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Abstract Algebra 1 & 2 Notes

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Notes taken in a two semester sequence of undergraduate Abstract Algebra (using Gallium text). Including definitions, theorems and proofs, as well as examples. Covered Material: - Division Algorithm - Groups and Abelian Groups - Cyclic Groups - Permutations and Permutation Groups - Subgroups and Normal Subgroups - Cosets and Quotient Groups - Rings and Integral Domains - Abstract Vector Spaces - Ideals and Quotient Rings - Polynomial Rings and Prime Polynomials - Fields and Extension Fields - Algebraic and Transcendental Numbers - Elementary Sylow and Galois Theory

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Abstract Algebra




muM
Well
orderi
Every
ng principle
set of natural
con-empty
*
numbers

# E0 1 2 3,
, , ,
...
n3 has a least element .




Proof .
(Induction on the size of the set

Base case Let S5N with 1Sl = / a =
bgor ,
and Orcb .

Then S :
En3 for some neW
Thus
,
n is the least element in Proof
.
Let S =
Ga-bk/ke #, n - bk 03
S .




Suppose 8 S Then . a -
bk = 0 = a= bk

Ind Case Let Ke I" suppose every non-empty we can choose ro and t
-
.

,



subset of N of size K has
,




a least element Suppose OxS. Note that a so
,
and

if aco ,
a - b(2a) =
a(l 2b) >, -




Now let ,
S'sN with 15 : 101 thus a-blaaJeS ,
and S is
non-empty.

SinceK20132 there is an Since SSN and S is
non-empty,
,
,


element acS' and S" := S'15a3, S has a least element ,
res
,
r = a-bg,

which subset of N. for I
ge .
is a non-empty some


size K . By the induction hypothesis,
S"has a least element b
.
,
Clearly ,
r =0 and a =
bgbr Suppose .
BWOC,

that r = b .




Thus ,
minda b3 ,
is the least Then b(q01)
a
bq
- =
a -
- b =
r -
b = 0

element of S TJ and a-blgp1) by < a - = r *
contradiction.
r = min(S) ,
so there cannot be an


element of S that is less them r.

So rub .


7 such that
Sps 79 ,, 92 ,
r ,
r
,


a =
ba tr , ,
a =
bactre ,
and Dr
,
r ,b
WLOG that Then,
, suppose r
,
3r
..


If alb
,
a is a divisor of b bq ,
br
,
=
baybre
=
b(q,92) =
my r
,



and b is a
multiple of a So ,
blire-r ) , .
However ,
Ostr ,
I re

=> r
=r,
= 0 = r = r * unique .
,




So ,
a -baz =
a -


by ,




92 =
9 ,
* unique

,Definition .
A
symmetry of a 2-D shope/ Definition Va b , ,
ceDn ,
(ab)c albe) =
,
Dn is



operation that associative.
region is an on



object s .
6 .
the imap befores
after the operation or identical.

A B
Symmetrics of square a Definition ↑
Let X G he sets. A
binay
>
-
Ro(rotation 5 coul CD
operation on
G is a function,
Ras (rotation 939
Ris (rotation 1800 · : > X
GxG -

Reo (rotation 270)
%




It (Glip about horizontal) Note Instead of (a b) ,
we write ab

verticle)
,

v
(flip about or .
ab

D
AD Iflip about disul AD)
BC
-




Disc (flip about
dapul If XSG
,
then we say G is closed
under


Every other symmetry is
equivalent to one of
Example Let In := E(0] [1, In-13. The , ...




these .
8 addition mode is a binay
operation on In .
Also closed ,




Definition The dihedral of order
group zn
.



(D.) the
LetGbe asetwihdin. )
of symmetries Definition
is
group
of a
regula n-gon . . ,




GroupIf
the
is a the
following
Definition ↑
The Cayley Table is complete axioms hold.

multiplication table of all elements Closin .
0 G is closed under
in the
group .
Associativity 1 . Va b cEG , , ,
(ab)c = a(bc)
Identity 2 JecG
=

.

,
ac-ea = a

·
Inverse .
3 JacG ca = a .
a = 2
o ,


Abelian Group
08
·
O
Commutativity 4 .
a -
b = b .
a

0
0
O sometime the
binary operation is rotated as

*
column o row not commutative.
,

o inverses are commutative .




