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ARRT PRACTICE EXAM QUESTIONS AND ANSWERS LATEST UPDATED 2026/2027 A COMPLETE SOLUTION ALL ANSWERS GET IT 100% CORRECT VERIFIED BEST GRADED A+ FOR SUCCESS

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ARRT PRACTICE EXAM QUESTIONS AND ANSWERS LATEST UPDATED 2026/2027 A COMPLETE SOLUTION ALL ANSWERS GET IT 100% CORRECT VERIFIED BEST GRADED A+ FOR SUCCESS

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ARRT PRACTICE EXAM QUESTIONS AND ANSWERS
LATEST UPDATED 2026/2027 A COMPLETE
SOLUTION ALL ANSWERS GET IT 100% CORRECT
VERIFIED BEST GRADED A+ FOR SUCCESS

Radiation intensity is usually measured as Exposure or:
a. effective dose
b. air kerma
c. absorbed dose
d. equivalent dose
b. air kerma
Effective dose (EfD) is defined by which of the following?
a. A measure of the biological effects of radiation based on type of dose
and tissue exposed.
b. A measure of the biological effects of radiation based on the absorbed
dose and the type of radiation involved.
c. A measure of the absorbed dose of radiation.
a. A measure of the biological effects of radiation based on type of dose
and tissue exposed.

(EfD is a way to measure the biological effects of radiation by multiplying
the absorbed dose by the Radiation Weighting Factor and the Tissue
Weighting Factor. This means that this calculation is not only based on the
type of absorbed dose that the individual received, but also takes into
account the radiosensitivity of the tissue that was exposed. The Effective
Dose is used to measure the stochastic effects of radiation, such as
cancer.)
The electron binding energy for the K shell of Tungsten is known to be:
a. 12 keV
b. 22 keV

,c. 57.5 keV
d. 69.5 keV
d. 69.5 keV
(The binding energy is unique for every orbital level within an atom, and
is also unique for every element. The inner shell always has the highest
binding energy, and in tungsten, the K shell binding energy is 69.5 keV)
A radiation worker inhales a large volume of an alpha-emitting radon gas
(WR = 20), resulting in an absorbed dose of 1.02 Gy to the lungs.
Calculate the equivalent dose.
a. 20.4 Sv
b. 1.02 Gy
c. 2448 mSv
d. 1.02 mGy
a. 20.4 Sv

(Equivalent Dose is calculated as D x WR . For this question, EqD = 1.02
Gy x 20 = 20.4 Sv. Remember that when absorbed dose is converted to
equivalent dose, the units change from Gray to Sievert.)
Which of the following is NOT an appropriate way to use exposure and air
kerma?
a. To test tube output
b. To measure leakage radiation
c. To measure scatter radiation
d. To measure dose to the patient
d. To measure dose to the patient
(Exposure and air kerma can be used anytime radiation in air is being
measured. This includes testing the two output, leakage radiation, and
even scatter radiation. Exposure and air kerma cannot be used to
measure dose to the patient)
What is the main difference between absorbed dose and equivalent dose?
a. Equivalent Dose takes into account the tissue type
b. Equivalent Dose takes into account the exposure rate

,c. Equivalent Dose takes into account the person's age
d. Equivalent Dose takes into account the radiation type
d. Equivalent Dose takes into account the radiation type

(Unlike the simple absorbed dose measurement, equivalent dose includes
the radiation type in the calculation. This is valuable in understanding the
biological harm caused to the exposed person)
A bremsstrahlung interaction occurs between an incident electron and
a. Outer shell electron
b. Inner shell electron
c. Nucleus of the atom
d. Neutron of the atom
c. Nucleus of the atom

(A bremsstrahlung interaction is the interaction between an incident
electron and an atom of tungsten with in the anode)
Effective Dose is calculated as:
a. Coulombs/kilogram
b. Joules/kilogram
c. D x WR
d. D x WR x WT
d. D x WR x WT

(Effective dose is calculated as the absorbed dose multiplied by the
radiation weighting factor (WR) and the tissue weighting factor (WT). You
could also say that effective dose is equal to the equivalent dose
multiplied by the tissue weighting factor)
During general fluoroscopy, the entrance skin exposure rate must not
exceed:
a. 1 mGy/hour
b. 100 mGy/hour

, c. 1 mGy/minute
d. 100 mGy/minute
d. 100 mGy/minute
A patient received a thyroid ablation treatment using an intravenously
injected radionuclide. If the absorbed dose to the thyroid is 0.59 Gy,
calculate the effective dose. Assume the thyroid has a tissue-weighting
factor of 0.04 and the emitted radiation has a radiation-weighting factor
of 1.0.
a. 0.59 Sievert
b. 0.0236 Sievert
c. 14.76 Sievert
d. 0.59 Millisievert
b. 0.0236 Sievert

(Effective Dose is equal to D x WR x WT. For this question, 0.59 Gy x 1 x
0.04 = 0.0236 Sv. Remember that when absorbed dose is converted to
effective dose, the units must be changed from gray to Sievert)
The radiological unit called the Gray is equal to:
a. Coulombs/kilogram
b. Joules/kilogram
c. Exposure x Radiation Weighting Factor
d. Coulombs/hour
b. Joules/kilogram

(The gray is a special unit used to describe radiation energy absorbed in
matter. The Gray is the unit for absorbed dose. It is equal to the joules of
energy absorbed divided by the kilograms of exposed tissue)
The two interactions needed to create x-ray photons are:
1. Photoelectric
2. Characteristic
3. Bremsstrahlung
4. Compton

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