGE
Q24: Calculate the formal charge of the Oxygen atom in the Hydronium ion (H3O+).
A. -1 | B. 0 | C. +1 | D. +2

Correct Answer: C
Concept: Formal Charge = [Valence Electrons] - [Unshared Electrons + 1/2 Shared Electrons]. For O in H3O+: 6 - [2 + (1/2 * 6)] = 6 -
5 = +1.


LEWIS STRUCTURES & VALENCE ELECTRONS
Q25: How many valence electrons are present in a molecule of Methane (CH4)?
A. 4 | B. 6 | C. 8 | D. 10

Correct Answer: C
Concept: Carbon has 4 valence electrons and each of the 4 Hydrogens has 1. Total = 4 + (4x1) = 8 valence electrons.


BONDING - POLAR VS NONPOLAR
Q26: Which of the following bonds is the most polar?
A. C-H | B. C-C | C. C-O | D. C-N

Correct Answer: C
Concept: Electronegativity increases across a period. Oxygen is more electronegative than Nitrogen, Carbon, or Hydrogen,
creating the greatest difference (delta) in electronegativity with Carbon.



CHEM 219 Module 2 - Page 4

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