LADWP ELECTRIC METER SETTER
ELECTRICAL THEORY EXAM WITH
QUESTIONS AND VERIFIED ANSWERS,
PLUS DETAILED RATIONALES/EXPERT
VERIFIED FOR GUARANTEED PASS
2026/LATEST UPDATE/INSTANT
DOWNLOAD PDF
1. Ohm’s Law
A meter setter is evaluating a resistive control circuit supplied by 120
volts. The measured resistance of the load is 24 ohms. Assuming the
load behaves as a purely resistive circuit, what current should be
expected through the load?
A. 0.2 A
B. 2 A
C. 5 A
D. 24 A
Answer: C. 5 A
Rationale: Ohm’s Law states that I = V ÷ R. Therefore, I = 120 V ÷ 24
Ω = 5 A. The 2-A value would result from incorrectly dividing 48 V by
24 Ω, while 24 A would incorrectly treat resistance as current.
Understanding this relationship is fundamental when determining
whether a service or metering circuit is operating within expected
electrical limits.
2. Voltage, Current, and Resistance
Which statement most accurately describes electrical voltage?
1
,A. The opposition to current flow
B. The rate at which electrical energy is consumed
C. The electrical potential difference that drives current through a circuit
D. The quantity of electrons flowing through a conductor per second
Answer: C. The electrical potential difference that drives current
through a circuit
Rationale: Voltage is electrical potential difference, measured in volts,
and provides the electrical "pressure" that drives current through an
impedance or resistance. Resistance opposes current, power represents
the rate of energy transfer, and current represents the rate of charge
flow. Confusing these quantities can lead to incorrect circuit
calculations and unsafe assumptions about energized equipment.
3. Series Circuit Resistance
Three resistors of 10 Ω, 15 Ω, and 25 Ω are connected in series. What is
the total resistance?
A. 50 Ω
B. 37.5 Ω
C. 15 Ω
D. 2.4 Ω
Answer: A. 50 Ω
Rationale: In a series circuit, resistances add directly: Rtotal = R1 +
R2 + R3. Thus, 10 + 15 + 25 = 50 Ω. A series circuit has only one
current path, so the same current flows through each resistor.
4. Parallel Circuit Resistance
Two resistors, 12 Ω and 6 Ω, are connected in parallel across a voltage
source. What is the equivalent resistance?
2
,A. 18 Ω
B. 9 Ω
C. 4 Ω
D. 2 Ω
Answer: C. 4 Ω
Rationale: For two parallel resistors, Rtotal = (R1 × R2) ÷ (R1 + R2).
Therefore, (12 × 6) ÷ (12 + 6) = 72 ÷ 18 = 4 Ω. The equivalent
resistance of parallel resistors is always less than the smallest
individual branch resistance.
5. Effect of Resistance on Current
A 120-V load initially has a resistance of 20 Ω. The resistance increases
to 40 Ω while the supply voltage remains constant. What happens to the
current?
A. It doubles from 6 A to 12 A
B. It decreases from 6 A to 3 A
C. It remains at 6 A
D. It increases from 3 A to 6 A
Answer: B. It decreases from 6 A to 3 A
Rationale: Initially, I = 120 ÷ 20 = 6 A. After the resistance increases,
I = 120 ÷ 40 = 3 A. With voltage held constant, current is inversely
proportional to resistance. This principle is important when evaluating
changes in load behavior.
6. Electrical Power
A resistive load operates at 240 volts and draws 10 amperes. How much
real power does it consume?
3
, A. 24 W
B. 240 W
C. 1,200 W
D. 2,400 W
Answer: D. 2,400 W
Rationale: For a purely resistive load, P = V × I. Therefore, 240 × 10 =
2,400 watts, or 2.4 kW. Real power represents the rate at which
electrical energy is converted into useful work, heat, light, or another
form of energy.
7. Electrical Energy
A 2-kW load operates continuously for 5 hours. How much electrical
energy does it consume?
A. 0.4 kWh
B. 2 kWh
C. 7 kWh
D. 10 kWh
Answer: D. 10 kWh
Rationale: Energy in kilowatt-hours is calculated as power in kilowatts
multiplied by operating time in hours. Thus, 2 kW × 5 h = 10 kWh.
Electric energy meters fundamentally measure accumulated energy
consumption, making the distinction between kW and kWh
particularly important.
8. Conductors and Insulators
Which material is generally the best electrical conductor among the
following?