Since Dn is not commutative ,
Dn is


non-Abelian

, In
Thorm .
a
group
G
,
the identity is Order and
Subgroups
Definition The number of elements
unique. . in a


G is the order of G demoed
group
, , ,



pf .
Suppose e
,
e, G ze dentity
elements. Then
,
e
,
= 2
,
e
,
=
e
Example (( 011 .
,
= -



Theorem Let G be Then for all I(V , )) =



group
.
a .




a b ceG,
Un=Eme(god(m n)
, ,


ab =
ac = b = e (left cancellation) Recall . ,
= 13 is a


ba =a => b=c (right cancellation group
w/ multiplication .




ab-ac Let a G.
pf Suppose .
.




Thus ,
Up =
21 ,
2 4
, ,
5
,
7
,
83 /Val ,
= 9

b = eb
-(a a) Example 131 . ,
-1
,
:
, :3) = 4
= (ab)
a (ac)
=
Definition .
The order of an element
geG is
(a ale
"
the smallest positive
=

such
inter n


eC that 1 e
g
=


ng-o-e
= or



b =
c
,
Likemse with ba- ca T

In Vo 111 = 1
,
131 = 4 171 =
4
,
191 = 2
, ,


Theorem If G a ,beG then
group and
.
is a
,



(ab)" :3
,


= b a In E1 ,
-1
,
i
,-
111 - 1 ,
1-11 52
,
,


Let consider abeG Since (i) 4 1 - i) 4
pf a beG and = =
.
.
, , ,



G is closed under immuses and multipleation .


b a EG Definition. if G is a and acG,
group
Earlne * 3
,


Then (b a )(ab) =
b (a a)b b b =
then (a ) .
=




Enalne 13
,



b "(b) =
b (eb) = =
e (a) =




Similarly (ab)(b a-1) e =
T

Definition If a subset HSG is a
group
.




Theorem For .
each aEG ,
thre is a
unique elevant under the same operation as


beG that ab-ba (Inverses G It
,
such = e .
or
,
we say is a
subgroup
nuique) .
Denoted HSG .




pf .

Suppose b ,beeG ,
and ab =b , ,
a = e


Then ab abz = b Definition A proper of G
and abe = b,a = e .
= ,
= be , .



subgroup a
group
is



by left cancellation H
.
A a
subgroupIs G such thut * G

denoted H<G.



subgroup Ge3
For G the is
group ,


the trivial If HSG
subgroup of G .




and H*Ge3 ,
It is called non-trivial .

, Example
. 50 23 ,
<
Ey :
Proper subgroup Theorem 2-Step
.


subgroup test
:


>
-
Closed Let G be a and ** HSG.
group
Associative If It is closed under the operation of G,

Identity and has inverses ,
then HSG

Inverses p If It is closed under "multiplication" and

taking inveses then a, bel = abelt.
,



Thus by
, 1-step test ,
HSG. TJ




Suppose groupand
a
Theorem .




ExampleLearn
. Seder x

p . Notice associativity of in It is


inherited from (G.. ) .
Since H **,
let xeH .

Choosing a = b = X
, gives
as


XX" ab" H Next
e = =
.

,
choosing
Theorem. Finite test :
a = e and b = x
gives as

LetI be
Subgroup
X = e . X = abel for all XeHt . a nommpty ,
finite subset
of G T It is closed
group
.




Next let
,
x
, yelt. We know y "is under the operation of G.
I
in It ,
and a = x
,
b =
y gives
Xy = x(y)) = ab H pf .
Let x+ H. Firstf x+e ,
then clearly
X etH= .




Example Let G be an abelian and let Suppose X* C and consider the
-




group
H =
ExcG)x e3 =
.
Show HSG. elements X
,
X2 , X3 ,
...
eG .
Since It is

Associativity Inherited from
*
: G closed under multiplication ,
X H.

Identity e :
= e
,
H Since It is finike, Si , je &" , wher isj
Inverses (x-1)" (x2)" e





: = = = e and Xi = X! .




Closure :
a belt b = e b b
. =
, , ,


lab)" = ab' *
Associativity is Commutativity Thus ,
xi =
Xi = xi i =
e .




= l l .
= C Since xxe
,
i -

j > /
i
xi i =
xi
-




=>
-




x . = = e


Note e'=e ,
and celt. So H .
* D
,


Suppose a be H .
Thus ate = b? This So ,
x = xi -T !. Thus XeH.
,



means a = a is
&
b" = b .
Since Gis Abelian

and associative :




(ab") (ab)" (ab)(ab) : = = (a a)(b b)
- - =
ab
=
e .
e =
c
. Thus HSG ·
$

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Publisher: 2009 ISBN: 9780547165097 Edition: Unknown

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August 19, 2026
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2024/2025
Type
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Joshua carlson (i) & andrew becklin (ii)
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