Page 1 of 76
PRINCIPLES OF RADIOGRAPHIC IMAGING: AN ART AND A
SCIENCE, 6TH EDITION QUESTIONS 2026 ACTUAL EXAM
LATEST VERSION QUESTIONS AND ANSWERS 2026 EDITION
Principles of Radiographic Imaging: An Art and a Science, 6th Edition Exam
PART I: RADIOGRAPHIC PRINCIPLES AND MATHEMATICAL FOUNDATIONS
1. What is the first step in converting a fraction to its decimal equivalent in
radiographic calculations?
A) Multiplying the numerator by the denominator
B) Dividing the numerator by the denominator
C) Adding the numerator and denominator
D) Finding the lowest common denominator
Answer: B
Rationale: Transforming a fraction into its decimal equivalent involves dividing the
numerator by the denominator . This is a fundamental mathematical skill needed for
radiographic calculations involving exposure factors and measurements.
2. When converting 0.75 to a percentage, what is the correct result?
A) 0.75%
B) 7.5%
C) 75%
D) 750%
Answer: C
Rationale: To convert a decimal to a percentage, multiply the decimal by 100 . 0.75 ×
100 = 75%. This calculation is frequently used in radiographic quality assurance and
statistical analysis.
, Page 2 of 76
3. What is the product of the fractions 2/3 and 3/4?
A) 1/2
B) 5/12
C) 6/12
D) 1/3
Answer: A
Rationale: Multiplying fractions involves finding the product of two fractions . 2/3 × 3/4
= (2×3)/(3×4) = 6/12 = 1/2. This skill is used in radiographic calculations involving
exposure time and other factors.
4. What is 74 kilovolts expressed in volts?
A) 74 V
B) 740 V
C) 7,400 V
D) 74,000 V
Answer: D
Rationale: 1 kV = 1,000 volts, so 74 kV = 74,000 V . Kilovolt to volt conversion is
essential in radiography for understanding X-ray tube potential.
5. What is 400 milliamperes expressed in amperes?
A) 0.04 A
B) 0.40 A
C) 4.00 A
D) 40.0 A
Answer: B
Rationale: 1,000 mA = 1 A, so 400 mA = 0.40 A . Understanding milliampere to ampere
conversion is critical for tube current settings.
6. If 120,000 V is converted to kilovolt peak, what is the result?
A) 12 kVp
B) 120 kVp
, Page 3 of 76
C) 1,200 kVp
D) 12,000 kVp
Answer: B
Rationale: 1 kVp = 1,000 V; 120,000 V = 120 kVp . Kilovolt peak is a key exposure factor
in radiographic imaging.
7. What is 3.7 meters expressed in centimeters?
A) 37 cm
B) 370 cm
C) 3,700 cm
D) 37,000 cm
Answer: B
Rationale: 1 m = 100 cm; 3.7 m = 370 cm . Distance measurements are critical for
source-to-image distance (SID) and object-to-image distance (OID).
8. The density of mercury is 13.6 g/cm³. This refers to which physical property?
A) The mass per unit volume of mercury
B) The volume per unit mass of mercury
C) The temperature of mercury
D) The pressure of mercury
Answer: A
Rationale: Density is mass per unit volume . Mercury's density of 13.6 g/cm³ is
significant in radiography for understanding radiation attenuation properties of
materials.
9. What is the formula for converting Fahrenheit to Celsius?
A) °C = (°F - 32) × 5/9
B) °C = (°F + 32) × 9/5
C) °C = (°F × 9/5) + 32
D) °C = (°F × 5/9) - 32
Answer: A
, Page 4 of 76
Rationale: The correct formula for converting Fahrenheit to Celsius is °C = (°F - 32) ×
5/9 . Temperature conversions are important in film processing and equipment
maintenance.
10. What is the equation for a perfect square?
A) x² - 2xy + y² = (x - y)²
B) x² + 2xy + y² = (x + y)²
C) Both A and B
D) Neither A nor B
Answer: C
Rationale: The equations of perfect squares are: x² + 2xy + y² = (x + y)² and x² - 2xy + y² =
(x - y)² . Understanding perfect squares is important in inverse square law calculations.
11. If x = ay/bd, what happens to x when b is increased?
A) x increases
B) x decreases
C) x remains the same
D) x becomes negative
Answer: B
Rationale: Increasing b decreases the value of x in the proportional relationship x =
ay/bd . This mathematical concept relates to how changing exposure factors affects
image characteristics.
12. If x = ay/bd, what happens to x when d is decreased?
A) x increases
B) x decreases
C) x remains the same
D) x becomes negative
Answer: A
Rationale: Decreasing d increases the value of x . This concept applies to
understanding how changes in distance affect exposure and image quality.
