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MARYLAND LOW VOLTAGE/SECURITY SYSTEMS LICENSE EXAM PRACTICE QUESTIONS AND CORRECT
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Review Summary 53 Questions
Foundations - Application - Maryland LOW Voltage/security Systems License AND Correct PLUS Rationale
2026/ Instant Download PDF LOW Voltage AND Security Systems Maryland State License Graduate /
Professional License Preparation
All answers with rationales
,Table of Contents
Content Area Questions Key Topics
General Knowledge AND 1-9 Circuit, System, Alarm, Power, Cable
Safety
LOW Voltage Systems 10-18 System, Cable, Circuit, Maximum, Installing
FIRE Alarm Systems 19-27 System, Video, Cable, Installing, Security
Security Systems 28-36 System, Cameras, Circuit, Minimum, Power
Telecommunications AND 37-45 System, Alarm, Security, Requires, Voltage
DATA Systems
National Electrical CODE 46-53 System, Alarm, Detector, Floor, Cable
NEC AND Regulations
TOTAL 53 All questions include answers and detailed rationales
,Section A - General Knowledge AND Safety
Q1.
A designer is specifying a Class 2 power-limited circuit for a network of IP cameras. The
circuit is routed through an environment where the ambient temperature is 55°C. The
cable is rated at 75°C and the ampacity correction factor is 0.71. If the connected load
draws 6.5A, what is the minimum required ampacity of the conductors before derating?
A. 9.15 A B. 10.5 A
C. 8.5 A D. 7.5 A
Correct: A - 9.15 A
Rationale:The ampacity after derating must be at least the load current (6.5A). Therefore, the
minimum ampacity before derating is 6.5A / 0.71 = 9.15A. This ensures the conductor's
capacity after derating meets the load.
Why the other answers are wrong:
B. This would be the result if you used a derating factor of 0.6 or added a safety margin
incorrectly.
C. This is the load current divided by 0.8, which is not the correct derating factor.
D. This is the load current without any derating, which would be insufficient at elevated
temperatures.
Reference: NFPA 70 (NEC) Article 310.15(B)(2)(a)
Q2.
In a Class A fire alarm initiating device circuit (IDC), a short circuit occurs between the
device and the panel. Which statement correctly describes the operation of the circuit?
A. The panel detects the short and B. The panel immediately shuts down the
continues to monitor devices beyond the entire circuit until the short is cleared.
fault via the return path.
C. The short causes the panel to enter D. The short is isolated by an end-of-line
alarm because it mimics an activation. resistor and the circuit continues normally.
Correct: A - The panel detects the short and continues to monitor devices beyond the fault
via the return path.
Rationale:Class A circuits are designed with a redundant return path. A single open or short
(to ground) causes the panel to switch to the alternate path, maintaining supervision of all
devices beyond the fault. This is a key requirement of NFPA 72 for survivability.
Why the other answers are wrong:
B. This describes a Class B circuit behavior, which does not have the redundant path.
Page 3
, Section A - General Knowledge AND Safety
C. A short does not necessarily cause an alarm; it is a trouble condition unless designed
otherwise.
D. End-of-line resistors are used for supervision, not for isolating shorts in Class A circuits.
Reference: NFPA 72, National Fire Alarm and Signaling Code, Section 12.3.6
Q3.
A security system integrator is designing an access control system for a facility that
requires fail-secure operation for a perimeter door. Which locking device should be
specified to meet this requirement during a power loss?
A. Electromagnetic lock B. Electric strike (fail-secure)
C. Electric strike (fail-safe) D. Electrified mortise lock (fail-safe)
Correct: B - Electric strike (fail-secure)
Rationale:A fail-secure electric strike remains locked when power is removed, ensuring
security during a power outage. Electromagnetic locks are fail-safe (unlock on power loss).
Fail-safe electric strikes unlock on power loss, which is not fail-secure.
Why the other answers are wrong:
C. Fail-safe electric strikes unlock on power loss, compromising security.
D. Fail-safe electrified mortise locks unlock on power loss, not fail-secure.
Reference: Access Control and Security Systems Integration, industry standard practice
Q4.
An IP video surveillance system uses Power over Ethernet (PoE) to power cameras. The
cameras require 12.95W, and the switch provides PoE+ (30W per port). The cable run is 90
meters. Which statement best describes the power delivery?
A. The camera will receive sufficient power B. The camera may not receive enough
because PoE+ delivers 30W at the switch power due to cable resistance voltage drop.
port.
C. The camera will receive exactly 12.95W D. The camera will not work because PoE+
because the switch negotiates the exact is not compatible with IP cameras.
power.
Correct: B - The camera may not receive enough power due to cable resistance voltage
drop.
Rationale:PoE power delivery is subject to cable resistance, causing voltage drop over long
runs. The switch provides up to 30W at the port, but the power available at the camera is
reduced. Standards ensure sufficient power for the class, but actual power can be lower due
to losses. Proper design must account for this.
Why the other answers are wrong:
Page 4