4
ELECTRICAL THEORY EXAM WITH
QUESTIONS AND VERIFIED ANSWERS,
PLUS DETAILED RATIONALES/EXPERT
VERIFIED FOR GUARANTEED PASS
2026/LATEST UPDATE/INSTANT
DOWNLOAD PDF
1. Ohm’s Law
A meter setter is evaluating a resistive control circuit supplied by 120
volts. The measured resistance of the load is 24 ohms. Assuming the
load behaves as a purely resistive circuit, what current should be
expected through the load?
A. 0.2 A
B. 2 A
C. 5 A
D. 24 A
Answer: C. 5 A
Rationale: Ohm’s Law states that I = V ÷ R. Therefore, I = 120 V ÷ 24
Ω = 5 A. The 2-A value would result from incorrectly dividing 48 V by
24 Ω, while 24 A would incorrectly treat resistance as current.
Understanding this relationship is fundamental when determining
whether a service or metering circuit is operating within expected
electrical limits.
2. Voltage, Current, and Resistance
Which statement most accurately describes electrical voltage?
1
,A. The opposition to current flow
B. The rate at which electrical energy is consumed
C. The electrical potential difference that drives current through a circuit
D. The quantity of electrons flowing through a conductor per second
Answer: C. The electrical potential difference that drives current
through a circuit
Rationale: Voltage is electrical potential difference, measured in volts,
and provides the electrical "pressure" that drives current through an
impedance or resistance. Resistance opposes current, power represents
the rate of energy transfer, and current represents the rate of charge
flow. Confusing these quantities can lead to incorrect circuit
calculations and unsafe assumptions about energized equipment.
3. Series Circuit Resistance
Three resistors of 10 Ω, 15 Ω, and 25 Ω are connected in series. What is
the total resistance?
A. 50 Ω
B. 37.5 Ω
C. 15 Ω
D. 2.4 Ω
Answer: A. 50 Ω
Rationale: In a series circuit, resistances add directly: Rtotal = R1 +
R2 + R3. Thus, 10 + 15 + 25 = 50 Ω. A series circuit has only one
current path, so the same current flows through each resistor.
4. Parallel Circuit Resistance
Two resistors, 12 Ω and 6 Ω, are connected in parallel across a voltage
source. What is the equivalent resistance?
2
,A. 18 Ω
B. 9 Ω
C. 4 Ω
D. 2 Ω
Answer: C. 4 Ω
Rationale: For two parallel resistors, Rtotal = (R1 × R2) ÷ (R1 + R2).
Therefore, (12 × 6) ÷ (12 + 6) = 72 ÷ 18 = 4 Ω. The equivalent
resistance of parallel resistors is always less than the smallest
individual branch resistance.
5. Effect of Resistance on Current
A 120-V load initially has a resistance of 20 Ω. The resistance increases
to 40 Ω while the supply voltage remains constant. What happens to the
current?
A. It doubles from 6 A to 12 A
B. It decreases from 6 A to 3 A
C. It remains at 6 A
D. It increases from 3 A to 6 A
Answer: B. It decreases from 6 A to 3 A
Rationale: Initially, I = 120 ÷ 20 = 6 A. After the resistance increases,
I = 120 ÷ 40 = 3 A. With voltage held constant, current is inversely
proportional to resistance. This principle is important when evaluating
changes in load behavior.
6. Electrical Power
A resistive load operates at 240 volts and draws 10 amperes. How much
real power does it consume?
3
, A. 24 W
B. 240 W
C. 1,200 W
D. 2,400 W
Answer: D. 2,400 W
Rationale: For a purely resistive load, P = V × I. Therefore, 240 × 10 =
2,400 watts, or 2.4 kW. Real power represents the rate at which
electrical energy is converted into useful work, heat, light, or another
form of energy.
7. Electrical Energy
A 2-kW load operates continuously for 5 hours. How much electrical
energy does it consume?
A. 0.4 kWh
B. 2 kWh
C. 7 kWh
D. 10 kWh
Answer: D. 10 kWh
Rationale: Energy in kilowatt-hours is calculated as power in kilowatts
multiplied by operating time in hours. Thus, 2 kW × 5 h = 10 kWh.
Electric energy meters fundamentally measure accumulated energy
consumption, making the distinction between kW and kWh
particularly important.
8. Conductors and Insulators
Which material is generally the best electrical conductor among the
following?
4