13. What is the volume of a cone formula?
PRINCIPLES OF RADIOGRAPHIC IMAGING: AN ART AND A
SCIENCE, 6TH EDITION QUESTIONS 2026 ACTUAL EXAM
LATEST VERSION QUESTIONS AND ANSWERS 2026 EDITION
Principles of Radiographic Imaging: An Art and a Science, 6th Edition Exam
PART I: RADIOGRAPHIC PRINCIPLES AND MATHEMATICAL FOUNDATIONS
1. What is the first step in converting a fraction to its decimal equivalent in
radiographic calculations?
A) Multiplying the numerator by the denominator
B) Dividing the numerator by the denominator
C) Adding the numerator and denominator
D) Finding the lowest common denominator
Answer: B
Rationale: Transforming a fraction into its decimal equivalent involves dividing the
numerator by the denominator . This is a fundamental mathematical skill needed for
radiographic calculations involving exposure factors and measurements.
2. When converting 0.75 to a percentage, what is the correct result?
A) 0.75%
B) 7.5%
C) 75%
D) 750%
Answer: C
Rationale: To convert a decimal to a percentage, multiply the decimal by 100 . 0.75 ×
100 = 75%. This calculation is frequently used in radiographic quality assurance and
statistical analysis.
, Page 2 of 76
3. What is the product of the fractions 2/3 and 3/4?
A) 1/2
B) 5/12
C) 6/12
D) 1/3
Answer: A
Rationale: Multiplying fractions involves finding the product of two fractions . 2/3 × 3/4
= (2×3)/(3×4) = 6/12 = 1/2. This skill is used in radiographic calculations involving
exposure time and other factors.
4. What is 74 kilovolts expressed in volts?
A) 74 V
B) 740 V
C) 7,400 V
D) 74,000 V
Answer: D
Rationale: 1 kV = 1,000 volts, so 74 kV = 74,000 V . Kilovolt to volt conversion is
essential in radiography for understanding X-ray tube potential.
5. What is 400 milliamperes expressed in amperes?
A) 0.04 A
B) 0.40 A
C) 4.00 A
D) 40.0 A
Answer: B
Rationale: 1,000 mA = 1 A, so 400 mA = 0.40 A . Understanding milliampere to ampere
conversion is critical for tube current settings.
6. If 120,000 V is converted to kilovolt peak, what is the result?
A) 12 kVp
B) 120 kVp
, Page 3 of 76
C) 1,200 kVp
D) 12,000 kVp
Answer: B
Rationale: 1 kVp = 1,000 V; 120,000 V = 120 kVp . Kilovolt peak is a key exposure factor
in radiographic imaging.
7. What is 3.7 meters expressed in centimeters?
A) 37 cm
B) 370 cm
C) 3,700 cm
D) 37,000 cm
Answer: B
Rationale: 1 m = 100 cm; 3.7 m = 370 cm . Distance measurements are critical for
source-to-image distance (SID) and object-to-image distance (OID).
8. The density of mercury is 13.6 g/cm³. This refers to which physical property?
A) The mass per unit volume of mercury
B) The volume per unit mass of mercury
C) The temperature of mercury
D) The pressure of mercury
Answer: A
Rationale: Density is mass per unit volume . Mercury's density of 13.6 g/cm³ is
significant in radiography for understanding radiation attenuation properties of
materials.
9. What is the formula for converting Fahrenheit to Celsius?
A) °C = (°F - 32) × 5/9
B) °C = (°F + 32) × 9/5
C) °C = (°F × 9/5) + 32
D) °C = (°F × 5/9) - 32
Answer: A
, Page 4 of 76
Rationale: The correct formula for converting Fahrenheit to Celsius is °C = (°F - 32) ×
5/9 . Temperature conversions are important in film processing and equipment
maintenance.
10. What is the equation for a perfect square?
A) x² - 2xy + y² = (x - y)²
B) x² + 2xy + y² = (x + y)²
C) Both A and B
D) Neither A nor B
Answer: C
Rationale: The equations of perfect squares are: x² + 2xy + y² = (x + y)² and x² - 2xy + y² =
(x - y)² . Understanding perfect squares is important in inverse square law calculations.
11. If x = ay/bd, what happens to x when b is increased?
A) x increases
B) x decreases
C) x remains the same
D) x becomes negative
Answer: B
Rationale: Increasing b decreases the value of x in the proportional relationship x =
ay/bd . This mathematical concept relates to how changing exposure factors affects
image characteristics.
12. If x = ay/bd, what happens to x when d is decreased?
A) x increases
B) x decreases
C) x remains the same
D) x becomes negative
Answer: A
Rationale: Decreasing d increases the value of x . This concept applies to
understanding how changes in distance affect exposure and image quality.
13. What is the volume of a cone formula?
